Problem 121
Question
Calculate total number of \(\alpha\) -H present in alkene formed when 2, 3-dimethyl butanol react with concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4} / \Delta\)
Step-by-Step Solution
Verified Answer
The alkene formed is 2,3-dimethyl-2-butene with 6 \(\alpha\)-hydrogens.
1Step 1: Understand the Reaction Type
The reaction is a dehydration of alcohol, where 2,3-dimethyl butanol in the presence of concentrated sulfuric acid (\(\mathrm{H}_{2} \mathrm{SO}_{4}/ \Delta \)) loses a water molecule to form an alkene.
2Step 2: Identify the Structure of 2,3-dimethyl butanol
The structure of 2,3-dimethyl butanol is CH3-CH(CH3)-CH(CH3)-CH2OH. It is a 4-carbon alcohol with methyl groups on the 2nd and 3rd carbons.
3Step 3: Determine the Alkene Product
Dehydration occurs primarily at the OH-bearing carbon and an adjacent carbon (due to Zaitsev's Rule which states the more substituted alkene is favored). The major product is 2,3-dimethyl-2-butene.
4Step 4: Draw the Structure of the Alkene
The structure of 2,3-dimethyl-2-butene is \( CH_3-C(CH_3)=C(CH_3)-CH_3 \). This has a double bond between the second and third carbons, making it more substituted.
5Step 5: Calculate the Number of \(\alpha\)-Hydrogens
\(\alpha\)-Hydrogens are the hydrogen atoms attached to the \(\alpha\)-carbon, which is the carbon adjacent to the double-bonded carbons. In 2,3-dimethyl-2-butene, the \(\alpha\)-carbons are the methyl groups attached to the second and third carbons. Each methyl (CH3) group contains 3 hydrogens, leading to a total of 6 \(\alpha\)-hydrogens.
Key Concepts
Dehydration ReactionZaitsev's RuleAlpha Hydrogen Calculation
Dehydration Reaction
A dehydration reaction is an essential concept in organic chemistry where a water molecule is removed from a compound. This often involves alcohols turning into alkenes, and is catalyzed by acids like concentrated sulfuric acid. 2,3-dimethyl butanol undergoes dehydration when treated with concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}/ \Delta\), meaning heat may be applied to facilitate the reaction. During this process:
- The hydroxyl group (OH) of the alcohol is protonated by the acid, increasing its leaving capability.
- A water molecule is eliminated, forming an unstable carbocation intermediate.
- The carbocation then loses a hydride ion (H⁻), forming a double bond hence an alkene.
Zaitsev's Rule
In organic chemistry, selecting which hydrogen atom to eliminate during a dehydration reaction is often determined by Zaitsev's Rule. This rule posits that the more substituted alkene, one with the most non-hydrogen substituent groups on the double-bonded carbons, is the favored product.
In the reaction involving 2,3-dimethyl butanol, the major product, 2,3-dimethyl-2-butene, exemplifies this rule.
In the reaction involving 2,3-dimethyl butanol, the major product, 2,3-dimethyl-2-butene, exemplifies this rule.
- This alkene is more substituted due to the presence of methyl groups at the double-bonded carbons.
- By following Zaitsev's Rule, you can predict that the alkene formed will be more stable and thus predominantly produced.
Alpha Hydrogen Calculation
Alpha hydrogens are counted to understand the reactivity of a substance, particularly in understanding stability and kinetic aspects of a reaction. To calculate \( \alpha \)-hydrogens in the given alkene, 2,3-dimethyl-2-butene, they are located on the carbons adjacent to the double bond.
These adjacent carbons have been termed \( \alpha \) carbons, and the hydrogens attached are the \( \alpha \)-hydrogens. The 2,3-dimethyl-2-butene structure consists of methyl groups \( (CH_3) \) on each side of the double bond:
These adjacent carbons have been termed \( \alpha \) carbons, and the hydrogens attached are the \( \alpha \)-hydrogens. The 2,3-dimethyl-2-butene structure consists of methyl groups \( (CH_3) \) on each side of the double bond:
- Each methyl group is attached to the \( \alpha \) carbons and has 3 hydrogens.
- With two such groups, there is a total of 6 \( \alpha \)-hydrogens.
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