Problem 13
Question
\(\alpha\) -particle is considered identical to He-nucleus because (a) He-nucleus is present in the nuclei of all \(\alpha\) -emitters. (b) He-nucleus has two protons and two neutrons. (c) any sealed vessel containing some \(\alpha\) -emitter is found to contain He gas after some time. (d) He-nucleus is the most stable nucleus.
Step-by-Step Solution
Verified Answer
An \(\alpha\)-particle is considered identical to a He-nucleus because it has the same composition, with both consisting of two protons and two neutrons (Option b).
1Step 1: Understanding Alpha Particles
An \(\alpha\)-particle is defined as a type of nuclear particle that is emitted during \(\alpha\)-decay. By definition, an \(\alpha\)-particle is composed of two protons and two neutrons, which is the same as a helium-4 (\(^{4}_{2}\text{He})\) nucleus.
2Step 2: Analyzing the given options
Option (a) is not a defining characteristic, as \(\alpha\)-emitters evolve to other elements after emission. Option (c) demonstrates a result rather than an identity match. Option (d) speaks to helium's stability but does not define the particle. Option (b) directly identifies the composition of an \(\alpha\)-particle as identical to that of a helium nucleus. Thus, it is the defining reason why an \(\alpha\)-particle is considered identical to a He-nucleus.
Key Concepts
Alpha DecayHelium NucleusNuclear ChemistryPhysical Chemistry
Alpha Decay
Alpha decay represents a fascinating aspect of nuclear chemistry, where unstable atoms work towards achieving stability by emitting a specific type of particle known as an alpha particle. This process typically involves heavy nuclei (such as uranium or radium) where the nucleus ejects an assembly of two protons and two neutrons—a configuration identical to a helium-4 nucleus.
By losing these particles, the original atom decreases in atomic mass by four units and in atomic number by two, essentially transforming into a completely different element. Alpha decay is instrumental in the natural transmutation of elements and is also a source of energy release within the decay process, playing a crucial role in applications such as radiometric dating and medical treatments.
By losing these particles, the original atom decreases in atomic mass by four units and in atomic number by two, essentially transforming into a completely different element. Alpha decay is instrumental in the natural transmutation of elements and is also a source of energy release within the decay process, playing a crucial role in applications such as radiometric dating and medical treatments.
Helium Nucleus
Delving into the helium nucleus, specifically helium-4 (( ^{4}_{2}He )), we uncover that this ensemble of two protons and two neutrons is not only the end product of alpha decay but also an exceptionally stable arrangement of nuclear material. This stability stems from the helium nucleus's tightly-bound structure and perfect balance of nuclear forces.The unique attributes of the helium nucleus make it an ideal benchmark in the study of nuclear stability and reactions. It's also interesting to note that the presence of helium, a noble gas, can be used as an indicator of alpha decay activity in sealed environments, as it accumulates over time as a byproduct of the decay process.
Nuclear Chemistry
Nuclear chemistry is a potent and dynamic field focusing on the reactions, structures, and properties of atomic nuclei. Pivotal for our understanding of the microscopic world, this branch of science looks at phenomena such as radioactive decay, nuclear fission and fusion, and isotopic labeling.
The principles of nuclear chemistry are core to various applications, from generating electricity in nuclear power plants to diagnosing and treating diseases with radiopharmaceuticals. As a content creator with a passion for demystifying complex concepts, it's my task to ensure the pivotal reactions—like alpha decay—are presented in a comprehensible manner, illustrating the transformation of elements at the subatomic level.
The principles of nuclear chemistry are core to various applications, from generating electricity in nuclear power plants to diagnosing and treating diseases with radiopharmaceuticals. As a content creator with a passion for demystifying complex concepts, it's my task to ensure the pivotal reactions—like alpha decay—are presented in a comprehensible manner, illustrating the transformation of elements at the subatomic level.
Physical Chemistry
Physical chemistry, at its essence, merges physics and chemistry to dissect how matter behaves on a molecular and atomic level, and how chemical reactions occur. Within this discipline, the focus on the alpha particle or decay finds its place in discussing energy transitions and the quantifiable aspects of chemical systems.
For students tackling this subject, appreciating how physical chemistry interplays with atomic structures and nuclear reactions is paramount. It enables a holistic understanding of the principles governing the material universe—from the way reactions release or absorb energy to the intricate dance of particles and forces within an atom.
For students tackling this subject, appreciating how physical chemistry interplays with atomic structures and nuclear reactions is paramount. It enables a holistic understanding of the principles governing the material universe—from the way reactions release or absorb energy to the intricate dance of particles and forces within an atom.
Other exercises in this chapter
Problem 11
Among the isotopes of all the elements (only non-radioactive), the \(n / p\) ratio is maximum for (a) \(\mathrm{H}^{1}\) (b) \({ }_{1} \mathrm{H}^{3}\) (c) \({
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Among the isotopes of all the elements (radioactive as well as non- radioactive), the packing fraction is maximum for (a) \({ }_{1} \mathrm{H}^{1}\) (b) \({ }_{
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Emission of one \(\alpha\) -particle from a nucleus results the loss of two protons and two neutrons from the nucleus. These four particles (two protons and two
View solution Problem 15
In \(\beta\) -decay, an electron comes out from an atom. The electron comes out due to nuclear change, not from the orbit of the atom. It may be explained by th
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