Problem 126
Question
An isomer of the compound \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHOHCH}_{3}\) is (a) \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O} ;\) (b) \(\mathrm{CH}_{3} \mathrm{CHOHCH}_{2} \mathrm{CH}_{3}\) (c) \(\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{2} \mathrm{OH} ;\) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3}\)
Step-by-Step Solution
Verified Answer
The isomer of the compound \(\mathrm{CH}_{3} \mathrm{CH}_{2}\mathrm{CHOHCH}_{3}\) is \(\mathrm{CH}_{3}\mathrm{CHOHCH}_{2} \mathrm{CH}_{3}\).
1Step 1: Identify the Original Compound
First, we identify the initial compound, which is \(\mathrm{CH}_{3} \mathrm{CH}_{2}\mathrm{CHOHCH}_{3}\). It contains four carbon atoms (C), nine Hydrogen atoms (H) and one Oxygen atom (O). Thus, its molecular formula is \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}\).
2Step 2: Compare with Options
Next, we compare this with the given choices. The molecular formulae for the options provided are - (a) \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\), (b) \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}\), (c) \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}\), and (d) \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}\). An isomer would share the same molecular formula, but the arrangement of the atoms would be different.
3Step 3: Identify the Isomer
Given that isomers share the same molecular formula, we can rule out option (a) because it does not match the formula \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}\). Comparing the structural diagrams of the original compound and the other options, we find that option (b) \(\mathrm{CH}_{3}\mathrm{CHOHCH}_{2} \mathrm{CH}_{3}\) differs in the placement of the OH group, thus it is the isomer of the original compound.
Key Concepts
Organic ChemistryMolecular FormulaStructural IsomersFunctional Groups
Organic Chemistry
Understanding organic chemistry is fundamental when studying molecules with carbon. This branch of science explores the structure, properties, composition, reactions, and preparation of carbon-containing compounds. Carbon's ability to form stable bonds with itself and a wide variety of other elements allows for complex structures.
For example:
For example:
- Carbon can form single, double, and triple bonds.
- It can create chains, branches, and rings.
- These features lead to an immense variety of organic compounds.
Molecular Formula
The molecular formula tells us the types and numbers of atoms in a molecule. It helps in identifying substances and determining isomers. For instance, 'the molecular formula is given as '\(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}\) in the original compound. This formula indicates there are four carbon, nine hydrogen, and one oxygen atoms present.
When identifying isomers, it's crucial to ensure the molecular formula remains constant even though the arrangement of atoms (structure) might not.
When identifying isomers, it's crucial to ensure the molecular formula remains constant even though the arrangement of atoms (structure) might not.
- A small change in the arrangement can lead to different properties.
- Even if the molecular formula remains the same, structural changes can lead to different substances.
Structural Isomers
Structural isomers are compounds with the same molecular formula but different structures. This means the atoms are connected in different ways. Isomers can have entirely different physical and chemical properties even though their molecular formula is identical.
A key step is comparing how the atoms are bonded:
A key step is comparing how the atoms are bonded:
- For instance, the molecular formula \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}\) can be rearranged to form different structures.
- In the given exercise, the original compound is compared with options to find its structural isomer.
- Option (b), \(\mathrm{CH}_{3}\mathrm{CHOHCH}_{2} \mathrm{CH}_{3}\), has a different OH group placement, thereby being a structural isomer.
Functional Groups
Functional groups are specific groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules. They play a crucial role in determining the reactivity and solubility of compounds. Common functional groups include hydroxyl (\(-\mathrm{OH}\)), carboxyl (\(-\mathrm{COOH}\)), and amino (\(-\mathrm{NH}_{2}\)).
In our exercise:
In our exercise:
- The hydroxyl group \(-\mathrm{OH}\) is present in the original compound.
- Different placements of this group in a molecule can drastically change its properties.
- Structural isomers often have similar functional groups but differ in their positions.
Other exercises in this chapter
Problem 124
The formula for calcium chlorite is (a) \(\mathrm{CaClO}_{2}\) (b) \(\mathrm{Ca}\left(\mathrm{ClO}_{2}\right)_{2} ;(\mathrm{c}) \mathrm{CaClO}_{3} ;(\mathrm{d})
View solution Problem 125
A formula unit of the compound \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}\) has nearly equal masses of (a) \(\mathrm{S}\) and \(
View solution Problem 127
A hydrate of \(\mathrm{Na}_{2} \mathrm{SO}_{3}\) contains almost exactly \(50 \% \mathrm{H}_{2} \mathrm{O}\) by mass. What is the formula of this hydrate?
View solution Problem 128
Malachite is a common copper-containing mineral with the formula \(\mathrm{CuCO}_{3} \cdot \mathrm{Cu}(\mathrm{OH})_{2} .\) (a) What is the mass percent copper
View solution