Problem 12
Question
Multiply. $$-12 m(11 m-4)$$
Step-by-Step Solution
Verified Answer
The short answer is \(-12m(11m - 4) = -132m^2 + 48m\).
1Step 1: Identify the monomial and binomial
In this exercise, we have a monomial, \(-12m\), and a binomial, \(11m - 4\).
2Step 2: Distributive Property
Now, we will apply the distributive property by multiplying the monomial \(-12m\) by each term of the binomial \(11m - 4\).
3Step 3: Multiply the first term of the binomial
First, we'll multiply the monomial \(-12m\) by the first term of the binomial, \(11m\):
\[
(-12m) \times (11m).
\]
Now we multiply the coefficients, and multiply the variables: \((-12) \times (11) = -132\) and \(m \times m = m^2\). So, we get:
\[
(-12m) \times (11m) = -132m^2.
\]
4Step 4: Multiply the second term of the binomial
Next, we'll multiply the monomial \(-12m\) by the second term of the binomial, \(-4\):
\[
(-12m) \times (-4).
\]
Now we multiply the coefficients: \((-12) \times (-4) = 48\), and we keep the variable \(m\). So, we get:
\[
(-12m) \times (-4) = 48m.
\]
5Step 5: Combine the results
Now that we've multiplied the monomial \(-12m\) by each term of the binomial \(11m - 4\), we can combine our results:
\[
-12m(11m - 4) = -132m^2 + 48m.
\]
Thus, the final answer is \(-132m^2 + 48m\).
Key Concepts
MonomialBinomialDistributive PropertyAlgebraic Expressions
Monomial
A **monomial** is a type of algebraic expression that consists of a single term. It's composed of numbers, variables, or both, multiplied together. In simple terms, it's like having one package, whether it's a number, a letter, or both in a multiplication dance. For example, in our problem, the monomial is \(-12m\).
If you break it down:
If you break it down:
- \(-12\) is the coefficient, which is the numerical part of the monomial.
- \(m\) is the variable, which can represent various numbers.
Binomial
A **binomial** is an algebraic expression that consists of two terms separated by a plus or minus sign. It's like having two different packages tied together. In our exercise, the binomial is \(11m - 4\).
Here's what it looks like:
Here's what it looks like:
- The first term is \(11m\) which consists of the coefficient \(11\) and the variable \(m\).
- The second term is \(-4\) which is a constant because it doesn’t have any variables.
Distributive Property
The **Distributive Property** is a rule in algebra that allows us to multiply a single term by a sum or difference within a parenthesis. It's like the rule that tells us how to distribute chocolate evenly at a party! 🌟
In our problem, we have to multiply the monomial \(-12m\) by each term in the binomial \(11m - 4\). The distributive property lets us do that:
Simply distribute the monomial to both terms inside the binomial:
In our problem, we have to multiply the monomial \(-12m\) by each term in the binomial \(11m - 4\). The distributive property lets us do that:
Simply distribute the monomial to both terms inside the binomial:
- First, multiply \(-12m\) with \(11m\).
- Next, multiply \(-12m\) with \(-4\).
Algebraic Expressions
**Algebraic expressions** are mathematical phrases that include numbers, variables, and operations (such as addition and multiplication). They are like sentences but written in the language of math! Expressions can range from simple to complex, involving various parts, such as monomials and binomials.
Here's what makes up an algebraic expression:
Here's what makes up an algebraic expression:
- **Variables**: symbols like \(x\) or \(m\) that stand in for numbers.
- **Coefficients**: numbers that multiply variables, such as \(-12\) in \(-12m\).
- **Constants**: fixed numbers such as \(-4\).
Other exercises in this chapter
Problem 11
Evaluate using the rules of exponents. $$6^{0}+\left(-\frac{1}{2}\right)^{-5}$$
View solution Problem 12
Divide. $$\frac{-54 j^{5}+30 j^{3}-9 j^{2}+15}{9 j}$$
View solution Problem 12
Determine whether each is a monomial, a binomial, or a trinomial. $$v^{4}+7 v^{2}+6$$
View solution Problem 12
Evaluate using the rules of exponents. $$\left(\frac{1}{4}\right)^{-2}+\left(\frac{1}{4}\right)^{0}$$
View solution