Problem 127
Question
An aldose is oxidized separately by \(\mathrm{Br}_{2} / \mathrm{H}_{2} \mathrm{O}\) (condition-A) and by \(\mathrm{HNO}_{3}\) (condition-B). Which of the following is the correct combination of the products formed? (a) condition-A gives aldaric acid while condition-B yields a mixture of aldonic and aldaric acids (b) condition-A gives aldonic acid while condition-B yields a mixture of aldonic and aldaric acids (c) condition-A gives aldaric acid while condition-B yields aldonic acid (d) condition-A gives aldonic acid while condition-B yields aldaric acid
Step-by-Step Solution
Verified Answer
Option (d) is correct: condition-A gives aldonic acid and condition-B yields aldaric acid.
1Step 1: Understanding the Reaction with Bromine Water
When an aldose is oxidized using \( \mathrm{Br}_2 / \mathrm{H}_2 \mathrm{O} \) (condition-A), the aldehyde group of the aldose is selectively oxidized to form an aldonic acid. The reaction does not affect the primary alcohol group present in an aldose, so the terminal hydroxyl group remains unchanged.
2Step 2: Understanding the Reaction with Nitric Acid
When an aldose is oxidized using \( \mathrm{HNO}_3 \) (condition-B), both the aldehyde group and the primary alcohol group are oxidized. This reaction converts the aldose into an aldaric acid, where both ends of the molecule are oxidized to carboxylic acid groups.
3Step 3: Comparing Product Formation in Conditions
In condition-A using \( \mathrm{Br}_2 / \mathrm{H}_2 \mathrm{O} \), we get aldonic acid, while in condition-B using \( \mathrm{HNO}_3 \), an aldaric acid is formed. This matches option (d) where condition-A gives aldonic acid and condition-B yields aldaric acid.
Key Concepts
Aldonic acidAldaric acidBromine water oxidationNitric acid oxidation
Aldonic acid
Aldonic acids are formed when an aldose sugar undergoes a selective oxidation reaction. Specifically, the aldehyde group at the top of the aldose molecule is oxidized to form a carboxylic acid. Importantly, this reaction does not affect other parts of the molecule, such as the primary alcohol at the end of the sugar.
- The oxidation typically uses a mild oxidizing agent, like bromine water (\(\mathrm{Br}_2/\mathrm{H}_2\mathrm{O}\)).
- After the reaction, the sugar now has a carboxyl group (-COOH) instead of a terminal aldehyde (-CHO).
Aldaric acid
Aldaric acids are produced when both the aldehyde and the primary alcohol groups in an aldose are oxidized. This complete oxidation is typically achieved with a more potent oxidizing agent, such as nitric acid (\(\mathrm{HNO}_3\)). Both ends of the sugar molecule are converted into carboxylic acid groups.
- Each aldose gives rise to a specific aldaric acid, with unique properties.
- This modification can lead to changes in the sugar's physical and chemical behavior.
Bromine water oxidation
Bromine water oxidation specifically targets the aldehyde group on an aldose, converting it into an aldonic acid. This method is favored for its selectivity and mildness, which means it does not tamper with other functional groups within the sugar.
- In the reaction, the bromine acts as an oxidant, and the presence of water facilitates the conversion.
- The simplicity of this reaction makes it popular in laboratory settings for preparing aldonic acids easily.
Nitric acid oxidation
Nitric acid oxidation is a powerful process used to transform aldose sugars into aldaric acids by oxidizing both the aldehyde and primary alcohol groups. Due to its stronger oxidative power, nitric acid can efficiently modify both ends of the sugar molecule.
- This oxidation offers chemists a way to fully open and oxidize a sugar's structure, enabling the creation of symmetric molecules.
- While this reaction is more aggressive compared to others, it is controlled to selectively oxidize the desired groups without damaging the carbon chain.
Other exercises in this chapter
Problem 123
Which statements are correct about peptide bond? (1) - CONH-group is planar (2) \(\mathrm{C}-\mathrm{N}\) bond length in protein is longer than usual bond lengt
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Consider the following statements about carbohydrates: 1\. Bromine water can be used to differentiate an aldose from a ketose 2\. All monosaccharides, whether a
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If \(\mathrm{C}-5\) carbon of \(\mathrm{D}-\) glucose is inverted the new compound is related to the parent compound as (a) Enantiomer (b) Epimer (c) Anomer (d)
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