Problem 12
Question
$$ \text { In Exercises } 11 \text { through } 32 \text {, find the solution set of the given inequality and illustrate the solution on the real number } $$ $$ 3-x<5+3 x $$
Step-by-Step Solution
Verified Answer
The solution set is \(x > -1/2\).
1Step 1 - Move Variables to One Side
Start by moving all the terms containing the variable to one side of the inequality. Subtract \(3x\) from both sides:\(3 - x - 3x < 5 + 3x - 3x\)
2Step 2 - Combine Like Terms
Combine the like terms on each side:\(3 - 4x < 5\)
3Step 3 - Isolate the Variable
Subtract 3 from both sides to isolate the term that contains \(x\):\(3 - 4x - 3 < 5 - 3\)\(-4x < 2\)
4Step 4 - Solve for the Variable
Divide both sides by -4, remembering to reverse the inequality sign when dividing by a negative number:\(-4x / -4 > 2 / -4\)\( x > -1 / 2\)
5Step 5 - Illustrate the Solution
On a number line, draw an open circle at \(-1/2\) and shade all numbers to the right to indicate that \(x\) can be any value greater than \(-1/2\).
Key Concepts
Inequalities in AlgebraIsolation of VariablesReversing Inequality SignsNumber Line Representation
Inequalities in Algebra
When we work with inequalities in algebra, our goal is to find a set of values that satisfy the given inequality. Inequalities are similar to equations, but instead of having an equal sign (\( = \)), they use less than (\( < \)), greater than (\( > \)), less than or equal to (\( \leq \)), and greater than or equal to (\( \geq \)) signs.
For example, in the inequality \( 3 - x < 5 + 3x \), we are looking for all the values of \( x \) that make this statement true.
The primary difference between solving equations and inequalities is how we handle the inequality signs, especially when multiplying or dividing by negatives.
For example, in the inequality \( 3 - x < 5 + 3x \), we are looking for all the values of \( x \) that make this statement true.
The primary difference between solving equations and inequalities is how we handle the inequality signs, especially when multiplying or dividing by negatives.
Isolation of Variables
To solve inequalities, we often need to isolate the variable. This means getting the variable on one side of the inequality and the constant terms on the other.
In our exercise, we start by moving all \( x \) terms to one side: \( 3 - x - 3x < 5 + 3x - 3x \).
After simplifying, we get \( 3 - 4x < 5 \). Now, we need to isolate \( x \) by getting rid of the constants on the left side. We subtract 3 from both sides to get \( -4x < 2 \).
Isolation helps us to get a clearer view of the variable's relationship with the constant.
In our exercise, we start by moving all \( x \) terms to one side: \( 3 - x - 3x < 5 + 3x - 3x \).
After simplifying, we get \( 3 - 4x < 5 \). Now, we need to isolate \( x \) by getting rid of the constants on the left side. We subtract 3 from both sides to get \( -4x < 2 \).
Isolation helps us to get a clearer view of the variable's relationship with the constant.
Reversing Inequality Signs
A critical point in solving inequalities is the need to reverse the inequality sign when multiplying or dividing by a negative number.
In our example, once we have \( -4x < 2 \), we must divide by -4 to solve for \( x \). This means that we need to reverse the inequality sign: \( -4x / -4 > 2 / -4 \).
Therefore, \( x > -1/2 \).
This rule is essential to remember because it ensures that the inequality's direction accurately represents the relationship between the numbers.
In our example, once we have \( -4x < 2 \), we must divide by -4 to solve for \( x \). This means that we need to reverse the inequality sign: \( -4x / -4 > 2 / -4 \).
Therefore, \( x > -1/2 \).
This rule is essential to remember because it ensures that the inequality's direction accurately represents the relationship between the numbers.
Number Line Representation
Once we have solved the inequality, it is useful to represent the solution on a number line.
In our case, \( x > -1/2 \) means that \( x \) can be any number greater than \( -1/2 \).
On the number line, we indicate this solution with an open circle at \( -1/2 \) (to show that \( -1/2 \) itself is not included) and shade all numbers to the right.
This visual representation helps to quickly see the range of solutions.
In our case, \( x > -1/2 \) means that \( x \) can be any number greater than \( -1/2 \).
On the number line, we indicate this solution with an open circle at \( -1/2 \) (to show that \( -1/2 \) itself is not included) and shade all numbers to the right.
This visual representation helps to quickly see the range of solutions.
Other exercises in this chapter
Problem 12
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