Problem 12
Question
Represent each given condition using a single variable, \(x\). The area of the circle is \(25 \pi\) square kilometers. Find its radius.
Step-by-Step Solution
Verified Answer
The radius of the circle is 5 kilometers.
1Step 1: Identify the Formula for the Circle's Area
The area of a circle is given by the formula: \( A = \pi r^2 \), where \( r \) is the radius.
2Step 2: Set the Formula Equal to the Given Area
Given that the area is \( 25 \pi \), set the formula equal to the given area: \( \pi r^2 = 25 \pi \).
3Step 3: Simplify the Equation
Divide both sides of the equation by \( \pi \) to eliminate it from the equation, resulting in \( r^2 = 25 \).
4Step 4: Solve for the Radius
To find \( r \), take the square root of both sides of the equation: \( r = \sqrt{25} \).
5Step 5: Calculate the Value of the Radius
Simplify \( r = \sqrt{25} \) to find \( r = 5 \).
Key Concepts
Circle Area FormulaSolving for RadiusSimplifying Equations
Circle Area Formula
When dealing with circles, one of the most fundamental ideas is how to calculate the area. The formula for this is \[ A = \pi r^2 \] where \( A \) represents the area, \( \pi \) is a constant approximately equal to 3.14159, and \( r \) is the radius of the circle.
This simple equation allows us to calculate how much space is contained within the boundary of a circle. You can think of the radius \( r \) as the distance from the center of the circle to any point along its edge. Understanding this formula is key to solving many problems involving circles.
This simple equation allows us to calculate how much space is contained within the boundary of a circle. You can think of the radius \( r \) as the distance from the center of the circle to any point along its edge. Understanding this formula is key to solving many problems involving circles.
- Reminder: Always ensure you understand what each symbol in a formula represents.
- Know that \( \pi \) is a universal constant in circle calculations.
Solving for Radius
Solving for the radius of a circle is often necessary when you know the area. To find the radius from the circle's area, the circle area formula is rearranged. Given the formula \( A = \pi r^2 \), you can solve for \( r \) when \( A \) is known. This process involves setting the area you know equal to the formula and isolating \( r \).
- For example, start with the formula: \( \pi r^2 = 25\pi \).
- Then, divide both sides by \( \pi \) to simplify: \( r^2 = 25 \).
- Next, take the square root of both sides to isolate \( r \): \( r = \sqrt{25} \).
Simplifying Equations
Simplifying equations is a useful skill in mathematics that helps make equations easier to work with and solve. It involves manipulating the equation in ways that make it less complex without changing its fundamental meaning.
In our scenario, you start by having an equation with the area of the circle set equal to the formula: \( \pi r^2 = 25 \pi \). To simplify, remove common factors from both sides. Since \( \pi \) appears on both sides of the equation, you can divide through by \( \pi \) to simplify it to \( r^2 = 25 \). This eliminates the \( \pi \), leaving us with a much simpler equation to solve for \( r \).
In our scenario, you start by having an equation with the area of the circle set equal to the formula: \( \pi r^2 = 25 \pi \). To simplify, remove common factors from both sides. Since \( \pi \) appears on both sides of the equation, you can divide through by \( \pi \) to simplify it to \( r^2 = 25 \). This eliminates the \( \pi \), leaving us with a much simpler equation to solve for \( r \).
- Look for common terms on both sides of the equation when simplifying.
- Remember that simplifying equations makes it easier and faster to find solutions.
Other exercises in this chapter
Problem 11
Solve each equation. $$ 2 x(x+12)=0 $$
View solution Problem 12
Factor each trinomial completely. $$ x^{2}+18 x+81 $$
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Factor each trinomial by grouping. Exercises 9 through 12 are broken into parts to help you get started. \(6 x^{2}-13 x+5\) a. Find two numbers whose product is
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Find the \(G C F\) for each list. $$ p^{7} q, p^{8} q^{2}, p^{9} q^{3} $$
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