Problem 124
Question
Write each sum in expanded form. $$ \sum_{n=0}^{3} a_{n} \text { where } a_{0}=1 \text { and } a_{n+1}=2 a_{n} $$
Step-by-Step Solution
Verified Answer
The sum is expanded as \(1 + 2 + 4 + 8\).
1Step 1: Identify the given summation
We are given the summation expression \( \sum_{n=0}^{3} a_{n} \). This means we will sum the terms \(a_0, a_1, a_2,\) and \(a_3\).
2Step 2: Calculate the first term
We start from \(n=0\), where \(a_0 = 1\).
3Step 3: Use the recursive formula to find subsequent terms
We use the recursive formula \(a_{n+1} = 2a_n\) to find each term up to \(a_3\).
4Step 4: Calculate \(a_1\)
Using the previous term \(a_0 = 1\), we apply the formula: \(a_1 = 2 \times a_0 = 2 \times 1 = 2\).
5Step 5: Calculate \(a_2\)
Using \(a_1 = 2\), we apply the formula: \(a_2 = 2 \times a_1 = 2 \times 2 = 4\).
6Step 6: Calculate \(a_3\)
Using \(a_2 = 4\), we apply the formula: \(a_3 = 2 \times a_2 = 2 \times 4 = 8\).
7Step 7: Write the sum in expanded form
The terms \(a_0\), \(a_1\), \(a_2\), and \(a_3\) are 1, 2, 4, and 8 respectively. Therefore, the expanded form of the sum is \(1 + 2 + 4 + 8\).
Key Concepts
Recursive FormulaExpanded FormSeries
Recursive Formula
In calculus, a recursive formula is a key concept that helps define a sequence in terms of its preceding terms. In simpler terms, instead of giving you each number in a series outright, it provides a way to calculate the next number based on the previous one.
For our exercise, the recursive formula is given as \(a_{n+1} = 2a_n\). This tells us how to find any term of the series if we know the term before it:
For our exercise, the recursive formula is given as \(a_{n+1} = 2a_n\). This tells us how to find any term of the series if we know the term before it:
- The formula shows how to "double" the previous term to get the next one.
- Start with \(a_0 = 1\).
- For each next term, multiply the previous term by 2.
Expanded Form
When we talk about writing a summation in expanded form, we're essentially unfolding the sum so we can clearly see all the components. It's like opening a box to see what's inside.
An expanded form writes out each term in the series one by one, rather than just providing a compact formula like \( \sum \). For our exercise:
An expanded form writes out each term in the series one by one, rather than just providing a compact formula like \( \sum \). For our exercise:
- We have to find the sum \( \sum_{n=0}^{3} a_{n} \).
- We calculated that \( a_0 = 1 \), \( a_1 = 2 \), \( a_2 = 4 \), and \( a_3 = 8 \).
Series
A series in calculus refers to the sum of the terms of a sequence. The term "series" might sound grand, but it's just about adding certain numbers from a sequence together.
In the context of our current exercise, when we calculate the series \(\sum_{n=0}^{3} a_{n}\), we're summing up the terms from \(n=0\) to \(n=3\), which we have already figured out are 1, 2, 4, and 8. The series therefore equals:
Understanding series can make solving complex problems easier, as they provide a structured way to think about adding sequences of numbers. They can sometimes even lead to formulas that describe infinitely many terms, which is a fascinating topic in advanced calculus.
In the context of our current exercise, when we calculate the series \(\sum_{n=0}^{3} a_{n}\), we're summing up the terms from \(n=0\) to \(n=3\), which we have already figured out are 1, 2, 4, and 8. The series therefore equals:
- \(1 + 2 + 4 + 8\)
Understanding series can make solving complex problems easier, as they provide a structured way to think about adding sequences of numbers. They can sometimes even lead to formulas that describe infinitely many terms, which is a fascinating topic in advanced calculus.
Other exercises in this chapter
Problem 122
Write each sum in expanded form. $$ \sum_{k=1}^{3} \frac{k^{2}}{k^{2}+1} $$
View solution Problem 123
Write each sum in expanded form. $$ \sum_{n=0}^{3} a_{n} \text { where } a_{0}=1 \text { and } a_{n+1}=2 a_{n} $$
View solution Problem 125
In Problems 125-132, write each sum in sigma notation. \(2+4+6+8+\cdots+2 n\)
View solution Problem 126
Write each sum in sigma notation. \(\frac{1}{\sqrt{1}}+\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{3}}+\frac{1}{\sqrt{4}}\)
View solution