Problem 126
Question
In the Argand diagram, if \(O, P\) and \(Q\) represent respectively the origin and the complex numbers \(z\) and \(z+i z\), then the \(\angle O P Q\) is (A) \(\frac{\pi}{4}\) (B) \(\frac{\pi}{3}\) (C) \(\frac{\pi}{2}\) (D) \(\frac{2 \pi}{3}\)
Step-by-Step Solution
Verified Answer
The angle \( \angle OPQ \) is \( \frac{\pi}{2} \).
1Step 1: Identify Given Complex Numbers
The problem states that in the Argand diagram, point \( O \) is the origin, \( P \) represents the complex number \( z \), and \( Q \) represents the complex number \( z + i z \). We can express \( z \) as \( x + i y \) where \( x, y \) are real numbers.
2Step 2: Determine Location of Q
Given \( z = x + iy \), the complex number \( z + iz \) becomes \( (x + iy) + i(x + iy) = x + iy + ix - y \), which simplifies to \( (x-y) + i(x+y) \). Thus, \( Q \) is located at \( (x-y, x+y) \).
3Step 3: Express Vectors OP and PQ
Vector \( \overrightarrow{OP} \) is \( x + iy \) and vector \( \overrightarrow{PQ} \) is obtained by subtracting \( P \) from \( Q \), which is \( ((x-y) + i(x+y)) - (x + iy) = -y + ix \).
4Step 4: Calculate Angle OPQ using Dot Product
The dot product of vectors \( \overrightarrow{OP} \) and \( \overrightarrow{PQ} \) is \(-yx + i(x^2 - y^2)\). Since these vectors are perpendicular when their dot product is zero, let's calculate the angle. The imaginary part, which does not affect the real angle calculation, is calculated by dividing the vectors into real and imaginary components: \( \overrightarrow{OP} = x \hat{i} + y \hat{j} \) and \( \overrightarrow{PQ} = -y \hat{i} + x \hat{j} \). The dot product is zero: \( x(-y) + y(x) = -xy + xy = 0 \). Thus, the angle between them is \( \frac{\pi}{2} \).
5Step 5: Determine the Answer
Since the calculated angle \( \angle O P Q \) is \( \frac{\pi}{2} \), the correct answer is option (C) \( \frac{\pi}{2} \).
Key Concepts
Argand DiagramVector RepresentationDot ProductAngle Calculation
Argand Diagram
The Argand Diagram is a powerful tool used to visualize complex numbers. Imagine it like a coordinate plane, where each complex number gets its own unique spot. This diagram helps us understand the location of complex numbers as points in the plane.
In the Argand diagram:
In the Argand diagram:
- The horizontal axis represents the real part of the complex number.
- The vertical axis represents the imaginary part.
Vector Representation
Vector Representation is like giving directions between points on a map. In mathematics, it helps us understand points as arrow-like structures with direction and magnitude.
In the given exercise, we have:
In the given exercise, we have:
- Vector \( \overrightarrow{OP} \), going from the origin \( O \) to point \( P \), represented as \( x + iy \).
- Vector \( \overrightarrow{PQ} \), which connects points \( P \) and \( Q \). It is represented as \( -y + ix \), obtained by the difference of points \( Q \) and \( P \).
Dot Product
The Dot Product is a mathematical operation that multiplies two vectors and gives a scalar result. It is a fundamental tool in vector calculus and helps to determine the angle between two vectors.
The dot product of two vectors \( \overrightarrow{a} \) and \( \overrightarrow{b} \) is calculated by:\[\overrightarrow{a} \cdot \overrightarrow{b} = a_1b_1 + a_2b_2\]Where \( a_1, a_2 \) and \( b_1, b_2 \) are components of the vectors. In the exercise, we have:
The dot product of two vectors \( \overrightarrow{a} \) and \( \overrightarrow{b} \) is calculated by:\[\overrightarrow{a} \cdot \overrightarrow{b} = a_1b_1 + a_2b_2\]Where \( a_1, a_2 \) and \( b_1, b_2 \) are components of the vectors. In the exercise, we have:
- \( \overrightarrow{OP} \) with components \( x \) and \( y \).
- \( \overrightarrow{PQ} \) with components \( -y \) and \( x \).
Angle Calculation
Calculating the angle between vectors is very useful in understanding their relationship. When performing angle calculation, particularly between vectors in the Argand diagram, we often rely on the dot product.
If the dot product of two vectors is zero, it means they are perpendicular to each other. This is because:\[\cos(\theta) = \frac{\overrightarrow{a} \cdot \overrightarrow{b}}{\|\overrightarrow{a}\| \|\overrightarrow{b}\|}\]where \( \theta \) is the angle between them.
In the exercise, because the dot product of \( \overrightarrow{OP} \) and \( \overrightarrow{PQ} \) equals zero, the angle \( \angle OPQ \) is \( \frac{\pi}{2} \) radians, or 90 degrees. This demonstrates a perfect right angle, proving the perpendicular nature of the vectors on the Argand diagram.
If the dot product of two vectors is zero, it means they are perpendicular to each other. This is because:\[\cos(\theta) = \frac{\overrightarrow{a} \cdot \overrightarrow{b}}{\|\overrightarrow{a}\| \|\overrightarrow{b}\|}\]where \( \theta \) is the angle between them.
In the exercise, because the dot product of \( \overrightarrow{OP} \) and \( \overrightarrow{PQ} \) equals zero, the angle \( \angle OPQ \) is \( \frac{\pi}{2} \) radians, or 90 degrees. This demonstrates a perfect right angle, proving the perpendicular nature of the vectors on the Argand diagram.
Other exercises in this chapter
Problem 123
If \(z_{1}\) and \(z_{2}\) are any two complex numbers, then \(\left|z_{1}+\sqrt{z_{1}^{2}-z_{2}^{2}}\right|+\left|z_{1}-\sqrt{z_{1}^{2}-z_{2}^{2}}\right|\) is
View solution Problem 124
If \(z=x+i y\) lies in IIIrd quadrant, then \(-\) also lies in the IIIrd quadrant if \(z\) (A) \(y>x>0\) (B) \(yy>0\)
View solution Problem 127
If \(z\) satisfies \(|z+1|7\) (D) \(|\omega+5|
View solution Problem 128
If \(z\) satisfies \(|z+1|7\) (D) \(|\omega+5|
View solution