Problem 124
Question
Write a numerical expression for each phrase, and simplify the expression. The product of \(-\frac{2}{3}\) and \(-\frac{1}{5},\) divided by \(\frac{1}{7}\)
Step-by-Step Solution
Verified Answer
\[ \frac{14}{15} \]
1Step 1: Identify the mathematical operations
First, determine the operations required. The phrase 'The product of \(-\frac{2}{3}\) and \(-\frac{1}{5},\) divided by \frac{1}{7}\', includes multiplication and division.
2Step 2: Write the expression
Translate the phrase into a numerical expression. This results in: \[ \( -\frac{2}{3} \times -\frac{1}{5}\) \div \frac{1}{7} \]
3Step 3: Simplify the multiplication
First, simplify the multiplication part of the expression: \[ \-\frac{2}{3} \times -\frac{1}{5} = \frac{2 \times 1}{3 \times 5} = \frac{2}{15} \]
4Step 4: Rewrite the division as multiplication
To divide by \frac{1}{7}, multiply by its reciprocal: \[ \frac{2}{15} \times 7 = \frac{2 \times 7}{15} \]
5Step 5: Simplify the final expression
Complete the multiplication: \[ \frac{2 \times 7}{15} = \frac{14}{15} \]
Key Concepts
Multiplication of FractionsDivision of FractionsReciprocal in Mathematics
Multiplication of Fractions
When multiplying fractions, you simply multiply the numerators (top numbers) together and the denominators (bottom numbers) together.
For example: \( \frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d} \).
As seen in the given problem, to multiply \( -\frac{2}{3} \) and \( -\frac{1}{5} \), follow this rule: \( -\frac{2}{3} \times -\frac{1}{5} = \frac{-2 \times -1}{3 \times 5} = \frac{2}{15} \).
The negative signs cancel each other out, resulting in a positive fraction.
This simplified result, \( \frac{2}{15} \), becomes the output of our multiplication process.
For example: \( \frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d} \).
As seen in the given problem, to multiply \( -\frac{2}{3} \) and \( -\frac{1}{5} \), follow this rule: \( -\frac{2}{3} \times -\frac{1}{5} = \frac{-2 \times -1}{3 \times 5} = \frac{2}{15} \).
The negative signs cancel each other out, resulting in a positive fraction.
This simplified result, \( \frac{2}{15} \), becomes the output of our multiplication process.
Division of Fractions
Dividing fractions might seem tricky, but it's quite simple when you understand the basic rule: To divide by a fraction, multiply by its reciprocal.
A reciprocal of a fraction \( \frac{a}{b} \) is \( \frac{b}{a} \).
So, when we see a division sign like \( \div \frac{1}{7} \), we know we need to multiply by \( \frac{7}{1} \).
Applying this to our previous result: \( \frac{2}{15} \div \frac{1}{7} \), we instead do \( \frac{2}{15} \times \frac{7}{1} = \frac{2 \times 7}{15} = \frac{14}{15} \).
And thus, our final simplified expression is \( \frac{14}{15} \).
A reciprocal of a fraction \( \frac{a}{b} \) is \( \frac{b}{a} \).
So, when we see a division sign like \( \div \frac{1}{7} \), we know we need to multiply by \( \frac{7}{1} \).
Applying this to our previous result: \( \frac{2}{15} \div \frac{1}{7} \), we instead do \( \frac{2}{15} \times \frac{7}{1} = \frac{2 \times 7}{15} = \frac{14}{15} \).
And thus, our final simplified expression is \( \frac{14}{15} \).
Reciprocal in Mathematics
A reciprocal is essentially flipping a fraction. If you have \( \frac{a}{b} \), its reciprocal is \( \frac{b}{a} \).
This comes in handy, particularly with division of fractions.
For example, dividing by \( \frac{1}{7} \) is the same as multiplying by \( 7 \).
Think of it like this: Instead of splitting a whole into even more parts, you see how many times a slightly larger part (like 7, in this instance) can fit.
In our given problem, this step is crucial to turning the division into a multiplication and simplifying our work.
It's these little rules that make working with fractions much simpler and more consistent.
This comes in handy, particularly with division of fractions.
For example, dividing by \( \frac{1}{7} \) is the same as multiplying by \( 7 \).
Think of it like this: Instead of splitting a whole into even more parts, you see how many times a slightly larger part (like 7, in this instance) can fit.
In our given problem, this step is crucial to turning the division into a multiplication and simplifying our work.
It's these little rules that make working with fractions much simpler and more consistent.
Other exercises in this chapter
Problem 123
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