Problem 12
Question
List the transformations needed to transform the graph of \(h(x)=2^{x}\) into the graph of the given function. $$g(x)=-\left(2^{x}\right)$$
Step-by-Step Solution
Verified Answer
Answer: To transform the graph of h(x) = 2^x into the graph of g(x) = - (2^x), we need to flip the graph of h(x) about the x-axis.
1Step 1: Identify the base function and its transformation
The base function is h(x) = 2^x. The function we want to transform it into is g(x) = - (2^x). We can see that the transformation involves negating the output of the base function h(x).
2Step 2: Describe the transformation
Since the function g(x) is the negation of h(x), the transformation required to get the graph of g(x) from the graph of h(x) is flipping the graph about the x-axis. This means that all the points on the graph of h(x) will have their y-coordinates negated, resulting in the flipped graph.
3Step 3: List the transformations
To better visualize this, we can list all the individual transformations needed. In this case, there is only one transformation:
1. Flip the graph of h(x) about the x-axis.
These steps show how to transform the graph of h(x) = 2^x into the graph of g(x) = - (2^x) by listing the transformations required to achieve this.
Key Concepts
flipping graphsexponential functionsreflection over x-axis
flipping graphs
Flipping graphs is a type of transformation where the graph of a function is inverted to form a mirror image across a specified line, such as the x-axis or y-axis. In mathematics, this process is referred to as a reflection. When you flip a graph, the points on the graph change position based on the line of reflection.
A flipped graph can look quite different from the original, though the shape remains the same. This transformation is particularly useful for visualizing how a graph behaves when reflected.
Some key things to remember about flipping graphs:
- The basic shape of the graph doesn't change; it only appears as a mirror image.
- Flipping can occur over either the x-axis or y-axis, depending on the transformation.
- This transformation affects the output values (y-values) of the function.
exponential functions
Exponential functions are a class of mathematical functions that involve the raising of a constant, known as the base, to a variable exponent. The typical form of an exponential function is given by \(f(x) = a^x\), where \(a>0\) and \(a eq 1\). These functions are characterized by their rapid rate of growth or decay, depending on whether the base \(a\) is greater or less than one. Exponential functions have several important properties:
- They are continuous and smooth, without any jumps or breaks.
- The graph of an exponential growth function \(f(x)=a^x\) with \(a>1\) rises upwards from left to right.
- Conversely, if \(0
- The y-intercept of \(f(x) = a^x\) is always at point (0,1), since \(a^0 = 1\).
reflection over x-axis
Reflection over the x-axis is a specific graph transformation where each point of the graph is mirrored across the x-axis. This results in the inversion of the graph, transforming each y-value into its negative counterpart, while x-values remain unchanged.For instance, if you start with a function \(h(x) = 2^x\), reflecting it over the x-axis would yield \(g(x) = -2^x\). This transformation changes:
- Positive y-values to negative y-values.
- Negative y-values to positive y-values.
- The graph makes a vertical flip over the x-axis.
Other exercises in this chapter
Problem 12
In Exercises \(11-16,\) let \(u=\ln x\) and \(v=\ln y .\) Write the given expression in terms of u and v. For example, $$\ln x^{3} y=\ln x^{3}+\ln y=3 \ln x+\ln
View solution Problem 12
Translate the given logarithmic statement into an equivalent exponential statement. $$\ln s=r$$
View solution Problem 13
Compute and simplify. $$\left(x^{1 / 2}+y^{1 / 2}\right)\left(x^{1 / 2}-y^{1 / 2}\right)$$
View solution Problem 13
In Exercises \(11-16,\) let \(u=\ln x\) and \(v=\ln y .\) Write the given expression in terms of u and v. For example, $$\ln x^{3} y=\ln x^{3}+\ln y=3 \ln x+\ln
View solution