Problem 13
Question
An equation for loudness \(L\) in decibels, is \(L=10 \log _{10} R\) where \(R\) is the relative intensity of the sound. Solve \(130=10 \log _{10} R\) to find the relative intensity of a fireworks display with a loudness of 130 decibels.
Step-by-Step Solution
Verified Answer
The relative intensity of the fireworks display is 10,000,000,000,000.
1Step 1: Understand the Equation
We are given the equation for loudness: \( L = 10 \log_{10} R \), where \( L \) is the loudness in decibels and \( R \) is the relative intensity of the sound. We need to find \( R \) when \( L = 130 \).
2Step 2: Substitute the Given Loudness
Substitute 130 for \( L \) in the equation: \( 130 = 10 \log_{10} R \). Our goal is to solve for \( R \).
3Step 3: Isolate the Logarithm
Divide both sides of the equation by 10 to isolate the logarithm: \( 13 = \log_{10} R \).
4Step 4: Solve for R Using Exponential Form
Convert the log equation into its exponential form: \( R = 10^{13} \). This conversion uses the property \( \log_{10} a = b \) implies \( a = 10^b \).
5Step 5: Calculate the Relative Intensity
Raise 10 to the power of 13 to find \( R \). This results in \( R = 10^{13} \) which equals 10,000,000,000,000.
Key Concepts
Loudness in DecibelsRelative IntensityExponential FormSolving Equations
Loudness in Decibels
Decibels serve as a unit measuring the loudness of sound. Understanding how loudness is quantified can be quite fascinating. The equation for loudness, given by \( L = 10 \log_{10} R \), helps us understand how different sounds can be compared.
- In this equation, \( L \) represents the loudness in decibels.
- \( R \) is the relative intensity of the sound.
Relative Intensity
Relative intensity \( R \) refers to the power of sound compared to a standard reference point. This concept is crucial in understanding how loud a sound can be.Factors that affect relative intensity include:
- Distance from the sound source: The closer you are, the greater the intensity.
- The power of the sound source: A powerful explosion or fireworks will have a higher intensity.
Exponential Form
The exponential form is a way of expressing equations using exponents. It's particularly useful when dealing with logarithmic equations, like those involving sound intensity level. After isolating the logarithm in our equation \(13 = \log_{10} R\), we converted it to exponential form: \(R = 10^{13}\). Here's a quick guide on how this works:
- The base of the log (\(10\) in this case) becomes the base of the exponential form.
- The result of the logarithm is the exponent (\(13\) here).
- "\( R \) equals the base raised to the power of the exponent" defines your exponential expression.
Solving Equations
Solving equations, especially involving logs, involves a systematic approach.To solve \(130=10\log_{10}R\), we undertake a series of logical steps:
- Start by substituting known values (here, replacing \(L\) with \(130\)).
- Then, carefully isolate the variable or expression with logs, often involving simple algebra like division.
- Once the logarithm is alone, change it to an exponential form to solve for \(R\).
- Finally, calculate to find the numerical solution, knowing each step narrows to your answer.
Other exercises in this chapter
Problem 13
Use \(\log _{5} 2 \approx 0.4307\) and \(\log _{5} 3 \approx 0.6826\) to approximate the value of each expression. \(\log _{5} 30\)
View solution Problem 13
Express each logarithm in terms of common logarithms. Then approximate its value to four decimal places. $$ \log _{2} 9 $$
View solution Problem 13
Solve each equation. Check your solution. $$ 9^{2 y-1}=27^{y} $$
View solution Problem 14
Solve each equation or inequality. Round to the nearest ten-thousandth. \(\ln x
View solution