Problem 12
Question
Solve a System of Linear Equations by Graphing In the following exercises, solve the following systems of equations by graphing. $$ \left\\{\begin{array}{l} -2 x+3 y=-3 \\ x+y=4 \end{array}\right. $$
Step-by-Step Solution
Verified Answer
The solution is (3, 1).
1Step 1 - Write Equations in Slope-Intercept Form
Rewrite each equation in the form of y = mx + b. For the first equation: \[-2x + 3y = -3\] Add 2x to both sides: \[3y = 2x - 3\] Divide by 3: \[y = \frac{2}{3}x - 1\] For the second equation: \[x + y = 4\] Subtract x from both sides: \[y = -x + 4\]
2Step 2 - Graph the First Equation
Graph y = \(\frac{2}{3}x - 1\) on a coordinate plane. Start by plotting the y-intercept at (0, -1). Then, use the slope \(\frac{2}{3}\) to find another point by going up 2 units and right 3 units.
3Step 3 - Graph the Second Equation
Graph y = -x + 4 on the same coordinate plane. Start by plotting the y-intercept at (0, 4). Then, use the slope -1 to find another point by going down 1 unit and right 1 unit.
4Step 4 - Find the Intersection Point
Identify the point where the two lines intersect. This point is the solution to the system of equations. Check the graph to see where the lines \(y = \frac{2}{3}x - 1\) and \(y = -x + 4\) intersect.
5Step 5 - Verify the Solution
Verify the coordinates of the intersection point by substituting them back into the original equations to ensure they satisfy both equations.
Key Concepts
linear equationsslope-intercept formgraphing techniquesintersection point
linear equations
Linear equations are mathematical expressions that represent straight lines when graphed on a coordinate plane. These equations are typically written in the form \(ax + by = c\), where \(a\), \(b\), and \(c\) are constants, and \(x\) and \(y\) are variables. Linear equations have two main characteristics: the line is straight, and it has no exponents higher than 1 for any variable.
In solving systems of linear equations, you will often be working with more than one linear equation. The goal is to find a common solution that satisfies all the involved equations.
In solving systems of linear equations, you will often be working with more than one linear equation. The goal is to find a common solution that satisfies all the involved equations.
slope-intercept form
The slope-intercept form of a linear equation is \(y = mx + b\). In this format:
Using the slope-intercept form is very helpful for graphing because it allows you to quickly identify the y-intercept and slope, enabling you to sketch the line more easily.
- 'm' represents the slope of the line
- 'b' represents the y-intercept, which is where the line crosses the y-axis.
Using the slope-intercept form is very helpful for graphing because it allows you to quickly identify the y-intercept and slope, enabling you to sketch the line more easily.
graphing techniques
Graphing linear equations is a visual way to find solutions. Here are some steps to help you:
Accurate graphing is essential for solving systems of linear equations because the intersection point gives the solution. Remember to label points clearly and use a ruler for straight lines.
- Start with the y-intercept: This is where the line crosses the y-axis.
- Use the slope to find other points: The slope 'm' tells you how to move from the y-intercept. If \(m = \frac{2}{3}\), go up 2 units and right 3 units from the y-intercept.
- Draw the line: Connect the points with a straight line.
- Repeat for additional equations: If dealing with a system of equations, graph the other lines on the same coordinate plane.
Accurate graphing is essential for solving systems of linear equations because the intersection point gives the solution. Remember to label points clearly and use a ruler for straight lines.
intersection point
The intersection point of two lines on a graph is where the lines cross. This point represents the common solution to both equations in a system of linear equations. To identify the intersection point:
For example, if the lines \(y = \frac{2}{3}x - 1\) and \(y = -x + 4\) intersect at point (3,1), then 3 is the value of x and 1 is the value of y that satisfy both equations. It's always a good idea to verify this by substituting back into the original equations to confirm they hold true.
- Graph each equation on the same coordinate plane.
- Look for the point where the lines meet.
For example, if the lines \(y = \frac{2}{3}x - 1\) and \(y = -x + 4\) intersect at point (3,1), then 3 is the value of x and 1 is the value of y that satisfy both equations. It's always a good idea to verify this by substituting back into the original equations to confirm they hold true.
Other exercises in this chapter
Problem 10
Solve a System of Linear Equations by Graphing In the following exercises, solve the following systems of equations by graphing. $$ \left\\{\begin{array}{l} -x+
View solution Problem 11
Solve a System of Linear Equations by Graphing In the following exercises, solve the following systems of equations by graphing. $$ \left\\{\begin{array}{l} -3
View solution Problem 13
Solve a System of Linear Equations by Graphing In the following exercises, solve the following systems of equations by graphing. $$ \left\\{\begin{array}{l} y=x
View solution Problem 14
Solve a System of Linear Equations by Graphing In the following exercises, solve the following systems of equations by graphing. $$ \left\\{\begin{array}{l} y=x
View solution