Problem 128
Question
Use fundamental identities to find each expression. Write \(\tan \theta\) in terms of \(\cos \theta\) if \(\theta\) is in quadrant IV.
Step-by-Step Solution
Verified Answer
\( \tan \theta = \frac{-\sqrt{1 - \cos^2 \theta}}{\cos \theta} \) in Quadrant IV.
1Step 1: Identify Trigonometric Identities
We know from the basic trigonometric identities that \( \tan \theta = \frac{\sin \theta}{\cos \theta} \). In order to express \( \tan \theta \) in terms of \( \cos \theta \), we need to find \( \sin \theta \).
2Step 2: Use Pythagorean Identity
Recall the Pythagorean identity: \( \sin^2 \theta + \cos^2 \theta = 1 \). Since we need to express everything in terms of \( \cos \theta \), we rearrange it to find \( \sin \theta \): \( \sin \theta = \pm \sqrt{1 - \cos^2 \theta} \).
3Step 3: Determine the Sign of \( \sin \theta \)
Since \( \theta \) is in Quadrant IV, we know that \( \sin \theta \) is negative. Therefore, \( \sin \theta = -\sqrt{1 - \cos^2 \theta} \) in this quadrant.
4Step 4: Substitute \( \sin \theta \) into the Tangent Formula
Substitute \( \sin \theta = -\sqrt{1 - \cos^2 \theta} \) into the tangent identity: \( \tan \theta = \frac{-\sqrt{1 - \cos^2 \theta}}{\cos \theta} \).
Key Concepts
Tangent FunctionPythagorean IdentityQuadrant IV
Tangent Function
The tangent function, denoted as \( \tan \theta \), is a fundamental trigonometric function. It relates the angles and sides of a right triangle, but it's also defined using the sine and cosine functions. In the context of trigonometric identities, the relationship between these functions is given by:
Ultimately, the tangent function helps bridge various trigonometric scenarios, whether it is solving equations or analyzing periodic behaviors.
- \( \tan \theta = \frac{\sin \theta}{\cos \theta} \)
Ultimately, the tangent function helps bridge various trigonometric scenarios, whether it is solving equations or analyzing periodic behaviors.
Pythagorean Identity
The Pythagorean Identity is a crucial element in understanding trigonometric functions, often serving as a stepping stone in derivations and proofs. The Pythagorean Identity is:
- \( \sin^2 \theta + \cos^2 \theta = 1 \)
- If you have a known \( \cos \theta \), you can rearrange the identity to find \( \sin \theta \) as \( \sin \theta = \pm \sqrt{1 - \cos^2 \theta} \).
Quadrant IV
Understanding the quadrant in which an angle resides is crucial for determining the signs of trigonometric functions. In Quadrant IV, specific behaviors of functions must be considered:
- \( \sin \theta \) is negative because the sine function represents the y-coordinate, which is below the x-axis in this quadrant.
- \( \cos \theta \) is positive since it represents the x-coordinate, aligning with the positive x-axis.
- \( \tan \theta \), being the ratio \( \frac{\sin \theta}{\cos \theta} \), is negative because a negative value (\( \sin \theta \)) over a positive value (\( \cos \theta \)) results in a negative outcome.
Other exercises in this chapter
Problem 126
In a square window of your calculator that gives a good picture of the first quadrant, graph the line \(y=\sqrt{3} x\) with \(x \geq 0 .\) Then, trace to any po
View solution Problem 127
Use fundamental identities to find each expression. Write \(\sin \theta\) in terms of \(\cot \theta\) if \(\theta\) is in quadrant III.
View solution Problem 129
Use fundamental identities to find each expression. Write \(\tan \theta\) in terms of \(\sin \theta\) if \(\theta\) is in quadrant I or IV.
View solution Problem 129
The unusual corral in the figure is separated into 26 areas, many of which approximate sectors of a circle. Assume that the corral has a diameter of 50 meters.
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