Problem 13
Question
Determine the following limits at infinity. $$\lim _{t \rightarrow \infty} e^{t}, \lim _{t \rightarrow-\infty} e^{t}, \text { and } \lim _{t \rightarrow \infty} e^{-t}$$
Step-by-Step Solution
Verified Answer
Answer: As t approaches infinity, the limits are:
- e^t: ∞
- e^(-t): 0
As t approaches negative infinity, the limit for e^t is 0.
1Step 1: Determine the limit as t -> infinity for e^t
To find the limit for the exponential function as t approaches infinity, we can observe the behavior of the function. As t becomes larger, the value of e^t will also increase without bound because e > 1 (approximately 2.718). Therefore, the limit as t approaches infinity for e^t is:
$$\lim_{t \rightarrow \infty} e^t = \infty$$
2Step 2: Determine the limit as t -> -infinity for e^t
Now let's find the limit for the exponential function as t approaches negative infinity. As t becomes more negative, the value of e^t gets closer to 0. This is because as the exponent becomes a very large negative value, e^t essentially becomes 1 divided by a very large positive value, which makes it approach 0. Therefore, the limit as t approaches negative infinity for e^t is:
$$\lim_{t \rightarrow-\infty} e^{t} = 0$$
3Step 3: Determine the limit as t -> infinity for e^(-t)
Finally, let's find the limit for the exponential function with a negative exponent as t approaches infinity. As t becomes larger, the value of e^(-t) gets closer to 0. This is because the exponent is negated and essentially becomes more negative, making e^(-t) approach 0 just like in the previous case. Therefore, the limit as t approaches infinity for e^(-t) is:
$$\lim_{t \rightarrow \infty} e^{-t} = 0$$
In conclusion, the limits for the given exponential functions are as follows:
$$\lim_{t \rightarrow \infty} e^t = \infty$$
$$\lim_{t \rightarrow-\infty} e^{t} = 0$$
$$\lim_{t \rightarrow \infty} e^{-t} = 0$$
Key Concepts
Exponential FunctionsAsymptotic BehaviorLimit Concept
Exponential Functions
Exponential functions are mathematical functions of the form \(f(t) = a^t\), where \(a\) is a constant and \(t\) is a variable. These functions have interesting properties because they grow very rapidly once the value of \(t\) increases. When \(a > 1\), the function experiences exponential growth, meaning the value of \(f(t)\) increases faster and faster as \(t\) becomes large.
- For \(e^t\), where \(e\) (approximately 2.718) is the base of the natural logarithm, it is a common example of an exponential function.
- Exponential functions are used to model many real-world situations, like population growth and compound interest.
- The rapid increase or decrease makes exponential functions crucial in both mathematical theory and applications.
Asymptotic Behavior
The term "asymptotic behavior" refers to the way a function behaves as the variable grows very large in magnitude. In other words, it describes how a function approaches a line, curve, or another function as the value of the variable heads towards infinity or negative infinity.
- For \(e^t\), as \(t\) heads to infinity, \(e^t\) becomes infinitely large, demonstrating rapid growth.
- When \(t\) tends towards negative infinity, \(e^t\) approaches zero, as it becomes an inverse of a large positive number.
- Similarly, \(e^{-t}\) approaches zero as \(t\) moves towards infinity, because negating the exponent flips the growth direction of the function.
Limit Concept
The limit concept in calculus is a fundamental idea that helps us understand and analyze the behavior of functions as the input approaches a particular value. It is often used to describe the value that a function "approaches" as the input changes.
- In our exercise, we deal with limits as \(t\) approaches both positive and negative infinity.
- The limit \(\lim_{t \rightarrow \infty} e^t = \infty\) means that the function grows without bound as \(t\) becomes very large.
- Conversely, the limit \(\lim_{t \rightarrow -\infty} e^t = 0\) indicates that the function approaches zero as \(t\) becomes very negative.
- Lastly, \(\lim_{t \rightarrow \infty} e^{-t} = 0\) suggests the function approaches zero for very large values of \(t\), due to flipping the rapid growth to rapid decay.
Other exercises in this chapter
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