Problem 121
Question
Particle When an alpha particle (a subatomic particle) is moving in a horizontal path along the positive \(x\) -axis and passes between charged plates, it is deflected in a parabolic path. If the plate is charged with 2000 volts and is 0.4 meter long, then an alpha particle's path can be described by the equation \(y=-\frac{k}{2 v_{0}} x^{2}\) where \(k=5 \times 10^{-9}\) is constant and \(v_{0}\) is the initial velocity of the particle. If \(v_{0}=10^{7}\) meters per second, what is the deflection of the alpha particle's path in the \(y\) -direction when \(x=0.4\) meter? (Source: Semat, H. and J. Albright, Introduction to Atomic and Nuclear Physics, Holt, Rinehart and Winston.)
Step-by-Step Solution
Verified Answer
The deflection is \(-4 \times 10^{-17}\) meters.
1Step 1: Identify the Given Information
We are given the equation of the path of an alpha particle between charged plates: \(y = -\frac{k}{2 v_0} x^2\). The constants and variables given are:- \(k = 5 \times 10^{-9}\)- \(v_0 = 10^7\) meters per second- The distance \(x = 0.4\) meters.
2Step 2: Substitute Known Values into the Equation
Insert the values of \(k\), \(v_0\), and \(x\) into the equation to find the value of \(y\):\[ y = -\frac{5 \times 10^{-9}}{2 \times 10^7} (0.4)^2 \]
3Step 3: Calculate the Expression
Compute the value of the expression:1. Calculate \(2 \times 10^7 = 2 \times 10^7 = 2 \times 10000000 = 20000000\).2. Calculate \(x^2 = (0.4)^2 = 0.16\).3. Substitute these values back into the expression: - \( y = -\frac{5 \times 10^{-9} \times 0.16}{20000000}\)
4Step 4: Simplify the Expression
Determine the result by simplifying the fraction:\[ y = -\frac{8 \times 10^{-10}}{2 \times 10^7} = -\frac{8 \times 10^{-10}}{20000000} \]Multiply and simplify:\[ y = -\frac{8}{2} \times 10^{-10} \times 10^{-7} \]\[ y = -4 \times 10^{-17} \]
5Step 5: Final Answer Interpretation
The deflection of the alpha particle in the \(y\)-direction is calculated to be \(-4 \times 10^{-17}\) meters. The negative sign indicates the direction of deflection.
Key Concepts
Alpha ParticleEquation of PathDeflection CalculationCharged Plates
Alpha Particle
The alpha particle is a type of subatomic particle that consists of two protons and two neutrons, making it essentially a helium nucleus. These particles are emitted naturally during the radioactive decay of some elements and can also be produced artificially in nuclear reactions.
When alpha particles travel, they can be influenced by electric and magnetic fields. This property makes them useful in experimental physics, where their movement can be tracked and analyzed to understand various forces or fields they pass through.
- They are positively charged due to the protons they contain.
- They are relatively heavy among particles in the nuclear realm.
- They possess high kinetic energy but do not penetrate materials deeply due to their larger mass and charge.
When alpha particles travel, they can be influenced by electric and magnetic fields. This property makes them useful in experimental physics, where their movement can be tracked and analyzed to understand various forces or fields they pass through.
Equation of Path
Considering the motion of an alpha particle between charged plates leads to a parabolic trajectory, which can be described mathematically. The path is influenced by the electric field between the plates, and the motion in the vertical direction can be represented by parabolic equations.
In our context, the equation used is:\[ y = -\frac{k}{2 v_{0}} x^{2}\]
The variables in this equation represent:
In our context, the equation used is:\[ y = -\frac{k}{2 v_{0}} x^{2}\]
The variables in this equation represent:
- \(y\): the vertical deflection of the particle.
- \(x\): the horizontal distance traveled by the alpha particle.
- \(k\): a constant related to the strength of the electric field.
- \(v_0\): the initial velocity of the particle.
Deflection Calculation
Deflection refers to how much the alpha particle's path deviates from its original course due to the influence of external forces, like the electric field in this case.
Calculating this deflection involves using the given equation of path and inserting known values:
Calculating this deflection involves using the given equation of path and inserting known values:
- Substitute into the equation: \(y = -\frac{5 \times 10^{-9}}{2 \times 10^{7}} (0.4)^2\)
- Simplify and solve: The computation results in \(y = -4 \times 10^{-17}\) meters.
- The exact measure of how much the particle's path is perturbed by the charged plates.
- The negative sign shows the deflection direction, which helps indicate the electric field's influence.
Charged Plates
Charged plates create an electric field, which is instrumental in deflecting the alpha particle's trajectory. These plates are commonly used in experiments to study particle behavior under electric forces.
In practical applications, such an arrangement helps physicists understand foundational principles of electromagnetism and particle physics by observing the interactions of charged particles with fields.
- The polarity of the plates determines the direction in which particles are deflected.
- The strength of the electric field will affect how much the path bends.
- A 2000-volt potential difference between the plates indicates significant energy, influencing particle motion considerably.
In practical applications, such an arrangement helps physicists understand foundational principles of electromagnetism and particle physics by observing the interactions of charged particles with fields.
Other exercises in this chapter
Problem 118
Path of an Object on a Planet When an object moves under the influence of a gravitational force (without air resistance), its path can be parabolic. This is the
View solution Problem 120
Design of a Radio Telescope The U.S. Naval Research Laboratory designed a giant radio telescope weighing 3450 tons. Its parabolic dish had a diameter of 300 fee
View solution Problem 124
Headlight \(A\) headlight is being constructed in the shape of a paraboloid with depth 4 inches and diameter 5 inches, as illustrated in the figure. Determine t
View solution Problem 117
Graph each parabola by hand, and check using a graphing calculator. Give the vertex, axis, domain, and range. Prove that the parabola with focus \((c, 0)\) and
View solution