Problem 120
Question
Exercises 117-120, find the sum of the infinite series. \( \displaystyle \sum_{i=1}^{\infty} 2 \left(\frac{1}{10} \right)^i \)
Step-by-Step Solution
Verified Answer
The sum of the given infinite series is \( \frac{2}{9}\) .
1Step 1: Verification
The series given by the exercise is \( \displaystyle \sum_{i=1}^{\infty} 2 \left(\frac{1}{10} \right)^i \). We can rewrite this as \(2 \displaystyle \sum_{i=1}^{\infty} \left(\frac{1}{10} \right)^i\). Thus the series is written in the basic form for a geometric series which is \(a*r^{n-1}\), where a is the first term, r is the ratio, and n is the term number. In this case, a = 1/5 , r = 1/10.
2Step 2: Conditions
Before we proceed with the calculation we need to ensure that the condition for the convergence of the geometric series is respected. In other words, the absolute value of r should be less than 1. In this case, |r| = |1/10| < 1. Hence, the condition is respected and we can proceed with the calculation of the sum.
3Step 3: Calculation
To find the sum of a convergent infinite geometric series, we use the formula: S= \frac{a}{1-r}. Substituting the values of a and r, we obtain S= \(\frac{1}{5}\) / (1 - \( \frac{1}{10}\)) = \( \frac{1}{5}\) / \( \frac{9}{10} = \frac{2}{9}\)
Key Concepts
Geometric Series ExplainedUnderstanding ConvergenceCalculating the Sum of Series
Geometric Series Explained
A geometric series is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. It's a way to represent repeated multiplication through addition.
In the provided exercise, the series is \( \sum_{i=1}^{\infty} 2 \left(\frac{1}{10} \right)^i \). Notice how each term is generated by multiplying the previous term by \( \frac{1}{10} \), which is the common ratio here.
A geometric series can be finite or infinite. An infinite series continues indefinitely, but remarkably, it can still have a sum, provided certain conditions are met.
In the provided exercise, the series is \( \sum_{i=1}^{\infty} 2 \left(\frac{1}{10} \right)^i \). Notice how each term is generated by multiplying the previous term by \( \frac{1}{10} \), which is the common ratio here.
A geometric series can be finite or infinite. An infinite series continues indefinitely, but remarkably, it can still have a sum, provided certain conditions are met.
- The first term in a geometric series is usually denoted by \( a \).
- The common ratio is denoted by \( r \).
- In our example, \( a = 2 \times \frac{1}{10} = \frac{1}{5} \) and \( r = \frac{1}{10} \).
Understanding Convergence
Convergence of a series is a key concept in calculus and mathematical analysis. It tells us whether an infinite series results in a finite sum or not. For a geometric series to converge, the absolute value of the common ratio \( r \) must be less than 1.
In mathematical terms, if \(|r| < 1\), the series converges; if \(|r| \geq 1\), it diverges and doesn't have a finite sum. This is because when \(|r| < 1\), the successive terms in the series become smaller and smaller, approaching zero.
For the given series, \( r = \frac{1}{10} \), and clearly \(|\frac{1}{10}| < 1\). This means our series is convergent.
In mathematical terms, if \(|r| < 1\), the series converges; if \(|r| \geq 1\), it diverges and doesn't have a finite sum. This is because when \(|r| < 1\), the successive terms in the series become smaller and smaller, approaching zero.
For the given series, \( r = \frac{1}{10} \), and clearly \(|\frac{1}{10}| < 1\). This means our series is convergent.
- Convergence allows us to calculate the sum of the series even if it includes infinite terms.
- This is essential in various fields of science and engineering where infinite processes are often modeled.
Calculating the Sum of Series
To find the sum of an infinite geometric series that converges, we use the formula:
\[S = \frac{a}{1 - r}\]
where \( S \) is the sum, \( a \) is the first term, and \( r \) is the common ratio.
For the series \( \sum_{i=1}^{\infty} 2 \left(\frac{1}{10} \right)^i \), we have \( a = \frac{1}{5} \) and \( r = \frac{1}{10} \). Plugging these values into the formula gives:
\[S = \frac{\frac{1}{5}}{1 - \frac{1}{10}} = \frac{\frac{1}{5}}{\frac{9}{10}}\]
Simplifying this expression:
\[S = \frac{1}{5} \times \frac{10}{9} = \frac{2}{9}\]
So, the infinite series sums up to \( \frac{2}{9} \).
\[S = \frac{a}{1 - r}\]
where \( S \) is the sum, \( a \) is the first term, and \( r \) is the common ratio.
For the series \( \sum_{i=1}^{\infty} 2 \left(\frac{1}{10} \right)^i \), we have \( a = \frac{1}{5} \) and \( r = \frac{1}{10} \). Plugging these values into the formula gives:
\[S = \frac{\frac{1}{5}}{1 - \frac{1}{10}} = \frac{\frac{1}{5}}{\frac{9}{10}}\]
Simplifying this expression:
\[S = \frac{1}{5} \times \frac{10}{9} = \frac{2}{9}\]
So, the infinite series sums up to \( \frac{2}{9} \).
- This result illustrates the power of using the geometric series sum formula.
- It shows how infinite sequences can be managed and understood using mathematical principles.
Other exercises in this chapter
Problem 119
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