Problem 12
Question
In Exercises \(1-12,\) match the equation with the surface it defines. Also, identify each surface by type (paraboloid, ellipsoid, etc.). The surfaces are labeled ( a \(-(1)\) . $$9 x^{2}+4 y^{2}+2 z^{2}=36$$
Step-by-Step Solution
Verified Answer
The surface is an ellipsoid.
1Step 1: Identify Standard Form
The given equation is \(9x^2 + 4y^2 + 2z^2 = 36\). To identify the surface type, we compare it to the standard form of an ellipsoid, which is \(\frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1\).
2Step 2: Simplify the Equation
Simplify the given equation by dividing all terms by 36, resulting in \(\frac{x^2}{4} + \frac{y^2}{9} + \frac{z^2}{18} = 1\).
3Step 3: Interpret the Standard Form
Now, the equation \(\frac{x^2}{4} + \frac{y^2}{9} + \frac{z^2}{18} = 1\) is in the standard form for an ellipsoid. This confirms that the surface is an ellipsoid.
Key Concepts
Conic SectionsSurface IdentificationEquation Simplification
Conic Sections
Conic sections are curves obtained by intersecting a cone with a plane. There are four classic types: circles, ellipses, parabolas, and hyperbolas. When we're dealing with three-dimensional shapes, these basics extend into surfaces such as ellipsoids, paraboloids, and hyperboloids. Each type has a distinct equation form that can help us identify them.
In this exercise, the primary aim is to match the given equation with its proper surface type using these concepts. Understanding conic sections lays the groundwork for understanding more complex three-dimensional shapes that are often encountered in multivariable calculus.
In this exercise, the primary aim is to match the given equation with its proper surface type using these concepts. Understanding conic sections lays the groundwork for understanding more complex three-dimensional shapes that are often encountered in multivariable calculus.
- Circles are special types of ellipses where the two axes are equal, expressed by \(x^2 + y^2 = r^2\).
- Ellipses take the form \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\) when centered at the origin.
- Parabolas are represented by equations like \(y = ax^2\) or \(x = ay^2\).
- Hyperbolas have forms such as \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\).
Surface Identification
Identifying a surface through its equation is an essential skill in geometry and calculus. This exercise provides us with the ellipsoid equation, recognizable by its standard form comparison.
Ellipsoids resemble stretched spheres, and their general equation is \(\frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1\). To successfully identify a given equation as representing an ellipsoid, the task involves transforming or simplifying it into this recognizable standard form.
Ellipsoids resemble stretched spheres, and their general equation is \(\frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1\). To successfully identify a given equation as representing an ellipsoid, the task involves transforming or simplifying it into this recognizable standard form.
- Ellipsoid: All squared terms, with positive coefficients, and a constant on the other side of the equation. The denominators \(a^2, b^2, c^2\) determine the length of the semi-axes.
- Identify ellipsoid properties by comparing the simplified equation to key details within the general form.
- The symmetrical nature and bounded surface features stand out as unique traits of ellipsoids.
Equation Simplification
Simplifying equations to match a standard form is crucial for identifying 3D surfaces. In this exercise, we start with a more complex shape equation, \(9x^2 + 4y^2 + 2z^2 = 36\), and we simplify it to an ellipsoid form.
Here's how the simplification process works:
Here's how the simplification process works:
- Divide every term in the equation by the constant (36 here) to start reshaping it.
- This yields \(\frac{x^2}{4} + \frac{y^2}{9} + \frac{z^2}{18} = 1\), which is now comparable to our target form \(\frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1\).
- The terms under the fractions reflect the squared terms from an ellipsoid; thus, simplifying places the equation into a recognizable pattern.
Other exercises in this chapter
Problem 12
In Exercises \(9-14,\) sketch the coordinate axes and then include the vectors \(\mathbf{u}, \mathbf{v},\) and \(\mathbf{u} \times \mathbf{v}\) as vectors start
View solution Problem 12
Find parametric equations for the lines in Exercises 1-12. The \(z\) -axis
View solution Problem 12
Find the component form of the vector. The sum of \(\overrightarrow{A B}\) and \(\overrightarrow{C D},\) where \(A=(1,-1), B=(2,0),\) \(C=(-1,3),\) and \(D=(-2,
View solution Problem 12
In Exercises \(1-16,\) give a geometric description of the set of points in space whose coordinates satisfy the given pairs of equations. $$x^{2}+(y-1)^{2}+z^{2
View solution