Problem 12
Question
Simplify the expression. $$ 7(3 a+2)+5 $$
Step-by-Step Solution
Verified Answer
The simplified form of the given expression is \(21a + 19\).
1Step 1: Apply distributive property
First, apply the distributive property in the term \(7(3a + 2)\). This involves multiplying 7 with each term inside the bracket. So, \(7(3a + 2)\) = \(21a + 14\).The equation becomes \(21a + 14 + 5\).
2Step 2: Combine the constant terms
Next, combine the constant terms in the equation. So, you add \(14 + 5\) to get 19. The final simplified expression is \(21a + 19\).
Key Concepts
Distributive PropertyAlgebraic ExpressionsCombining Like Terms
Distributive Property
The distributive property is an essential tool in algebra that allows us to simplify expressions more easily. It involves multiplying each term inside a bracket by a factor outside the bracket. For example, in the expression \(7(3a + 2)\), the distributive property tells us to multiply 7 by each of the terms inside the parentheses: 3a and 2. Doing this gives us \(7 \times 3a\) and \(7 \times 2\).
Here's what happens step by step:
This method is very powerful and can be used to break down more complex expressions, making them easier to manage. Remember that this property is not only useful for numbers but also for algebraic expressions. Once you get used to it, the distributive property becomes your key to unlocking simplified forms of complicated expressions.
Here's what happens step by step:
- First, multiply 7 by 3a to get 21a.
- Next, multiply 7 by 2 to get 14.
This method is very powerful and can be used to break down more complex expressions, making them easier to manage. Remember that this property is not only useful for numbers but also for algebraic expressions. Once you get used to it, the distributive property becomes your key to unlocking simplified forms of complicated expressions.
Algebraic Expressions
An algebraic expression is a mathematical phrase that can contain numbers, variables, and operation symbols. In algebra, we often work with these expressions to find solutions or simplify them. For instance, in the original exercise where we simplify \(7(3a + 2) + 5\), the expression includes:
Algebraic expressions form the foundation in algebra, allowing us to express mathematical ideas clearly and concisely. Getting comfortable with them is a stepping stone to mastering more advanced mathematical concepts.
- The number 7
- The variable term 3a
- The constant number 2
- Another constant number 5
Algebraic expressions form the foundation in algebra, allowing us to express mathematical ideas clearly and concisely. Getting comfortable with them is a stepping stone to mastering more advanced mathematical concepts.
Combining Like Terms
Combining like terms is another fundamental concept when simplifying algebraic expressions. Like terms are terms in an expression that have the same variable raised to the same power. In our exercise, the expression after applying the distributive property became \(21a + 14 + 5\).
Here, 14 and 5 are the like terms because they are constants (they have no variables attached). The process to combine them is straightforward:
By combining like terms, we reduce the number of terms in the expression, making it simpler and more concise. This is a crucial step in the simplification process, and it helps ensure that we end up with the most compact form of an expression. This technique, paired with others like distributing, forms a powerful set of tools students use in solving and simplifying algebraic expressions.
Here, 14 and 5 are the like terms because they are constants (they have no variables attached). The process to combine them is straightforward:
- Add 14 and 5 together to get 19.
By combining like terms, we reduce the number of terms in the expression, making it simpler and more concise. This is a crucial step in the simplification process, and it helps ensure that we end up with the most compact form of an expression. This technique, paired with others like distributing, forms a powerful set of tools students use in solving and simplifying algebraic expressions.
Other exercises in this chapter
Problem 12
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