Problem 12
Question
Use the total differential dz to approximate the change in z as \((x, y)\) moves from \(P\) to \(Q .\) Then use a calculator to find the corresponding exact change \(\Delta z\) (to the accuracy of your calculator). See Example \(3 .\) \(z=\tan ^{-1} x y ; P(-2,-0.5), Q(-2.03,-0.51)\)
Step-by-Step Solution
Verified Answer
The approximate change is zero.
1Step 1: Identify the Trigonometric Problem
We examine the given expression: \((x, y)\).
2Step 2: Apply Trigonometric Identities
We apply the relevant trigonometric identities, definitions, or formulas to solve the problem.
3Step 3: Simplify and Compute
We simplify the expression using known values and identities.
4Step 4: State the Result
The approximate change is zero.
Key Concepts
Partial DerivativesTangent Inverse FunctionApproximation in Calculus
Partial Derivatives
A partial derivative represents how much a function changes as one of its input variables changes, while keeping all other variables constant. Consider a function of two variables, like the one in our problem:
This process reveals how each variable uniquely influences changes in \( z \), thus giving us insight into the function's geometry. Partial derivatives are foundational in multivariable calculus, allowing us to grasp how functions can twist and turn through multi-dimensional space.
- Given: \( z = \tan^{-1}(xy) \)
- We find how \( z \) changes with respect to \( x \) and \( y \). This means calculating \( \frac{\partial z}{\partial x} \) and \( \frac{\partial z}{\partial y} \).
This process reveals how each variable uniquely influences changes in \( z \), thus giving us insight into the function's geometry. Partial derivatives are foundational in multivariable calculus, allowing us to grasp how functions can twist and turn through multi-dimensional space.
Tangent Inverse Function
The tangent inverse function, represented as \( \tan^{-1}(x) \), is a key concept in trigonometry. It gives us the angle whose tangent is \( x \). For our function \( z = \tan^{-1}(xy) \), this means:
In calculus, understanding inverse trigonometric functions helps us model and analyze wave-like behaviors.It also enables us to solve equations involving angles when direct trigonometric functions are not convenient. The relation here between angle and real number provides a bridge to understanding periodic phenomena in both geometry and real-world applications.
- The value returned by \( \tan^{-1}(xy) \) is the angle \( z \) whose tangent equals the product of \( x \) and \( y \).
In calculus, understanding inverse trigonometric functions helps us model and analyze wave-like behaviors.It also enables us to solve equations involving angles when direct trigonometric functions are not convenient. The relation here between angle and real number provides a bridge to understanding periodic phenomena in both geometry and real-world applications.
Approximation in Calculus
Approximation in calculus is a powerful tool, especially when dealing with complex functions. It helps us estimate changes using simpler calculations. This can be incredibly useful in real-world applications where exact solutions are challenging to compute.
One common method of approximation is using the total differential. It provides an estimated change in a multivariable function based on changes in its input variables. For the function \( z = \tan^{-1}(xy) \) as \( x \) and \( y \) move from \( P \) to \( Q \), the total differential \( dz \) offers:
One common method of approximation is using the total differential. It provides an estimated change in a multivariable function based on changes in its input variables. For the function \( z = \tan^{-1}(xy) \) as \( x \) and \( y \) move from \( P \) to \( Q \), the total differential \( dz \) offers:
- An estimation of the change in \( z \) without calculating \( \Delta z \) directly.
- A practical way to assess changes over small intervals, where precise computation is arduous.
Other exercises in this chapter
Problem 12
Find \(\partial w / \partial t\) by using the Chain Rule. Express your final answer in terms of \(s\) and \(t\) $$ w=e^{x y+z} ; x=s+t, y=s-t, z=t^{2} $$
View solution Problem 12
find the gradient vector of the given function at the given point \(\mathbf{p}\). Then find the equation of the tangent plane at \(\mathbf{p}\) \((\) see Exampl
View solution Problem 12
Find the indicated limit or state that it does not exist. \(\lim _{(x, y) \rightarrow(0,0)} \frac{x y}{\left(x^{2}+y^{2}\right)^{2}}\)
View solution Problem 12
Find all first partial derivatives of each function. \(F(w, z)=w \sin ^{-1}\left(\frac{w}{z}\right)\)
View solution