Problem 122
Question
At the equilibrium position in the process of adsorption (a) \(\Delta \mathrm{H}>0\) (b) \(\Delta \mathrm{H}<\mathrm{T} \Delta \mathrm{S}\) (c) \(\Delta \mathrm{H}>\mathrm{T} \Delta \mathrm{S}\) (d) \(\Delta \mathrm{H}=\mathrm{T} \Delta \mathrm{S}\)
Step-by-Step Solution
Verified Answer
At equilibrium, \( \Delta H = T \Delta S \), so the correct answer is (d).
1Step 1: Understanding Adsorption Equilibrium
In the context of adsorption processes, equilibrium is when the rate of adsorption equals the rate of desorption. At this point, the system reaches a state where the Gibbs free energy change (\( \Delta G \)) is zero.
2Step 2: Gibbs Free Energy Equation
The Gibbs free energy change is given by the equation: \( \Delta G = \Delta H - T \Delta S \), where \( \Delta H \) is the enthalpy change, \( T \) is the temperature, and \( \Delta S \) is the entropy change.
3Step 3: Condition for Equilibrium
At equilibrium, \( \Delta G = 0 \). Therefore, substituting into the Gibbs free energy equation gives \( 0 = \Delta H - T \Delta S \). Rearranging this equation, we find that \( \Delta H = T \Delta S \).
4Step 4: Choose the Correct Option
Based on the rearranged equation \( \Delta H = T \Delta S \), at equilibrium, the relationship between the enthalpy change and the product of temperature and entropy change is defined. Thus, the correct answer is option (d) \( \Delta H = T \Delta S \).
Key Concepts
Gibbs Free EnergyEnthalpy ChangeEntropy Change
Gibbs Free Energy
Gibbs free energy, represented by the symbol \(\Delta G\), is a central concept in understanding chemical reactions and processes, especially in thermodynamics. It determines the spontaneity of a reaction or process. A negative \(\Delta G\) indicates that a process is spontaneous, meaning it can occur without any external input of energy. On the other hand, a positive \(\Delta G\) means the process is non-spontaneous and requires added energy to proceed.
At equilibrium, a fascinating thing happens: \(\Delta G = 0\). This means there is no net change occurring in the system. It's like a perfectly balanced scale where no side tips over, depicting the balance between forward and reverse processes. In adsorption equilibrium, where materials adhere to surfaces, the rate of sticking to a surface equals the rate of leaving it. Hence, energy is perfectly balanced, leading to no overall change in the system's energy level.
At equilibrium, a fascinating thing happens: \(\Delta G = 0\). This means there is no net change occurring in the system. It's like a perfectly balanced scale where no side tips over, depicting the balance between forward and reverse processes. In adsorption equilibrium, where materials adhere to surfaces, the rate of sticking to a surface equals the rate of leaving it. Hence, energy is perfectly balanced, leading to no overall change in the system's energy level.
Enthalpy Change
Enthalpy change, denoted as \(\Delta H\), is a measure of the heat absorbed or released during a process at constant pressure. It tells us about the energy changes associated with making or breaking chemical bonds.
There are two types of processes based on enthalpy:
There are two types of processes based on enthalpy:
- Exothermic processes, where \(\Delta H < 0\), indicating energy is released as heat into the surroundings.
- Endothermic processes, where \(\Delta H > 0\), showing the system absorbs heat from the surroundings.
Entropy Change
Entropy change, symbolized by \(\Delta S\), is a quantitative expression of the disorder or randomness in a system. In thermodynamics, it signifies the degree of spread of energy and matter.
Processes can affect entropy in two primary ways:
Processes can affect entropy in two primary ways:
- When \(\Delta S > 0\), the system's disorder increases, leading to a more spontaneous process.
- When \(\Delta S < 0\), the system's disorder decreases, often resulting from energy being concentrated in fewer places.
Other exercises in this chapter
Problem 120
Choose the incorrect statement for chemical adsorption (1) value of adsorption enthalpy is above \(-20.0 \mathrm{kJmol}^{-1}\) (2) van der Waals forces exist be
View solution Problem 121
Which of the following process does not occur at the interface of phases (a) Hetergenous catalysis (b) Homogeneous catalysis (c) Corrosion (d) Crystallisation
View solution Problem 123
Which of the following interface cannot be obtained? (a) Solid-liquid (b) Liquid-liquid (c) Liquid gas (d) Gas-gas
View solution Problem 124
The term soption stands for (a) Adsorption (b) Absorption (c) Desorption (d) Both absorption and adsorption
View solution