Problem 13
Question
Complete each solution. Solve: \(\begin{aligned} \sqrt{3 x+3}-1 &=5 \\ \sqrt{3 x+3} &=\\\\(\sqrt{3 x+3}) &=(6) \\ &=36 \\ 3 x &=\\\ x &=\end{aligned}\)
Step-by-Step Solution
Verified Answer
The solution is \( x = 11 \).
1Step 1: Isolate the Square Root
Start with the equation \( \sqrt{3x + 3} - 1 = 5 \). Add 1 to both sides to isolate the square root, resulting in \( \sqrt{3x + 3} = 6 \).
2Step 2: Eliminate the Square Root
Square both sides of the equation to eliminate the square root. This gives you \( (\sqrt{3x + 3})^2 = 6^2 \), which simplifies to \( 3x + 3 = 36 \).
3Step 3: Solve for x
Subtract 3 from both sides to isolate \( 3x \), resulting in \( 3x = 33 \). Then, divide both sides by 3 to solve for \( x \), giving \( x = 11 \).
Key Concepts
Isolating Square RootsEliminating Square RootsAlgebra Problem Solving
Isolating Square Roots
When solving an equation involving a square root, the first step is to isolate the square root on one side of the equation.
This allows you to clearly identify the term under the square root, making it easier to manipulate the equation in future steps.
This allows you to clearly identify the term under the square root, making it easier to manipulate the equation in future steps.
- Start by moving other terms away from the square root by performing the inverse operation. In our exercise, the square root is involved in the equation \( \sqrt{3x + 3} - 1 = 5 \).
- To isolate the square root, add 1 to both sides: \( \sqrt{3x + 3} = 6 \).
Eliminating Square Roots
After isolating the square root, the next task is to eliminate it. This makes the equation solvable using standard algebraic operations.
The way to achieve this is by squaring both sides of the equation.
This step is crucial because it simplifies the equation so you can use basic algebra to solve for the unknown variable.
The way to achieve this is by squaring both sides of the equation.
- In our scenario, the isolated equation is \( \sqrt{3x + 3} = 6 \).
- Square both sides to remove the square root: \( (\sqrt{3x + 3})^2 = 6^2 \) yields \( 3x + 3 = 36 \).
This step is crucial because it simplifies the equation so you can use basic algebra to solve for the unknown variable.
Algebra Problem Solving
Once the square root is eliminated, you are left with a linear algebra problem that can be solved using simple operations.
The objective is to solve for the variable, in this case, \( x \).
Practicing these steps in different problems helps you become more proficient and confident in tackling algebraic equations.
The objective is to solve for the variable, in this case, \( x \).
- Start by isolating the term with the variable. With \( 3x + 3 = 36 \), subtract 3 from both sides to obtain \( 3x = 33 \).
- Next, divide each side by 3 to solve for \( x \): \( x = 11 \).
Practicing these steps in different problems helps you become more proficient and confident in tackling algebraic equations.
Other exercises in this chapter
Problem 13
Fill in the blanks. \(\sqrt{-4}\) is not a real number, because no real number _____________equals \(-4\).
View solution Problem 13
Simplify each expression. $$ \sqrt{50} $$
View solution Problem 14
Complete each rule for exponents. $$ \frac{1}{x^{-m / n}}= \square $$
View solution Problem 14
Complete each solution. $$ \begin{aligned} \frac{3}{2-i} &=\frac{3}{2-i} \cdot \\ &=\frac{6+}{4-} \\ &=\frac{6+3 i}{5} i \\ &=-+\frac{3}{5} \end{aligned} $$
View solution