Problem 12
Question
In Exercises \(9-12,\) write the system of linear equations represented by the augmented matrix. Use \(x, y, z,\) and, if necessary, \(w, x, y,\) and \(z,\) for the variables. \(\left[\begin{array}{rrrr|r}4 & 1 & 5 & 1 & 6 \\ 1 & -1 & 0 & -1 & 8 \\ 3 & 0 & 0 & 7 & 4 \\ 0 & 0 & 11 & 5 & 3\end{array}\right]\)
Step-by-Step Solution
Verified Answer
The system of linear equations that the given augmented matrix represents is: \n1. \(4x + y + 5z + w = 6\)\n2. \(x - y - w = 8\)\n3. \(3x + 7w = 4\)\n4. \(11z + 5w = 3\)
1Step 1: Identify the Variables
The variables for this system of equations are \(x, y, z, w\). This is determined by the number of columns in the coefficient matrix (four in this case). The final column represents the constants on the right-hand side of the equation.
2Step 2: Formulate the linear equations
Formulate the linear equations from the augmented matrix using the variables. Each row represents a separate equation in the system. Translate each element of the rows into their respective coefficients. The equations will be as follows: \n1. \(4x + y + 5z + w = 6\)\n2. \(x - y - w = 8\)\n3. \(3x + 7w = 4\)\n4. \(11z + 5w = 3\)
3Step 3: Recap the System of Linear Equations
The system of linear equations that the given augmented matrix represents is: \n1. \(4x + y + 5z + w = 6\)\n2. \(x - y - w = 8\)\n3. \(3x + 7w = 4\)\n4. \(11z + 5w = 3\)
Key Concepts
Augmented MatrixMatrices in AlgebraSolving Linear Equations
Augmented Matrix
An augmented matrix is a powerful tool used to simplify and solve systems of linear equations. It combines the coefficients of variables and the constants on the right-hand side into one convenient display.
Imagine it like this:
This setup is especially useful when applying matrix operations like row reduction to find solutions.
Imagine it like this:
- We organize the coefficients of each variable in the system into rows and columns.
- The rightmost column contains the constants from every equation.
This setup is especially useful when applying matrix operations like row reduction to find solutions.
Matrices in Algebra
Matrices are essential in modern algebra and mathematics. They serve multiple purposes, but in solving systems of linear equations, they are indispensable. Here’s how they function in this context:
In practical applications beyond just linear equations, such as computer graphics, network theory, and data analysis, matrices provide a robust framework for managing complex information efficiently.
- Each matrix represents a vector of equations, allowing for structured manipulation.
- The rows of a matrix can be viewed as individual linear equations, with their positions aiding in systematic transformation.
- Column positions reflect different variables involved in equations.
In practical applications beyond just linear equations, such as computer graphics, network theory, and data analysis, matrices provide a robust framework for managing complex information efficiently.
Solving Linear Equations
Solving a system of linear equations involves finding the values of variables that satisfy all the given equations simultaneously. A popular approach uses matrices to organize the work.
Here’s a basic rundown of how solving typically proceeds:
Here’s a basic rundown of how solving typically proceeds:
- Write the system of equations in augmented matrix form.
- Perform row operations (like swapping, multiplying, or adding rows) to transform the matrix into a simpler form, often called row-echelon form or reduced row-echelon form.
- Once the matrix is simplified, interpret it back into equations to find the variable values.
Other exercises in this chapter
Problem 12
find the products \(A B\) and \(B A\) to determine whether \(B\) is the multiplicative inverse of \(A\). $$ A=\left[\begin{array}{rrrr} 1 & -2 & 1 & 0 \\ 0 & 1
View solution Problem 12
Use Gaussian elimination to find the complete solution to each system of equations, or show that none exists. $$\begin{aligned}&2 w-x+3 y+z=0\\\&3 w+2 x+4 y-z=0
View solution Problem 13
In Exercises \(9-16,\) find: a. \(A+B\) b. \(A-B\) c. \(-4 A\) d. \(3 A+2 B\) $$ A=\left[\begin{array}{r} 2 \\ -4 \\ 1 \end{array}\right], \quad B=\left[\begin{
View solution Problem 13
Use Cramer's rule to solve each system or to determine that the system is inconsistent or contains dependent equations. $$ \begin{array}{r}12 x+3 y=15 \\\2 x-3
View solution