Problem 127
Question
Determine whether each statement is true or false. If the statement is false, make the necessary change \((s)\) to produce a true statement. If \(a\) and \(b\) are any real numbers, then \(a x+b=0\) always has one number in its solution set.
Step-by-Step Solution
Verified Answer
The given statement is false. The true statement would be 'If \(a\) and \(b\) are any real numbers, and \(a\) is not equal to zero, then \(a x+b=0\) always has one number in its solution set.'
1Step 1: Identify the Linear Equation
From the statement, we have a linear equation in one variable, \(a x+b=0\), where \(a\) and \(b\) are any real numbers.
2Step 2: Check for the Existence of a Solution
For a linear equation in one variable, a common solution exists when the coefficient of the variable is not zero. In this case, if \(a\) (the coefficient of \(x\)) is not zero, the equation will have one unique real number as a solution.
3Step 3: Validate Given Statement
Assuming \(a\) and \(b\) to be any real numbers, if \(a=0\) and \(b\neq0\), the equation becomes \(0x+b=0\) or \(b=0\). This indicates no solution because all real values of \(x\) do not satisfy the equation, contradicting the given statement.
4Step 4: Correct the Statement
The false statement 'If \(a\) and \(b\) are any real numbers, then \(a x+b=0\) always has one number in its solution set.' can be made true by stating 'If \(a\) and \(b\) are any real numbers, and \(a\) is not equal to zero, then \(a x+b=0\) always has one number in its solution set.'
Key Concepts
Understanding Real NumbersExploring the Solution SetUnique Solutions in Linear Equations
Understanding Real Numbers
Real numbers are fundamental in mathematics. They include both rational and irrational numbers. Rational numbers are those that can be expressed as a fraction, while irrational numbers cannot be expressed as fractions and have non-repeating, non-terminating decimals.
Together, real numbers cover all numbers that can be found on the number line, from negative infinity to positive infinity.
Understanding real numbers helps in manipulating equations correctly and predicting solutions accurately.
Together, real numbers cover all numbers that can be found on the number line, from negative infinity to positive infinity.
- Rational numbers include integers, fractions, and repeating or terminating decimals.
- Irrational numbers include numbers like \(\pi\) and \(\sqrt{2}\), which cannot be precisely written as fractions.
Understanding real numbers helps in manipulating equations correctly and predicting solutions accurately.
Exploring the Solution Set
The solution set of a linear equation refers to the set of all possible values of the variable that satisfy the equation. For a simple linear equation like \(a x + b = 0\), this typically means finding the value of \(x\) that makes the equation true.
On the other hand, when \(aeq0\), the solution set contains exactly one unique value for \(x\).
- If the equation is \(2x + 3 = 0\), the solution \(x = -\frac{3}{2}\) is part of the solution set as it satisfies the equation.
- If an equation cannot be satisfied by any real number, it is said to have no solution, meaning its solution set is empty.
On the other hand, when \(aeq0\), the solution set contains exactly one unique value for \(x\).
Unique Solutions in Linear Equations
In linear equations, a unique solution means there is exactly one value of the variable that satisfies the equation. For \(a x + b = 0\), if \(aeq0\), there will be one and only one value of \(x\) that can solve the equation. This makes the solution unique.
However, if \(a = 0\), the situation changes drastically, and the equation might not even have a solution. This highlights why having \(aeq0\) is essential for ensuring a unique solution exists.
- The formula to find this unique solution is \(x = -\frac{b}{a}\), assuming \(aeq0\).
- This unique value exists because dividing \(-b\) by \(a\) gives a single value on the number line.
However, if \(a = 0\), the situation changes drastically, and the equation might not even have a solution. This highlights why having \(aeq0\) is essential for ensuring a unique solution exists.
Other exercises in this chapter
Problem 127
Solve equation by the method of your choice. $$ \frac{1}{x^{2}-3 x+2}=\frac{1}{x+2}+\frac{5}{x^{2}-4} $$
View solution Problem 127
In Exercises 122–133, use the strategy for solving word problems, modeling the verbal conditions of the problem with a linear inequality. A company manufactures
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Solve equation by the method of your choice. $$ \frac{x-1}{x-2}+\frac{x}{x-3}=\frac{1}{x^{2}-5 x+6} $$
View solution Problem 128
In Exercises 122–133, use the strategy for solving word problems, modeling the verbal conditions of the problem with a linear inequality. An elevator at a const
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