Problem 123
Question
Use a graphing utility and the graph's \(x\) -intercepts to solve each equation. Check by direct substitution. A viewing rectangle is given. $$\begin{aligned}&-x^{4}+4 x^{3}-4 x^{2}=0\\\&[-6,6,1] \text { by }[-9,2,1]\end{aligned}$$
Step-by-Step Solution
Verified Answer
The solutions are the x-values where the plot crosses the x-axis which are validated if they equal to zero when plugged back into the original equation.
1Step 1: Graph the Equation
For the equation \(-x^{4}+4 x^{3}-4 x^{2}=0\), set up your graphing utility to the given viewing rectangle [-6,6,1] by [-9,2,1]. This means your x-values will range from -6 to 6 and your y-values will range from -9 to 2. Once you have set up your graphing utility, plot the equation.
2Step 2: Identify the x-intercepts
The x-intercepts of any plot or graph on a Cartesian plane are points where the function crosses the x-axis, meaning where the y-value is zero. Identify these points on your graph, which are the real solutions for the equation.
3Step 3: Verify the Solutions
Now, directly substitute the identified x-values from step two into the original equation. These values should make the equation equal to zero. If they do, then they are the solutions to the equation. If not, revisualize the diagram and identify the intersect values again.
Key Concepts
Understanding x-interceptsUtilizing a graphing utilityWorking on a Cartesian planeDirect substitution for verification
Understanding x-intercepts
In any graph of a polynomial equation, the x-intercepts are crucial features to identify. These are the points on the graph where the curve crosses the x-axis, meaning the y-value is zero here.
To find the x-intercepts, simply look for the values of \(x\) where the output of the function (\(y\)) is zero. For the polynomial equation \(-x^4 + 4x^3 - 4x^2 = 0\), find the points on the plotted graph where the line meets the x-axis. This is where the x-intercepts are located.
To find the x-intercepts, simply look for the values of \(x\) where the output of the function (\(y\)) is zero. For the polynomial equation \(-x^4 + 4x^3 - 4x^2 = 0\), find the points on the plotted graph where the line meets the x-axis. This is where the x-intercepts are located.
- The x-intercepts represent the real roots of the equation.
- These points give an insight into how the graph behaves and provide the solutions to the equation.
- They help us understand the relationship between factors and the overall polynomial.
Utilizing a graphing utility
A graphing utility is a powerful tool for visualizing and solving polynomial equations. This tool allows you to plot the function, making it easier to see where the graph intersects with the x-axis.
- To use a graphing utility, input your equation and set the viewing rectangle to encompass a range of values for \(x\) and \(y\).
- For the equation \(-x^4 + 4x^3 - 4x^2 = 0\), the given range is \([-6,6,1]\) by \([-9,2,1]\), meaning \(x\) ranges from -6 to 6, and \(y\) from -9 to 2.
- The utility helps you visually find solutions by clearly showing the x-intercepts.
Working on a Cartesian plane
The Cartesian plane is a fundamental concept in graphing polynomial equations. It allows us to visually represent equations like \(-x^4 + 4x^3 - 4x^2 = 0\) and understand their solutions.
- The plane consists of two perpendicular axes: the x-axis (horizontal) and the y-axis (vertical).
- Each point on this plane represents a pair of values \((x, y)\), providing a visual method to solve equations.
- On this plane, the x-intercepts are easily identifiable as they appear where the curve crosses the x-axis.
Direct substitution for verification
Direct substitution is a method used to verify solutions obtained from a graph, specifically x-intercepts. After identifying these intercepts, substituting them back into the original equation confirms their validity.
- For the equation \(-x^4 + 4x^3 - 4x^2 = 0\), when you find x-intercepts such as \(x=a\), substitute \(a\) in place of \(x\) in the equation.
- If the equation results in 0 after substitution, it means that the identified \(x\)-value is indeed correct.
- This method ensures that the solutions are not only visually apparent but also algebraically valid.
Other exercises in this chapter
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