Problem 12
Question
Let \(A\) and \(B\) be finite sets such that \(A \subseteq B,|A|=b,|B|=a+b .\) Find the cardinality of each set. \(A \cup B\)
Step-by-Step Solution
Verified Answer
The cardinality of the union of sets A and B, denoted as \(|A \cup B|\), is equal to the cardinality of set B. Since \( |B| = a + b\), the cardinality of A ∪ B is \(a + b\).
1Step 1: Determine A is a subset of B
We are given that \(A \subseteq B\), meaning that all elements of set A are also in set B.
Step 2: Analyze the Cardinalities
2Step 2: Determine the cardinalities of A and B
The cardinalities of the sets A and B are given as follows:
- |A| = b
- |B| = a + b
Step 3: Determine the Union Set Cardinality
3Step 3: Determine the cardinality of A ∪ B
As A is a subset of B i.e. \(A \subseteq B\), all elements of set A are already in set B. So, the union of sets A and B will not have any additional elements from A. Thus, the cardinality of A ∪ B will be the same as the cardinality of B.
So, we have \(|A \cup B| = |B|\).
Step 4: Conclusion
4Step 4: Find the cardinality of A ∪ B
Using the earlier determined relationship for the cardinalities, we have:
\( |A \cup B| = |B|\)
Since |B| = a + b, the required cardinality is:
\( |A \cup B| = a + b\)
Key Concepts
Finite SetsSubsetCardinalityUnion of Sets
Finite Sets
When we talk about finite sets in set theory, we are referring to sets that have a limited number of distinct elements. Unlike infinite sets, which go on endlessly, finite sets come with a specific count of members. This makes them easier to analyze and work with since their size, known as "cardinality," is well-defined.
For example, consider a set like \( A = \{1, 2, 3\} \). This set is finite because we can enumerate its elements, and more importantly, we can count them. In this case, there are three elements, so the cardinality \(|A|\) is 3. Finite sets are a foundational concept in mathematics, especially in problems where understanding the size and limits of a set is crucial.
For example, consider a set like \( A = \{1, 2, 3\} \). This set is finite because we can enumerate its elements, and more importantly, we can count them. In this case, there are three elements, so the cardinality \(|A|\) is 3. Finite sets are a foundational concept in mathematics, especially in problems where understanding the size and limits of a set is crucial.
Subset
In set theory, a subset is a set that contains only elements found in another set, which is referred to as the "superset." If set \( A \) is a subset of set \( B \), denoted as \( A \subseteq B \), all elements of \( A \) are also elements of \( B \). However, \( B \) might have additional elements not found in \( A \).
There are a few key points to remember about subsets:
There are a few key points to remember about subsets:
- Every set is a subset of itself. Therefore, \( A \subseteq A \).
- The empty set is a subset of every set, regardless of the size or contents of the set.
Cardinality
Cardinality is a concept that denotes the number of elements in a set. In simpler terms, it indicates the "size" of the set. For finite sets, the cardinality is a non-negative integer representing how many unique elements the set contains. Knowing the cardinality of a set is crucial when performing operations like union or intersection.
In our scenario, we are given the cardinality of two sets:
In our scenario, we are given the cardinality of two sets:
- \(|A| = b\)
- \(|B| = a + b\)
Union of Sets
The union of two sets is a fundamental operation in set theory that combines all elements from both sets, without repeating any elements. The union of sets \( A \) and \( B \) is denoted by \( A \cup B \).
For example, if \( A = \{1, 2, 3\} \) and \( B = \{3, 4, 5\} \), then \( A \cup B = \{1, 2, 3, 4, 5\} \). Notice that the element "3," which is present in both \( A \) and \( B \), appears only once in the union.
In our exercise, since \( A \subseteq B \), every element in \( A \) is already in \( B \). Therefore, the union \( A \cup B \) essentially recreates set \( B \), meaning the cardinality \(|A \cup B|\) is equal to \(|B|\), which is \(a + b\). This property simplifies calculations and is a vital technique in problems involving subsets and unions.
For example, if \( A = \{1, 2, 3\} \) and \( B = \{3, 4, 5\} \), then \( A \cup B = \{1, 2, 3, 4, 5\} \). Notice that the element "3," which is present in both \( A \) and \( B \), appears only once in the union.
In our exercise, since \( A \subseteq B \), every element in \( A \) is already in \( B \). Therefore, the union \( A \cup B \) essentially recreates set \( B \), meaning the cardinality \(|A \cup B|\) is equal to \(|B|\), which is \(a + b\). This property simplifies calculations and is a vital technique in problems involving subsets and unions.
Other exercises in this chapter
Problem 11
Find \(|A \cap B|\) if \(|A|=2 a,|B|=a,\) and \(|A \cup B|=2 a+b\).
View solution Problem 12
Using the sets \(A=\\{a, b, e, h\\}, B=\\{b, c, e, f, h |, C=\\{c, d, f, g\\}, \text { and }\) \(U=\\{a, \ldots, h\\},\) find the binary representation of each
View solution Problem 12
Let \(A=\\{a, e, f, g, i\rangle, B=\\{b, d, e, g, h\\}, C=\\{d, e, f, h, i\\},\) and \(U=\\{a, b, \ldots, k\\}\) Find each set. $$ (A \cap B)-C $$
View solution Problem 12
Using the sets \(A=\\{a, b, e, h\\}, B=\\{b, c, e, f, h\\}, C=\\{c, d, f, g\\},\) and \(U=\\{a, \ldots, h\\},\) find the binary representation of each set. \(A
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