Problem 124
Question
In the following sequence of reactions. Identify (E)? \(\mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2} \longrightarrow(\mathrm{A}) \stackrel{\Delta, \mathrm{ZnCl}_{2}}{\longrightarrow}\) \((\mathrm{B}) \stackrel{\Delta}{\longrightarrow}(\mathrm{C})+(\mathrm{D}) \uparrow \stackrel{\mathrm{NaOH}}{\longrightarrow}(\mathrm{E})\) (a) \(\mathrm{NaHCO}_{3}\) (b) \(\mathrm{Na}_{2} \mathrm{O}_{2}\) (c) \(\mathrm{Na}_{2} \mathrm{ZnO}_{2}\) (d) \(\mathrm{Zn} \mathrm{CO}_{3}^{2}\)
Step-by-Step Solution
Verified Answer
The compound (E) is sodium zincate, option (c) \( \mathrm{Na}_2 \mathrm{ZnO}_2 \).
1Step 1: Understanding the Starting Reaction
The initial reaction is \[ \mathrm{Na}_2 \mathrm{CO}_3 + \mathrm{H}_2 \mathrm{O} + \mathrm{CO}_2 \rightarrow (\mathrm{A}) \]This reaction is a formation of sodium bicarbonate (baking soda), \[ \mathrm{NaHCO}_3 \ (\text{A}) \] The insulation of water and passing of carbon dioxide gas through sodium carbonate leads to the formation of sodium bicarbonate.
2Step 2: Reaction with Heat and Catalyst
The next reaction is what happens to compound \( (\mathrm{A}) \) when heated with \( \mathrm{ZnCl}_2 \).\[ \mathrm{2NaHCO}_3 \xrightarrow{\Delta, \mathrm{ZnCl}_2} \mathrm{Na}_2 \mathrm{CO}_3 \ (\text{B}) + \mathrm{CO}_2 + \mathrm{H}_2 \mathrm{O} \]This step regenerates sodium carbonate (\( \mathrm{Na}_2 \mathrm{CO}_3 \)) as compound \( (\mathrm{B}) \).
3Step 3: Decomposition by Heating
The compound \( (\mathrm{B}) \), the sodium carbonate, when heated further results in:\[ \mathrm{Na}_2 \mathrm{CO}_3 \xrightarrow{\Delta} \mathrm{Na}_2 \mathrm{O} \ (C) + \mathrm{CO}_2 \ (D) \uparrow \]This step decomposes sodium carbonate into sodium oxide \( \mathrm{Na}_2 \mathrm{O} \) and releases carbon dioxide gas.
4Step 4: Reaction with Sodium Hydroxide
Finally, the sodium oxide formed \( \mathrm{Na}_2 \mathrm{O} \) reacts with sodium hydroxide \( \mathrm{NaOH} \):\[ \mathrm{Na}_2 \mathrm{O} + \mathrm{NaOH} \rightarrow \mathrm{Na}_2 \mathrm{ZnO}_2 \ (\mathrm{E}) \]The product formed in the presence of \( \mathrm{NaOH} \) is sodium zincate \( \mathrm{Na}_2 \mathrm{ZnO}_2 \).
5Step 5: Identifying the Compound (E)
Compound \( (\mathrm{E}) \) corresponds to \( \mathrm{Na}_2 \mathrm{ZnO}_2 \), which is present in option (c).Therefore, the correct answer is option (c) \( \mathrm{Na}_2 \mathrm{ZnO}_2 \).
Key Concepts
Sodium Bicarbonate FormationDecomposition ReactionsSodium Zincate Formation
Sodium Bicarbonate Formation
We start with the formation of sodium bicarbonate, which is a critical step in many chemical processes. When sodium carbonate \( \text{Na}_2\text{CO}_3 \) is mixed with water \( \text{H}_2\text{O} \) and carbon dioxide \( \text{CO}_2 \), it undergoes a series of transformations. This combination leads to the creation of sodium bicarbonate, commonly known as baking soda. This reaction is represented as:
- \( \text{Na}_2\text{CO}_3 + \text{H}_2\text{O} + \text{CO}_2 \rightarrow \text{NaHCO}_3 \)
Decomposition Reactions
Understanding the principle of decomposition is essential in chemistry. In the case of sodium bicarbonate \( \text{NaHCO}_3 \), it undergoes decomposition when heated. Initially, when sodium bicarbonate is heated in the presence of \( \text{ZnCl}_2 \) (acting as a catalyst), it decomposes back into:
- \( 2\text{NaHCO}_3 \xrightarrow{\Delta, \text{ZnCl}_2} \text{Na}_2\text{CO}_3 + \text{CO}_2 + \text{H}_2\text{O} \)
- \( \text{Na}_2\text{CO}_3 \xrightarrow{\Delta} \text{Na}_2\text{O} + \text{CO}_2 \)
Sodium Zincate Formation
The final step introduces sodium hydroxide \( \text{NaOH} \), which reacts with the sodium oxide \( \text{Na}_2\text{O} \) formed from the decomposition process. This reaction creates sodium zincate:
- \( \text{Na}_2\text{O} + \text{NaOH} \rightarrow \text{Na}_2\text{ZnO}_2 \)
Other exercises in this chapter
Problem 122
Match the following: List I List II 1\. efflorescent (i) \(\mathrm{NaOH}\) 2\. deliquescent (ii) \(\mathrm{KOH}\) 3\. fusion mixture (iii) \(\mathrm{Na}_{2} \ma
View solution Problem 123
The major role of fluorspar \(\left(\mathrm{CaF}_{2}\right)\) which is added in small quantities in the electrolytic reduction of alumina dissolved in fused cry
View solution Problem 125
The pair of compounds which cannot exist together in aqueous solution is 1\. \(\mathrm{NaH}_{2} \mathrm{PO}_{4}\) and \(\mathrm{Na}_{2} \mathrm{HCO}_{3}\) 2\. \
View solution Problem 126
Consider the following reactions: 1\. \(2 \mathrm{Na}+2 \mathrm{H}_{2} \mathrm{O} \longrightarrow 2 \mathrm{NaOH}+\mathrm{H}_{2}\) 2\. \(2 \mathrm{NaOH}+\mathrm
View solution