Problem 124

Question

Planetary Orbils \(\quad\) The formula \(T(x)=x^{3 / 2}\) calculates the time in years that it takes a planet to orbit the sun if the planet is \(x\) times farther from the sun than Earth is. (a) Find the inverse of \(T\). (b) What does the inverse of \(T\) calculate?

Step-by-Step Solution

Verified
Answer
(a) The inverse is \(T^{-1}(x) = x^{2/3}\). (b) It calculates distance from the sun based on orbital period.
1Step 1: Understanding the Function
The function given is \(T(x) = x^{3/2}\). It determines the orbit period of a planet in years based on the distance ratio \(x\), compared to Earth's distance from the sun.
2Step 2: Finding the Inverse Function
To find the inverse of \(T(x) = x^{3/2}\), swap \(x\) and \(y\), setting \(y = x^{3/2}\). Solve for \(x\) in terms of \(y\):\[ x = y^{2/3} \]. Thus, the inverse function \(T^{-1}(x)\) is \(x^{2/3}\).
3Step 3: Interpreting the Inverse Function
The inverse function \(T^{-1}(x) = x^{2/3}\) calculates the distance of a planet from the sun (as a multiple of Earth's distance) based on the orbital period in Earth years. Essentially, it tells us how much farther a planet is from the sun compared to Earth if we know its orbital period.

Key Concepts

Orbital MechanicsAlgebraic FunctionsPlanetary Motion
Orbital Mechanics
Orbital mechanics is all about understanding how celestial bodies like planets, moons, and satellites move under the gravitational influence of other celestial bodies. It's part of the field known as astrophysics. One of the famous laws used in orbital mechanics is Kepler's Third Law, which states that the square of the period of orbit (the time it takes to complete one orbit) is proportional to the cube of the semi-major axis of its orbit. This principle helps us comprehend the intricate dance of planets around a star. In the context of the exercise, the function \[ T(x) = x^{3/2} \] is used to model the orbital period in years for planets at various distances from the sun. When applying this formula, astronomers can predict how long it takes for a planet to complete one orbit around the sun. Understanding this relationship is crucial for calculating orbits of not only planets but also man-made satellites.
Knowing how these elements interact forms the basis for mission planning, whether sending a probe to another planet or launching satellites into orbit. Engineers and scientists use these principles daily to ensure successful missions in space.
Algebraic Functions
Algebraic functions are the core mathematical expressions that involve variables and constants, utilizing operations like addition, subtraction, multiplication, and division. They form the foundation of many scientific calculations and problem-solving techniques.In solving the original exercise, we utilize one such function, \[ T(x) = x^{3/2} \]. This function is used to calculate the orbital period of a planet based on how far it is from the sun relative to Earth. To find the inverse of this function, we perform a sequence of algebraic manipulations:
  • Swap the variables: Set \( y = x^{3/2} \)
  • Solve for x: \( x = y^{2/3} \)
The inverse function, \[ T^{-1}(x) = x^{2/3} \], allows us to reverse the calculation process, determining how far a planet is from the sun if its orbital period is known. This kind of reverse calculation is common in science, allowing researchers to derive one quantity when another is measured.
Planetary Motion
Planetary motion describes how planets orbit around stars, such as Earth's orbit around the sun. This motion results from the gravitational pull exerted by the star, and it often follows predictable and calculable paths known as orbits. These orbits provide vital information for understanding the setup of our solar system and the dynamics within. The original exercise uses the formula \[ T(x) = x^{3/2} \] which reflects the relationship between a planet’s distance from the sun and its orbital period. The inverse function \[ T^{-1}(x) = x^{2/3} \] illustrates the distance of a planet based on its known orbital period. These functions show that a planet's orbital period will grow significantly longer as it moves further from the sun. By leveraging such mathematical models, scientists can explore how planets travel through space and how such motions affect the rest of the cosmic environment. This knowledge is also essential in space exploration and understanding potential habitable zones in other stellar systems.