Problem 12
Question
Write a system of linear equations in \(x, y,\) and \(z\) represented by each augmented matrix. $$\left[\begin{array}{rrr|r}1 & 4 & -7 & -11 \\\0 & 1 & 3 & -1 \\\0& 0 & 1 & 6\end{array}\right]$$
Step-by-Step Solution
Verified Answer
The short answer for the given augmented matrix is the system of linear equations:
\[\begin{cases}
x + 4y - 7z = -11 \\
y + 3z = -1 \\
z = 6
\end{cases}\]
1Step 1: Rewrite the augmented matrix as a system of equations
Given the augmented matrix:
\(\left[\begin{array}{rrr|r}
1 & 4 & -7 & -11 \\
0 & 1 & 3 & -1 \\
0 & 0 & 1 & 6
\end{array}\right]\)
We can rewrite this augmented matrix as a system of linear equations:
\(1x + 4y - 7z = -11\)
\(0x + 1y + 3z = -1\)
\(0x + 0y + 1z = 6\)
2Step 2: Simplify the system of equations
Now, we can simplify the system of equations by removing any unnecessary terms:
\(x + 4y - 7z = -11\)
\(y + 3z = -1\)
\(z = 6\)
3Step 3: Write the system using x, y, and z variables
Finally, we write the system of linear equations in terms of x, y, and z:
\[\begin{cases}
x + 4y - 7z = -11 \\
y + 3z = -1 \\
z = 6
\end{cases}\]
Key Concepts
Augmented MatrixSolving Linear SystemsVariables in EquationsMatrix Representation
Augmented Matrix
An augmented matrix is a convenient representation used in solving systems of linear equations. When you have a set of linear equations, you can organize the coefficients and constants into a matrix form. This matrix has two parts:
- The coefficients of the variables in the equations form the main part of the matrix.
- The constants on the right side of the equations form an additional column, which is the augmentation.
Solving Linear Systems
Solving a system of linear equations means finding the values of the variables that satisfy all the equations simultaneously.
Common methods include:
Common methods include:
- Substitution: Solving one equation for a variable and substituting it into the other equations.
- Elimination: Adding or subtracting equations to eliminate a variable.
- Augmented Matrix Method: This involves manipulating the augmented matrix to achieve a row-echelon form, ultimately leading to simpler equations to solve.
Variables in Equations
Variables are symbols like \(x\), \(y\), and \(z\) used to represent unknown values in a mathematical expression or equation.
In a system of equations, each equation involves these variables. Depending on the number of equations and their complexity, variables can be independent or dependent on each other.
In a system of equations, each equation involves these variables. Depending on the number of equations and their complexity, variables can be independent or dependent on each other.
- Independent variables: Values that can be freely chosen without any restriction from other variables in the system.
- Dependent variables: Values that depend on the independent variables and fulfil the conditions of the system.
Matrix Representation
Matrix representation is a powerful way to handle systems of linear equations. It allows us to visualize, simplify, and solve equations efficiently.
In a matrix representation, such as our example using variables \(x\), \(y\), and \(z\), each element of the matrix directly corresponds to a coefficient in the equation:
In a matrix representation, such as our example using variables \(x\), \(y\), and \(z\), each element of the matrix directly corresponds to a coefficient in the equation:
- The first column of the matrix corresponds to the coefficients of the variable \(x\).
- The second column corresponds to \(y\), and the third column corresponds to \(z\).
- The vertical line separates these coefficients from the constants, forming the augmented matrix.
Other exercises in this chapter
Problem 11
Solve each inequality. Graph the solution set and write the answer in interval notation. $$|3 k|
View solution Problem 11
Solve. $$|1-8 m|=9$$
View solution Problem 12
Graph using the test point method. \(4 x+3 y
View solution Problem 12
Solve each inequality. Graph the solution set and write the answer in interval notation. $$\left|\frac{5}{4} z\right| \leq 30$$
View solution