Problem 126
Question
For the following exercises, find the requested value. If \(\sin (t)=\frac{3}{8}\) and \(t\) is in the \(2^{\text { nd }}\) quadrant, find \(\cos (t)\)
Step-by-Step Solution
Verified Answer
\( \cos(t) = -\frac{\sqrt{55}}{8} \) in the 2nd quadrant.
1Step 1: Use the Pythagorean Identity
The Pythagorean identity states that for any angle \( t \), \( \sin^2(t) + \cos^2(t) = 1 \). To find \( \cos(t) \), we can substitute the value \( \sin(t) = \frac{3}{8} \) into this identity.
2Step 2: Square the Sine Value
Calculate \( \sin^2(t) \) by squaring \( \frac{3}{8} \): \[ \sin^2(t) = \left(\frac{3}{8}\right)^2 = \frac{9}{64} \]
3Step 3: Substitute in Pythagorean Identity
Substitute \( \sin^2(t) = \frac{9}{64} \) into the identity: \[ \sin^2(t) + \cos^2(t) = 1 \]\[ \frac{9}{64} + \cos^2(t) = 1 \]
4Step 4: Solve for Cosine Squared
Rearrange to solve for \( \cos^2(t) \): \[ \cos^2(t) = 1 - \frac{9}{64} \]Convert 1 to \( \frac{64}{64} \) and subtract: \[ \cos^2(t) = \frac{64}{64} - \frac{9}{64} = \frac{55}{64} \]
5Step 5: Determine the Sign of Cosine
Since \( t \) is in the second quadrant, the cosine of \( t \) is negative. Therefore, compute \( \cos(t) \):\[ \cos(t) = -\sqrt{\frac{55}{64}} \]
6Step 6: Simplify the Cosine Value
Simplify \( \cos(t) \):\[ \cos(t) = -\frac{\sqrt{55}}{8} \]
Key Concepts
Pythagorean IdentityTrigonometric FunctionsSecond Quadrant
Pythagorean Identity
The Pythagorean Identity is a critical relationship in trigonometry. It expresses a fundamental connection between the sine and cosine of an angle. The identity is written as \( \sin^2(t) + \cos^2(t) = 1 \). This equation is akin to the Pythagorean Theorem and is valid for any angle \( t \). To understand this identity, remember it essentially says if you square the sine of an angle and add it to the square of the cosine of the same angle, the result is always one.
This identity is immensely useful because it allows one trigonometric function to be expressed in terms of another. For example, knowing \( \sin(t) \) can help you determine \( \cos(t) \), and vice versa, when using this identity. Applying it to the problem in our exercise, we started with \( \sin(t) = \frac{3}{8} \) and used the identity to find \( \cos(t) \). By squaring the sine value and substituting it in, we could solve for \( \cos^2(t) \) and subsequently \( \cos(t) \). This is a quintessential technique in solving trigonometric problems.
This identity is immensely useful because it allows one trigonometric function to be expressed in terms of another. For example, knowing \( \sin(t) \) can help you determine \( \cos(t) \), and vice versa, when using this identity. Applying it to the problem in our exercise, we started with \( \sin(t) = \frac{3}{8} \) and used the identity to find \( \cos(t) \). By squaring the sine value and substituting it in, we could solve for \( \cos^2(t) \) and subsequently \( \cos(t) \). This is a quintessential technique in solving trigonometric problems.
Trigonometric Functions
Trigonometric functions are a set of mathematical functions that relate the angles of a triangle to the lengths of its sides. The primary functions are sine, cosine, and tangent. They are crucial in describing oscillatory phenomena like waves.
- **Sine (\( \sin \)):** This function gives the ratio of the opposite side to the hypotenuse in a right triangle. In the coordinate plane, it represents the y-coordinate of a point on the unit circle.- **Cosine (\( \cos \)):** This function gives the ratio of the adjacent side to the hypotenuse. It corresponds to the x-coordinate on the unit circle.- **Tangent (\( \tan \)):** It is the ratio of sine to cosine. It represents the slope of a line from the origin to a point on the unit circle.
These functions are periodic, meaning they repeat their values over regular intervals. That's why they're frequently used in cycling or wave-like patterns. Given \( \sin(t) \) in the problem, we utilized this function to determine \( \cos(t) \), exploiting their interrelation via the Pythagorean Identity.
- **Sine (\( \sin \)):** This function gives the ratio of the opposite side to the hypotenuse in a right triangle. In the coordinate plane, it represents the y-coordinate of a point on the unit circle.- **Cosine (\( \cos \)):** This function gives the ratio of the adjacent side to the hypotenuse. It corresponds to the x-coordinate on the unit circle.- **Tangent (\( \tan \)):** It is the ratio of sine to cosine. It represents the slope of a line from the origin to a point on the unit circle.
These functions are periodic, meaning they repeat their values over regular intervals. That's why they're frequently used in cycling or wave-like patterns. Given \( \sin(t) \) in the problem, we utilized this function to determine \( \cos(t) \), exploiting their interrelation via the Pythagorean Identity.
Second Quadrant
In trigonometry, the unit circle is divided into four quadrants. Each quadrant affects the sign of the trigonometric functions. In the second quadrant (angles between 90° and 180°, or \( \pi/2 \) and \( \pi \)), the values have specific sign characteristics:
Such quadrant rules prevent mistakes and guide correct evaluations of trigonometric values for given angles.
- The sine function is positive.
- The cosine function is negative.
- The tangent function is negative.
Such quadrant rules prevent mistakes and guide correct evaluations of trigonometric values for given angles.
Other exercises in this chapter
Problem 124
For the following exercises, find the requested value. If \(\cos (t)=\frac{1}{7}\) and \(t\) is in the \(4^{\text { th }}\) quadrant, find \(\sin (t)\)
View solution Problem 125
For the following exercises, find the requested value. If \(\cos (t)=\frac{2}{9}\) and \(t\) is in the \(1^{\text { st }}\) quadrant, find \(\sin (t)\)
View solution Problem 127
For the following exercises, find the requested value. If \(\sin (t)=-\frac{1}{4}\) and \(t\) is in the \(3^{\text { rd }}\) quadrant, find \(\cos (t)\)
View solution Problem 128
For the following exercises, find the requested value. Find the coordinates of the point on a circle with radius 15 corresponding to an angle of \(220^{\circ} .
View solution