PROBLEM 12.14 - Organic Chemistry

Question

Question: Draw the products of each reaction

a.

b.

Step-by-Step Solution

Answer

Answer

a.

b.

Reduction of sigma bonds with LiAlH 4

LiAlH₄ is used for the reduction of alkyl halide or epoxide. It donates H^- ions which replaces the X^-  ions in alkyl halide. 

The reaction follows S_N2 mechanism; hence it completes in a single step only. In epoxides, the H^-  ion attack on less substituted carbon.

Action of LiAlH 4

a. A hydrogen atom substitutes chlorine.

Reduction of alkyl halide 

b. Hydrogen is substituted, and the C-O bond is broken.

Reduction of epoxide