Problem 122
Question
Find the open interval in which \(x\) must lie in order for the given condition to hold. \(y=4 x-6,\) and the difference of \(y\) and 2 is less than 0.02.
Step-by-Step Solution
Verified Answer
1.995 < x < 2.005
1Step 1: Identify the given condition
The equation given is: y = 4x - 6 The problem states that the difference between y and 2 is less than 0.02. Mathematically, this is expressed as: |y - 2| < 0.02
2Step 2: Substitute y into the inequality
We know that y = 4x - 6. Substitute y in the equation |y - 2| < 0.02: |(4x - 6) - 2| < 0.02 Simplify the expression inside the absolute value: |4x - 8| < 0.02
3Step 3: Solve the absolute value inequality
To solve |4x - 8| < 0.02, we split it into two cases: 1. 4x - 8 < 0.02 2. 4x - 8 > -0.02 Solve each inequality separately: 4x - 8 < 0.02 4x < 8.02 x < 2.005 And: 4x - 8 > -0.02 4x > 7.98 x > 1.995
4Step 4: Combine the intervals
Combine the two inequalities: 1.995 < x < 2.005 This is the open interval in which x must lie.
Key Concepts
solving inequalitiesabsolute valueinequality intervalslinear equations
solving inequalities
Inequalities are like balancing acts. Instead of saying things are equal, they show a range of possibilities. If you have an inequality like:
4x - 8 < 0.02, it means the expression 4x - 8 must be less than 0.02.
To solve such inequalities, perform operations like adding, subtracting, multiplying, or dividing, just like you do in normal equations. However, pay attention when multiplying or dividing by negative numbers - the inequality sign flips! For example, dividing both sides by 4 in 4x < 8.02 gives:
x < 2.005.
4x - 8 < 0.02, it means the expression 4x - 8 must be less than 0.02.
To solve such inequalities, perform operations like adding, subtracting, multiplying, or dividing, just like you do in normal equations. However, pay attention when multiplying or dividing by negative numbers - the inequality sign flips! For example, dividing both sides by 4 in 4x < 8.02 gives:
x < 2.005.
absolute value
The absolute value of a number is a way to describe its distance from zero on a number line.
It's always positive or zero. When you see:
|a| < b, understand it as:
-a < a < b. In the exercise, we had:
|4x - 8| < 0.02. This means:
-0.02 < 4x - 8 < 0.02.
It's always positive or zero. When you see:
|a| < b, understand it as:
-a < a < b. In the exercise, we had:
|4x - 8| < 0.02. This means:
-0.02 < 4x - 8 < 0.02.
inequality intervals
After solving separate inequalities, you often combine them into a single interval. This gives a range showing all possible values.
From the exercise, we got two refined inequalities:
x < 2.005 and x > 1.995. These can be combined into the interval:
1.995 < x < 2.005, signifying that x can be any number between 1.995 and 2.005. Notice these small open intervals might be harder to identify, but practice makes perfect!
From the exercise, we got two refined inequalities:
x < 2.005 and x > 1.995. These can be combined into the interval:
1.995 < x < 2.005, signifying that x can be any number between 1.995 and 2.005. Notice these small open intervals might be harder to identify, but practice makes perfect!
linear equations
Linear equations are straightforward. They look like: y = mx + b, where m and b are constants. In our exercise, y = 4x - 6. These types of equations graph as straight lines. By substituting y = 4x - 6 into the inequality |y - 2| < 0.02, we could analyze the problem. This approach helps with visual understanding too! Be comfortable with manipulating such equations, adding, subtracting constants, or even changing forms. Linear methods build foundations for more advanced math topics later.
Other exercises in this chapter
Problem 119
Determine the number of ounces a filled carton of the given size may contain for the given relative error. $$ \left|\frac{x-x_{t}}{x_{t}}\right|=\text { relativ
View solution Problem 121
Find the open interval in which \(x\) must lie in order for the given condition to hold. \(y=2 x+1,\) and the difference of \(y\) and 1 is less than 0.1 .
View solution Problem 123
Find the open interval in which \(x\) must lie in order for the given condition to hold. \(y=4 x-8,\) and the difference of \(y\) and 3 is less than 0.001.
View solution Problem 124
Find the open interval in which \(x\) must lie in order for the given condition to hold. \(y=5 x+12,\) and the difference of \(y\) and 4 is less than 0.0001.
View solution