Problem 123
Question
Fill in the boxes so that each statement is true. (More than one answer may be possible for these exercises.) $$ x^{\square}=\frac{1}{x^{5}} $$
Step-by-Step Solution
Verified Answer
The exponent is -5.
1Step 1: Understand the problem
We have an equation involving an exponent, specifically the expression \( x^{\square}=\frac{1}{x^{5}} \). We need to find the exponent that makes this statement true.
2Step 2: Rewrite the expression
The expression \( \frac{1}{x^{5}} \) can be rewritten in terms of negative exponents. Recall that \( \frac{1}{x^n}=x^{-n} \). Using this, we can rewrite \( \frac{1}{x^{5}} \) as \( x^{-5} \).
3Step 3: Equate the exponents
Since \( x^{\square} \) is equal to \( x^{-5} \), the exponent needed is the one that equals \(-5\). Thus, \( \square = -5 \).
4Step 4: Verify the solution
Substitute \( -5 \) back into the original expression to verify. If \( \square = -5 \), then \( x^{-5} = \frac{1}{x^{5}} \), which is true. The expression is satisfied and correctly rewritten.
Key Concepts
Negative ExponentsAlgebraic ExpressionsEquation Solving
Negative Exponents
Negative exponents can initially be a bit confusing, but they are simply another way to represent reciprocals. When you see a negative exponent, such as \( x^{-n} \), it indicates that the base \( x \) is on the bottom of a fraction. This means that \( x^{-n} \) is the same as \( \frac{1}{x^n} \).
For example:
For example:
- \( x^{-2} = \frac{1}{x^2} \)
- \( a^{-3} = \frac{1}{a^3} \)
Algebraic Expressions
Algebraic expressions consist of variables (like \( x \) or \( y \)) combined with numbers and arithmetic operations. They can represent complex equations or simple operations.
Let's break down its components:
Let's break down its components:
- Variables: Symbols that can change value within an expression.
- Constants: Specific numbers that do not change.
- Coefficients: Numbers placed in front of variables, showing multiplication.
- Operations: Include addition, subtraction, multiplication, and division.
Equation Solving
Solving equations is like assembling a puzzle where you're finding the missing piece that makes the whole picture fit together. Equation solving involves finding a value for the unknown that satisfies the given equation.
Here are some strategies:
Here are some strategies:
- Isolating the Variable: Rearrange the equation so the unknown is on one side.
- Using Inverse Operations: Employ inverse mathematical operations to simplify both sides.
For example, use addition to cancel out a subtraction. - Checking Solutions: Substitute back into the original equation to confirm your solution is correct.
Other exercises in this chapter
Problem 122
Simplify. $$ \left(2 a^{3}\right)^{3} a^{-3}+a^{11} a^{-5} $$
View solution Problem 122
The formula \(S=6 x^{2}\) can be used to find the surface area \(S\) of a cube with side length \(x\). Find the surface area of a cube with side length 5 meters
View solution Problem 123
To find the amount of water that a swimming pool in the shape of a cube can hold, do we use the formula for volume of the cube or surface area of the cube? (See
View solution Problem 124
Fill in the boxes so that each statement is true. (More than one answer may be possible for these exercises.) $$ 7^{\square}=\frac{1}{49} $$
View solution