Problem 126
Question
The sum of the numbers in the \(n\) th row of Pascal's Triangle is \(2^{n}\).
Step-by-Step Solution
Verified Answer
The sum of the numbers in the \(n\) th row of Pascal's Triangle is \(2^{n}\), which is proven by formulating the sum of each row in terms of the binomial coefficients and showcasing the equivalence when \(a = 1\) and \(b = 1\) in the binomial expansion.
1Step 1: Understanding Pascal's Triangle
Pascal's triangle is a triangular array of the binomial coefficients. Each number in a row of the triangle is the sum of the two numbers directly above it. In this triangular arrangement, the \(n\) th row corresponds to the coefficients of \((a + b)^{n}\) in the binomial expansion. So, a row in Pascal's triangle is also the coefficients of the expansion of a binomial equation raised to the power \(n\).
2Step 2: Formulating terms in Pascal's Triangle
The \(n\) th row of Pascal's triangle will have \((n+1)\) terms and these coefficients correspond to the terms \({n \choose 0}, {n \choose 1}, ..., {n \choose n}\) in the binomial expansion of \((a + b)^{n}\). These are also known as binomial coefficients.
3Step 3: Proving the Sum of the \(n\) th row
The sum of the elements in the \(n\) th row can be written as \({n \choose 0} + {n \choose 1} + ... + {n \choose n}\). This same result can also be obtained by substituting \(a = 1\) and \(b = 1\) in the expansion of \((a + b)^{n}\), which yields \(2^{n}\). This is because substituting 1 for \(a\) and \(b\) in the expansion of \((a + b)^{n}\) and simplifying gives \(2^{n}\). This proves the sum of the numbers in the \(n\) th row of Pascal's Triangle is \(2^{n}\).
Key Concepts
Binomial CoefficientsBinomial TheoremCombinatorics
Binomial Coefficients
Binomial coefficients are the numbers that appear as the entries of Pascal's Triangle. They represent the different ways you can choose a number of items from a larger set. For example, in combinations, how many ways you can choose 2 objects from 5, is represented by a binomial coefficient.
- Binomial coefficients are denoted as \(\binom{n}{k}\), where \(n\) is the total number of items, and \(k\) is the number of items to choose.
- In Pascal's Triangle, each number is derived from the sum of the two numbers directly above it. This means that each row of the triangle builds on the one directly preceding it.
Binomial Theorem
The Binomial Theorem provides a way to expand expressions that are raised to a power. It states that \[(a+b)^n = \binom{n}{0}a^nb^0 + \binom{n}{1}a^{n-1}b^1 + ... + \binom{n}{n}a^0b^n\].
- The expansion reflects the distribution of the coefficients we find in Pascal's Triangle.
- The theorem is a powerful algebraic tool that lets us solve complex problems by breaking them into simpler ones.
Combinatorics
Combinatorics is an area of mathematics that focuses on counting, arrangement, and combination of objects. It's the broader science where binomial coefficients and the Binomial Theorem are applied.
- It involves counting techniques, such as permutations and combinations, to determine how objects can be arranged or grouped.
- The applications of combinatorics are vast and include areas like probability, geometry, and computer science.
Other exercises in this chapter
Problem 124
Prove the property for all integers \(r\) and \(n,\) where \(0 \leq r \leq n\) \(_{n} C_{0}-_{n} C_{1}+_{n} C_{2}-\cdots \pm_{n} C_{n}=0\)
View solution Problem 125
Determine whether the statement is true or false. Justify your answer. $$\sum_{i=1}^{4}\left(i^{2}+2 i\right)=\sum_{i=1}^{4} i^{2}+2 \sum_{i=1}^{4} i$$
View solution Problem 126
Determine whether the statement is true or false. Justify your answer. $$\sum_{j=1}^{4} 2^{j}=\sum_{j=3}^{6} 2^{j-2}$$
View solution Problem 127
Use the Fibonacci sequence. (See Example 5.) Write the first 12 terms of the Fibonacci sequence \(a_{n}\) and the first 10 terms of the sequence given by $$b_{n
View solution