Problem 121
Question
The total number of robberies in 2000 and 2001 was \(831,000 .\) From 2000 to 2001 the number of robberies declined by \(15,000 .\) (a) Write a system of equations whose solution represents the number of robberies committed in each of these years. (b) Solve the system symbolically. (c) Solve the system graphically.
Step-by-Step Solution
Verified Answer
2000: 423,000 robberies; 2001: 408,000 robberies.
1Step 1: Understand the Problem
We're given the total number of robberies over two years and how many fewer robberies occurred in 2001 compared to 2000. We need first to find out the number of robberies for each individual year.
2Step 2: Formulate Equations
Let \( x \) represent the number of robberies in 2000, and \( y \) represent the number of robberies in 2001. We know two things: 1. \( x + y = 831,000 \) (total number) 2. \( x - y = 15,000 \) (difference from 2000 to 2001). These two equations form our system of equations.
3Step 3: Solve Symbolically: Add Equations
First, add the two equations to eliminate \( y \) and solve for \( x \):\((x + y) + (x - y) = 831,000 + 15,000 \)\(2x = 846,000 \)\(x = 423,000 \) robberies in 2000.
4Step 4: Solve Symbolically: Substitute to Find y
Substitute \( x = 423,000 \) into the first equation to find \( y \):\(423,000 + y = 831,000 \)\(y = 408,000 \) robberies in 2001.
5Step 5: Solve Graphically
Graph the equations \( y = 831,000 - x \) and \( y = x - 15,000 \). The solution to the system corresponds to the point where these two lines intersect on a graph. This intersection is at the point (423,000, 408,000).
Key Concepts
Algebraic SolutionGraphical SolutionProblem-Solving in Algebra
Algebraic Solution
When solving a system of linear equations through algebraic methods, we often rely on techniques like substitution or elimination. In this context, we used the method of elimination to start with.
In simple terms, elimination involves either adding or subtracting equations to "eliminate" one of the variables. Here, by adding the two given equations:
In simple terms, elimination involves either adding or subtracting equations to "eliminate" one of the variables. Here, by adding the two given equations:
- First Equation: \( x + y = 831,000 \)
- Second Equation: \( x - y = 15,000 \)
- \( 2x = 846,000 \)
- Next, divide by 2 to find \( x \): \( x = 423,000 \).
- Substitute this back into the first equation to find \( y \): \( 423,000 + y = 831,000 \), giving \( y = 408,000 \).
Graphical Solution
Graphical solutions provide a visual approach to solving systems of linear equations. By converting equations into line equations, we can graph them to find their point of intersection.
For our example, we transform the given equations:
For our example, we transform the given equations:
- First Equation rearranged: \( y = 831,000 - x \)
- Second Equation rearranged: \( y = x - 15,000 \)
- The slope of the first line is negative, indicating it goes downwards.
- The slope of the second line is positive, going upwards.
Problem-Solving in Algebra
Solving algebraic equations and problems requires not just understanding equations but also translating word problems into mathematical terms. Problem-solving in algebra involves several critical steps:
- Understanding the problem: Identify what is known and what needs to be determined.
- Formulating equations: Convert the word problems into algebraic equations using variables.
- Choosing a solution method: Deciding whether to use substitution, elimination, or graphical representation.
- Evaluating: Check if the solution satisfies all original conditions.
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