Problem 122
Question
Simplify the expression. $$(18 x)^{0}(4 x y)^{2}\left(3 x^{-1}\right)$$
Step-by-Step Solution
Verified Answer
The simplified expression is \( 48xy^{2} \).
1Step 1: Simplify \( (18x)^{0} \)
Any number raised to the power of 0 equals to 1. Therefore, \( (18x)^{0} = 1 \).
2Step 2: Simplify \( (4xy)^{2} \)
A number or variable raised to the power of 2 means that it is multiplied by itself. Therefore, \( (4xy)^{2} = 4^{2} \cdot x^{2} \cdot y^{2} = 16x^{2}y^{2} \).
3Step 3: Simplify \( (3x^{-1}) \)
A variable raised to the power of -1 means the reciprocal of this variable is taken. Therefore, \( 3x^{-1} = 3/x \).
4Step 4: Combine
Combine the simplified components of the first 3 steps by multiplying them together. The product will be the simplified form of the given expression. Therefore, \( 1 \cdot 16x^{2}y^{2} \cdot 3/x = 48x^{2}y^{2} / x = 48xy^{2} \).
Key Concepts
Exponent RulesAlgebraic ExpressionsNegative Exponents
Exponent Rules
Exponent rules can seem tricky at first, but they're like friends once you get to know them. One key rule to remember is that any number or term raised to the zero power is always equal to one. This is expressed as \( a^0 = 1 \) for any nonzero \( a \). That's why in Step 1 of the solution, \((18x)^0\) becomes \(1\).
Another important rule involves multiplying exponents when you have a term raised to a power, such as \((4xy)^2\). Here, you apply the power to each component, turning the base, \(4xy\), into \(4^2 \cdot x^2 \cdot y^2\). This works because exponentiation distributes over multiplication.
Don't forget the rule for negative exponents: if you have a negative exponent, it implies the reciprocal of the term. For example, \(x^{-n}\) is the same as \(1/x^n\). This becomes useful when simplifying terms like \(3x^{-1}\), which turns into \(3/x\). With these rules, simplifying expressions with exponents becomes much simpler!
Another important rule involves multiplying exponents when you have a term raised to a power, such as \((4xy)^2\). Here, you apply the power to each component, turning the base, \(4xy\), into \(4^2 \cdot x^2 \cdot y^2\). This works because exponentiation distributes over multiplication.
Don't forget the rule for negative exponents: if you have a negative exponent, it implies the reciprocal of the term. For example, \(x^{-n}\) is the same as \(1/x^n\). This becomes useful when simplifying terms like \(3x^{-1}\), which turns into \(3/x\). With these rules, simplifying expressions with exponents becomes much simpler!
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operation symbols. These expressions must be simplified by following mathematical principles and rules.
Ultimately, simplified expressions are easier to work with, whether you're solving equations or performing calculations.
- Variables and Constants: Variables represent unknown values, often seen as letters like \(x\) and \(y\). Constants are numbers on their own.
- Operations: They can include addition, subtraction, multiplication, division, and exponentiation, which states how many times to multiply a base by itself.
Ultimately, simplified expressions are easier to work with, whether you're solving equations or performing calculations.
Negative Exponents
Negative exponents might seem intimidating, but they're just a way of expressing division in a neat manner. When you see an exponent like \(x^{-1}\), it means the reciprocal, which flips the base upside down.
Recognizing how to handle negative exponents will boost your confidence in algebra. Instead of fear, think of them as invitations to uncover more truths about numbers and variables! By embracing them, you'll be well-equipped to tackle complex algebraic challenges effortlessly.
- If you have \(x^{-1}\), it turns into \(1/x\).
- Similarly, \(x^{-n}\) becomes \(1/x^n\), suggesting multiple divisions.
Recognizing how to handle negative exponents will boost your confidence in algebra. Instead of fear, think of them as invitations to uncover more truths about numbers and variables! By embracing them, you'll be well-equipped to tackle complex algebraic challenges effortlessly.
Other exercises in this chapter
Problem 121
Simplify the expression. $$\left(5 s^{5} t^{-5}\right)\left(\frac{3 s^{-2}}{50 t^{-1}}\right)$$
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Use DeMoivre's Theorem to find the indicated power of the complex number. Write the result in standard form. $$(3-2 i)^{5}$$
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Simplify the expression. $$\left(5 a b^{2}\right)\left(a^{-3} b^{0}\right)\left(2 a^{0} b\right)^{-2}$$
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