Problem 122
Question
Iodine is a bluish-black solid. It forms a violetcolored vapor when heated. The solid melts at \(236^{\circ} \mathrm{F}\). What is this temperature in degrees Celsius? in kelvins?
Step-by-Step Solution
Verified Answer
The temperature is \(113.333^{\circ} C\) and \(386.483 \text{ K}\).
1Step 1: Convert Fahrenheit to Celsius Formula
The formula to convert Fahrenheit to Celsius is \( C = \frac{5}{9}(F - 32) \). Identify the Fahrenheit temperature given, which is \( 236^{\circ} F \).
2Step 2: Calculate the Temperature in Celsius
Substitute \(236\) for \(F\) in the conversion formula: \[ C = \frac{5}{9}(236 - 32) \]Calculate:\[ C = \frac{5}{9} \times 204 = 113.333 \ ^{\circ} \text{C} \]
3Step 3: Convert Celsius to Kelvin Formula
The formula to convert Celsius to Kelvin is \( K = C + 273.15 \). Use the Celsius temperature we just calculated: \(113.333^{\circ} C\).
4Step 4: Calculate the Temperature in Kelvin
Substitute \(113.333\) for \(C\) in the conversion formula:\[ K = 113.333 + 273.15 \]Calculate the sum:\[ K = 386.483 \]
Key Concepts
Fahrenheit to CelsiusCelsius to KelvinIodine Properties
Fahrenheit to Celsius
Converting temperatures between different scales is an important skill, especially in scientific contexts. When we're converting Fahrenheit to Celsius, we use the formula: \( C = \frac{5}{9}(F - 32) \). This formula allows us to transform a Fahrenheit temperature into its equivalent in Celsius.
- First, identify the given temperature in Fahrenheit. In this exercise, it's \(236^{\circ} \text{F}\).
- Next, subtract 32 from this value. This step adjusts for the baseline difference between the two scales.
- Then, multiply by \(\frac{5}{9}\). This ratio represents the difference in interval sizing between Fahrenheit and Celsius scales.
- Subtract 32: \(236 - 32 = 204\).
- Multiply by \(\frac{5}{9}\): \(\frac{5}{9} \times 204 = 113.333\ ^{\circ} \text{C}\).
Celsius to Kelvin
Once you have a temperature in Celsius, converting it to Kelvin is straightforward, as both scales are metric and linear. The conversion involves a simple addition: \( K = C + 273.15 \). This constant amount, 273.15, compensates for the starting point difference between the Celsius and Kelvin scales.
- The Kelvin scale starts at absolute zero, which is \(-273.15^{\circ} \text{C}\).
- The size of one degree Celsius is the same as one Kelvin.
- This consistency makes the conversion an addition problem, only dealing with the offset.
- Add 273.15: \(113.333 + 273.15 = 386.483 \ \text{K}\).
Iodine Properties
Iodine is a fascinating element, noted for its distinct bluish-black solid state and its dramatic transformation into a violet gas when heated. This transition occurs without turning into a liquid first, a process called sublimation.
- It is solid at room temperature but when heated, it transitions from solid directly to gas.
- This property makes iodine handy in various scientific applications, particularly in demonstrations of sublimation.
- Iodine's melting point, \(236^{\circ} \text{F}\), corresponds to \(113.333^{\circ} \text{C}\) or \(386.483 \ \text{K}\), showing how properties can be mapped across temperature scales.
Other exercises in this chapter
Problem 120
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