Problem 12
Question
Solve for \(x\) : \(\frac{1+\log _{2}(x-4)}{2 \log _{2}(\sqrt{x+3}-\sqrt{x-3})}=1\)
Step-by-Step Solution
Verified Answer
The solution to the given equation is \(x = 5\).
1Step 1: Simplify the Equation
The first step involves simplifying the equation. Since the right-hand side of the equation is 1, multiplying both sides of the equation by the denominator on the left-hand side, we get \(1+\log _{2}(x-4) = 2 \log _{2}(\sqrt{x+3}-\sqrt{x-3})\).
2Step 2: Remove the logarithm
In the next step, we try to isolate the logarithmic term and convert it to exponential form. Rearranging the equation gives \(\log _{2}(x-4) = 2 \log _{2}(\sqrt{x+3}-\sqrt{x-3})-1\). Since \(2 \log_a(b) = \log_a(b^2) \), we can write \(\log _{2}(x-4) = \log_{2} \left((\sqrt{x+3}-\sqrt{x-3})^2\right) - 1\). Now we subtract the value from each side to remove the log giving \(x-4 = (\sqrt{x+3}-\sqrt{x-3})^2 \times 2^{-1}\).
3Step 3: Expand the Square and Simplify
In this step, we expand the square and simplify the equation. Expanding the square gives \(x-4 = (x+3+x-3-2\sqrt{(x+3)(x-3)}) \times 2^{-1}\). Simplifying this gives \(x - 4 = x - 2\sqrt{(x^2-9)}\).
4Step 4: Solve for \( x \)
Rearrange and solve the equation for \( x \). We can square both sides again to remove the square root. Doing this correctly and solving using the quadratic formula will result in \(x = 5, 4\). Since the logarithm is undefined for negative numbers and zero, and the radicand cannot be negative, we must discard the solution \(x = 4\) but keep \(x = 5\), since it satisfies the original equation.
Key Concepts
Logarithmic EquationsIIT JEE PreparationQuadratic Formula
Logarithmic Equations
Logarithmic equations can initially seem daunting, but they can be tackled with some clear strategies.
These equations involve logs, which are crucial in converting multiplication into addition, division into subtraction, and exponentiation into multiplication.
In our example, we have logarithms with base 2. The equation can be simplified by using properties of logarithms such as \( \log_a(b^2) = 2 \log_a(b) \).
This ensures you discard any extraneous solutions.
Solving logarithmic equations effectively prepares students for more advanced mathematics, including calculus and sciences.
These equations involve logs, which are crucial in converting multiplication into addition, division into subtraction, and exponentiation into multiplication.
In our example, we have logarithms with base 2. The equation can be simplified by using properties of logarithms such as \( \log_a(b^2) = 2 \log_a(b) \).
- Always aim to isolate the logarithm: Try to have the log term alone on one side of the equation.
- Convert it to an exponential form: If \( \log_b(a) = c \), then \( b^c = a \). This step helps in removing the logarithm.
This ensures you discard any extraneous solutions.
Solving logarithmic equations effectively prepares students for more advanced mathematics, including calculus and sciences.
IIT JEE Preparation
The IIT JEE is one of the most challenging engineering entrance exams. It tests your understanding of complex concepts and your problem-solving skills.
Here's how you can effectively prepare:
Remember to take regular breaks and maintain a balanced study routine to avoid burnout.
Here's how you can effectively prepare:
- Understand the Syllabus: Familiarize yourself with the topics covered, and make sure to cover each one thoroughly.
- Regular Practice: Solve a variety of problems, including logarithmic equations and quadratics, to be well-prepared.
- Mock Tests: Take timed tests to improve speed and accuracy.
- Analyze Mistakes: Review incorrect answers to understand where you went wrong and focus on those areas.
Remember to take regular breaks and maintain a balanced study routine to avoid burnout.
Quadratic Formula
The quadratic formula is a fundamental tool for solving quadratic equations. These are equations of the form \( ax^2 + bx + c = 0 \).
The roots of the equation can be found using the formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
where \(a\), \(b\), and \(c\) are coefficients.
It's especially useful in IIT JEE preparation, where quick and accurate solutions are vital.
Additionally, double-check whether your solutions satisfy the original conditions, like in the log equations, for a complete answer.
The roots of the equation can be found using the formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
where \(a\), \(b\), and \(c\) are coefficients.
- Discriminant: The term under the square root, \( b^2 - 4ac \), is the discriminant. It determines the nature of the roots.
- If the discriminant is positive, there are two distinct real roots; if zero, one real root; and if negative, two complex roots.
- Ensure all calculations are precise, as small errors can lead to incorrect roots.
It's especially useful in IIT JEE preparation, where quick and accurate solutions are vital.
Additionally, double-check whether your solutions satisfy the original conditions, like in the log equations, for a complete answer.
Other exercises in this chapter
Problem 11
Solve for \(x\) : \(\frac{3}{2} \log _{4}(x+2)^{2}+3=\log _{4}(4-x)^{3}+\log _{4}(6+x)^{3}\)
View solution Problem 11
The value of \(5^{\log _{2} 7}-7^{\log _{2} 5}\) is (a) 5 (b) 0 (c) 7 (d) 2
View solution Problem 12
If \(\log _{10} 2=x\), then \(\log _{10} 5\) is (a) 1 (b) \(1-x\) (c) \(x+1\) (d) \(2 x\)
View solution Problem 12
Find the value of \(\log _{12} 54\), where \(b=\log _{12} 24\).
View solution