Problem 128
Question
Think About It A function \(f\) is increasing over its entire domain. Does \(f\) have an inverse function? Explain.
Step-by-Step Solution
Verified Answer
Yes, the function \(f\) does have an inverse because it is increasing over its entire domain, which means it is a one-to-one (bijective) function.
1Step 1: Defining the properties of a bijective function
A function \(f\) is said to be bijective (or one-to-one and onto), if each element of the codomain is mapped with exactly one element of the domain. In simple terms, there are no repeats in output, and every possible output is covered.
2Step 2: Analyzing the given function
The problem mentions that the function \(f\) is increasing over its entire domain. This implies that as you move from left to right along the curve of the function, the function values are always increasing, i.e., for any two numbers \(x1\) and \(x2\) in the domain, if \(x1 < x2\), then \(f(x1) < f(x2)\).
3Step 3: Deciding if function \(f\) has an inverse
Since the function \(f\) is always increasing, it means that the function will not repeat any value in the range. This means the function is one-to-one (bijective). As per the property of a bijective function, it can be inferred that the function has an inverse.
Key Concepts
Bijective FunctionIncreasing FunctionOne-to-One Function
Bijective Function
When we talk about bijective functions, we're addressing a key concept in mathematics. Think of a bijective function as a perfect matchmaker. It assigns each input a unique output and ensures all possible outputs are already paired. If you imagine the domain and codomain as two sets of people, a bijective function ensures everyone has one perfect dance partner.
- A function is one-to-one if different inputs produce different outputs.
- A function is onto if every possible output has been hit by some input.
- Bijective means both one-to-one and onto. Every element has a unique pair.
Increasing Function
An increasing function is like climbing a hill. As you move forward, you either go up or stay on the same level, never decreasing. This means as your input \(x\) increases, the output \(f(x)\) doesn't fall.
Thus, increasing, especially strictly, makes it easier to ensure a function is one-to-one, paving the way for being bijective!
- Formally, for any pair of values \(x_1 and x_2\), if \(x_1 < x_2\), then \(f(x_1) \leq f(x_2)\).
- Functions that always climb upwards, meaning \(f(x_1) < f(x_2)\), are strictly increasing.
Thus, increasing, especially strictly, makes it easier to ensure a function is one-to-one, paving the way for being bijective!
One-to-One Function
One-to-one functions ensure that each input maps to a distinctive output. It's like assigning a unique nickname to each friend in your circle. No two friends get the same nickname.
The beauty of a one-to-one function is its part of the story in making a function bijective. Combine this with being onto, and boom! You've got a function primed and ready for an inverse.
- For every pair of distinct inputs \(x_1, x_2\), \(f(x_1) eq f(x_2)\).
The beauty of a one-to-one function is its part of the story in making a function bijective. Combine this with being onto, and boom! You've got a function primed and ready for an inverse.
Other exercises in this chapter
Problem 126
Factor the trinomial. $$3 x^{2}-16 x+5$$
View solution Problem 127
Think About It The function \(f(x)=\frac{9}{5} x+32\) can be used to convert a temperature of \(x\) degrees Celsius to its corresponding temperature in degrees
View solution Problem 129
Think About It Describe a type of function that is not one-to-one on any interval of its domain.
View solution Problem 131
Proof Prove that if \(f\) and \(g\) are one-to-one functions, then \((f \circ g)^{-1}(x)=\left(g^{-1} \circ f^{-1}\right)(x)\).
View solution