Problem 13
Question
$$ \begin{aligned} &\lim _{x \rightarrow 1} \frac{x \sin (x-[x])}{x-1}, \text { where }[\cdot] \text { denotes the greatest }\\\ &\text { integer function, is equal to } \end{aligned} $$ (A) 1 (B) \(-1\) (C) \(\infty\) (D) Does not exist
Step-by-Step Solution
Verified Answer
(D) Does not exist (due to lack of differentiability at integers).
1Step 1: Understand the greatest integer function
The greatest integer function, denoted as \([x]\), gives the largest integer less than or equal to \(x\). For example, \([1.5] = 1\). In the expression \(x - [x]\), this represents the fractional part of \(x\). Because we approach \(x=1\) from both sides, \(x-[x]\) approaches 0.
2Step 2: Analyze the behavior near \(x = 1\)
Near \(x = 1\), the expression \(x - [x]\) is either very slightly less than 1 or equal to 0 if we reach exactly 1.Thus, for numbers very close to 1 but less than 1, \(x - [x] = x - 1\). This makes \(\sin(x-[x])\) approximately equal to \(\sin(0) = 0\).
3Step 3: Apply the limit using L'Hôpital's Rule
Since we have the form 0/0 when substituting \(x = 1\), we can apply L'Hôpital's Rule. Differentiate the numerator and the denominator:- The derivative of the numerator \(x\sin(x-[x])\) with respect to \(x\) is \(\sin(x-[x]) + x \cos(x-[x]) (1-[\cdot]')\).- The derivative of the denominator \(x-1\) is 1.Evaluate the limit:
4Step 4: Evaluate derivatives
However, since the greatest integer function is not differentiable at integer points, directly applying L'Hôpital's Rule without simplification is complex. Instead, conceptualize that the behavior of \(x\sin(x-[x])\) near 1 is essentially 0 times anything approaching zero, leading to 0.
5Step 5: Conclusion based on behavior analysis
As \(\lim_{x \to 1} \frac{x\sin(x-[x])}{x-1}\) simplifies directly into evaluating a factor tending towards 0 because the numerator tends to 0. Hence, the expression behaves consistently as being 0 divided by something non-zero. Thus, the limit simplifies to 0.
Key Concepts
Greatest Integer FunctionL'Hôpital's RuleFractional Part of a Number
Greatest Integer Function
The greatest integer function, often denoted as \([x]\), provides one of the foundational concepts in mathematics, particularly in calculus. It essentially involves a simple operation: rounding down any real number to the nearest integer less than or equal to that number.
For instance:
For instance:
- For 2.9, the greatest integer less than or equal to 2.9 is 2, so \([2.9] = 2\).
- For a negative number like -1.3, the function results in \([-1.3] = -2\), because -2 is the largest integer not greater than -1.3.
L'Hôpital's Rule
L'Hôpital's Rule is a very handy tool in calculus, particularly when you encounter indeterminate forms such as \(\frac{0}{0}\). It provides a way to evaluate limits of quotients by differentiating the numerator and denominator separately.
Here's how it works:
L'Hôpital's Rule can simplify complex limit problems significantly, making it an essential tool for students.
Here's how it works:
- To apply L'Hôpital's Rule, first confirm that the function you are evaluating results in an indeterminate form such as \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\) when evaluated at a certain point.
- Next, take the derivative of the numerator and the derivative of the denominator.
- Then, compute the limit of these derivatives.
L'Hôpital's Rule can simplify complex limit problems significantly, making it an essential tool for students.
Fractional Part of a Number
The fractional part of a number is the component that remains after the integer part has been subtracted. For a real number \(x\), the fractional part is \(x - [x]\), where \([x]\) represents the greatest integer less than or equal to \(x\).
Consider some examples:
Consider some examples:
- For a number like 3.75, the greatest integer is 3. Therefore, the fractional part is \(3.75 - 3 = 0.75\).
- For 1.2, the fractional part is \(1.2 - 1 = 0.2\).
Other exercises in this chapter
Problem 11
The value of \(\lim _{h \rightarrow 0} \frac{\ln (1+2 h)-2 \ln (1+h)}{h^{2}}\) is (A) 1 (B) \(-1\) (C) 0 (D) None of these
View solution Problem 12
The value of \(\lim _{n \rightarrow \infty}\left(\frac{1}{n}+\frac{e^{1 / n}}{n}+\frac{e^{2 / n}}{n}+\ldots+\frac{e^{(n-1) / n}}{n}\right)\) is (A) 1 (B) 0 (C)
View solution Problem 14
If \(f(x)=\int \frac{2 \sin x-\sin 2 x}{x^{3}} d x, x \neq 0\), then \(\lim _{x \rightarrow 0} f(x)\) is (A) 0 (B) \(\infty\) (C) \(-1\) (D) 1
View solution Problem 15
\(\lim _{x \rightarrow \pi / 2} \frac{\left[\frac{x}{2}\right]}{\ln (\sin x)}\) (where [.] denotes the greatest integer function) (A) Does not exist (B) equals
View solution