Problem 12
Question
The interval of convergence of a power series is \((-2,5]\). (a) What is the radius of convergence? (b) What is the center of the series?
Step-by-Step Solution
Verified Answer
The radius of convergence is 3.5 and the center of the series is 1.5.
1Step 1: Finding the Length of the Interval
First, find the length of the given interval. The interval is \((-2,5]\), so to find the length, subtract the left end of the interval from the right end of the interval, i.e., \(5 - (-2) = 7\).
2Step 2: Finding the Radius of Convergence
The radius of convergence is half the length of the interval of convergence. Therefore, divide the obtained length by 2. So, \(7/2 = 3.5\)
3Step 3: Finding the Center of the Series
The center of the series is just the midpoint of the interval of convergence, which can be found by averaging the endpoints of the interval, i.e., \((-2+5)/2 = 1.5\)
Key Concepts
Power SeriesRadius of ConvergenceCenter of the Series
Power Series
A power series is a type of infinite series that involves a variable raised to successive powers. It's expressed in the form \( \sum_{n=0}^{\infty} a_n (x - c)^n \), where \( a_n \) represents the coefficients, \( x \) is the variable of the series, and \( c \) is the center of the series. Power series are extremely versatile, as they can be used to represent various functions, especially in calculus for approximation purposes.
Some key characteristics of power series include:
Some key characteristics of power series include:
- The terms include powers of \( x \), which means the series is dependent on a variable unlike typical numerical series.
- The series can converge or diverge depending on the value of \( x \).
- Power series can represent analytical functions within their interval of convergence.
Radius of Convergence
The concept of the radius of convergence is central to understanding power series. It defines a distance within which the series will converge around the center. Our series might not converge for every value of \( x \), but within a certain radius from the center, it will.
To find the radius of convergence, especially if the interval is given, one needs to:
To find the radius of convergence, especially if the interval is given, one needs to:
- Measure the total length of the interval of convergence.
- Divide this length by 2 to calculate the radius.
Center of the Series
The center of a power series is a key feature that helps in understanding its behavior and characteristics. It is the point \( c \) at which the series is centered and forms the basis from which the radius of convergence is measured outwards.
To find the center of the series, particularly when given the interval of convergence, you can calculate the midpoint of this interval. This is done by averaging the endpoints of the interval.
For instance, given the interval \((-2, 5]\), the center of the series can be determined by calculating the average: \((-2 + 5)/2 = 1.5\).
The center is crucial because it acts as the focal point around which convergence is measured. Knowing the center allows us to better understand where around this point the series might converge and therefore be used effectively in approximations and calculations.
In summary, the center influences both the convergence behavior and the usability of a power series to model functions within the determined radius.
To find the center of the series, particularly when given the interval of convergence, you can calculate the midpoint of this interval. This is done by averaging the endpoints of the interval.
For instance, given the interval \((-2, 5]\), the center of the series can be determined by calculating the average: \((-2 + 5)/2 = 1.5\).
The center is crucial because it acts as the focal point around which convergence is measured. Knowing the center allows us to better understand where around this point the series might converge and therefore be used effectively in approximations and calculations.
In summary, the center influences both the convergence behavior and the usability of a power series to model functions within the determined radius.
Other exercises in this chapter
Problem 12
Approximate \(\frac{1}{e}\) with error less than \(10^{-5}\).
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What degree Taylor polynomial for \(e^{x}\) about \(x=0\) must be used to approximate \(e^{0.3}\) with error less than \(10^{-5}\) ?
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Determine whether the series converges or diverges. It is possible to solve Problems 4 through 19 without the Limit Comparison, Ratio, and Root Tests. \(\sum_{k
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Arrive at the series for \(\cos x\) by differentiating the Maclaurin series for \(\sin x\).
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