Problem 12
Question
Simplify each of the following expressions without using a calculator. $$11 \sqrt{100}$$
Step-by-Step Solution
Verified Answer
The simplified form of the expression is 110.
1Step 1: Recognize the Square Root
First, identify the number inside the square root. In this case, it's 100. We need to find the square root of 100.
2Step 2: Calculate the Square Root
The square root of 100 is the number that, when multiplied by itself, gives 100. This number is 10 because \( 10 \times 10 = 100 \). Hence, \( \sqrt{100} = 10 \).
3Step 3: Simplify the Expression
Now that we know \( \sqrt{100} = 10 \), substitute 10 back into the expression \( 11 \sqrt{100} \), which becomes \( 11 \times 10 \).
4Step 4: Multiply
Finally, perform the multiplication: \( 11 \times 10 = 110 \). This is the simplified form of the expression.
Key Concepts
Understanding Square RootsMultiplication BasicsPrealgebra Concepts in Simplification
Understanding Square Roots
Square roots can seem tricky, but they're actually quite simple with some practice. A square root asks the question: "What number multiplies by itself to give this value?" Square roots are represented by the symbol \( \sqrt{} \). If you see \( \sqrt{100} \), it means we need a number that, when multiplied by itself, equals 100.
For most perfect square numbers like 100, 64, or 36, their roots are integers. So, \( \sqrt{100} = 10 \) because \( 10 \times 10 = 100 \). Knowing the basic square roots of numbers like 1, 4, 9, 16, and so on, will help you simplify expressions quickly.
For most perfect square numbers like 100, 64, or 36, their roots are integers. So, \( \sqrt{100} = 10 \) because \( 10 \times 10 = 100 \). Knowing the basic square roots of numbers like 1, 4, 9, 16, and so on, will help you simplify expressions quickly.
- Remember the perfect squares (e.g., 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, etc.)
- To find a square root, determine which integer multiplied by itself equals the given number.
Multiplication Basics
Multiplication is one of the fundamental operations in prealgebra. It's like repeated addition. For example, \( 11 \times 10 \) means adding 11 together 10 times. The important thing about multiplication is recognizing patterns and shortcuts.
Breaking numbers into smaller, more manageable parts can help. For example, to multiply 11 and 10, you can think
of 11 as \( 10 + 1 \). Using
the distributive property, you can see it as:
Breaking numbers into smaller, more manageable parts can help. For example, to multiply 11 and 10, you can think
of 11 as \( 10 + 1 \). Using
the distributive property, you can see it as:
- \( 11 \times 10 = (10 + 1) \times 10 = 10\times 10 + 1 \times 10 = 100 + 10 = 110 \)
Prealgebra Concepts in Simplification
Prealgebra involves basic arithmetic skills which are foundational for understanding algebra. When you simplify expressions, you apply these skills to make complex problems more manageable. In the exercise \( 11 \sqrt{100} \), we used both square roots and multiplication concepts.
The flow looks like this:
The flow looks like this:
- Find the square root of 100 (which is 10).
- Replace the square root in the expression with 10.
- Multiply 11 by 10 to get 110.
Other exercises in this chapter
Problem 11
Write each number as a fraction or a mixed number. Do not reduce your answers. $$9.009$$
View solution Problem 11
Find each of the following sums. (Add.) $$5.0003+6.78+0.004$$
View solution Problem 12
Perform each of the following divisions. [Examples \(1-5]\) $$31.48 \div 4$$
View solution Problem 12
Simplify each square root, then combine if possible. Assume all variables represent positive numbers. $$\sqrt{12}+\sqrt{27}$$
View solution