Problem 12
Question
In Exercises, sketch the graph of the function. $$ f(x)=e^{2 x} $$
Step-by-Step Solution
Verified Answer
The function \(f(x) = e^{2x}\) being an exponential function has a specific shape. It passes the point (0, 1), inclines as \(x\) increases, and the \(y\)-axis is its horizontal asymptote. This can be verified by calculating the function's values at various points and plotting them.
1Step 1: Understanding the exponential function
Exponential functions of the form \(f(x) = a^x\), where \(a\) is a positive real number not equal to 1, have a characteristic shape. They always pass through the point (0, 1) and, in the case where \(a > 1\) , they increase, becoming steeper as \(x\) increases.
2Step 2: Calculate the function's value at various points
Calculate the function's value at a few key points for sketching the graph. Some relevant points would be \(x = -2, -1, 0, 1, 2\). Then we compute the respective \(f(x)\) for those values: \(f(-2) = e^{-4}\), \(f(-1) = e^{-2}\), \(f(0) = e^0 = 1\), \(f(1) = e^2\), \(f(2) = e^4\).
3Step 3: Plotting the function
Now we plot these calculated points along with the defining characteristics of the exponential function to accurately draw the function. The function should pass through the points (0,1), inclines as \(x\) increases and have an asymptote at \(y=0\)
Key Concepts
Graphing FunctionsFunction BehaviorExponential Growth
Graphing Functions
When graphing exponential functions like \( f(x) = e^{2x} \), it's important to understand their typical characteristics. Graphing involves plotting the function on a coordinate plane to visually represent its behavior. In the case of our function, it has an exponential form, meaning it rises sharply with increasing \( x \). This sharp rise is a hallmark of exponential growth.Graphs of exponential functions usually start below the x-axis for negative \( x \), cross the y-axis at some value, and continue upwards as \( x \) increases. These functions also have a horizontal asymptote, which is an invisible line that the function gets closer to but never actually touches, typically along the x-axis (or \( y = 0 \)).To sketch this function, you should:
- Identify key points: For \( f(x) = e^{2x} \), the graph passes through (0, 1), since \( e^0 = 1 \).
- Find additional points by calculating \( f(x) \) for several \( x \) values such as \( -2, -1, 0, 1, 2 \).
- Draw the graph starting from the left, moving upwards sharply, and approaching the horizontal asymptote without touching it.
Function Behavior
The behavior of an exponential function is defined by how it changes as the input \( x \) changes. For \( f(x) = e^{2x} \), this change is exponential, meaning its rate of increase grows faster as \( x \) becomes larger.Some key behavioral aspects of exponential functions include:
- **Monotonically increasing:** This function always increases because the base \( e \) (approximately 2.718) is greater than 1. As \( x \) increases, \( f(x) \) will never decrease.
- **Smooth curve:** The graph is continuous and smooth, with no breaks, jumps, or abrupt changes.
- **Y-intercept:** The function crosses the y-axis at \( y=1 \) because \( f(0) = e^0 = 1 \).
Exponential Growth
Exponential functions like \( f(x) = e^{2x} \) represent exponential growth, a powerful concept used in various scientific fields and real-life scenarios. This growth is characterized by the quantity doubling quickly over equal intervals of time.In our function:
- \( e^{2x} \) indicates very rapid growth since the exponent is positive and multi-fold (twice the regular \( e^x \)). It grows even faster compared to simpler exponential functions like \( e^x \).
- This rapid growth is why exponential functions are frequently used to model populations, financial predictions, and natural processes, where quantities grow at increasing rates.
Other exercises in this chapter
Problem 11
After \(t\) years, the remaining mass \(y\) (in grams) of 16 grams of a radioactive element whose half-life is 30 years is given by \(y=16\left(\frac{1}{2}\righ
View solution Problem 12
In Exercises, find the derivative of the function. $$ y=4 x^{3} e^{-x} $$
View solution Problem 12
After \(t\) years, the remaining mass \(y\) (in grams) of 23 grams of a radioactive element whose halflife is 45 years is given by \(y=23\left(\frac{1}{2}\right
View solution Problem 13
In Exercises, find the derivative of the function. $$ f(x)=\frac{2}{\left(e^{x}+e^{-x}\right)^{3}} $$
View solution