Problem 12
Question
If \(n\) is a positive integer greater than \(1,\) is \((n-1) ! \cdot n\) always equal to \(n ! ?\)
Step-by-Step Solution
Verified Answer
Yes, \((n-1)! \cdot n\) is always equal to \(n!\) for \(n > 1\).
1Step 1: Understand Factorial Notation
A factorial of a number, denoted by \(n!\), is the product of all positive integers less than or equal to \(n\). For example, \(5! = 5 \times 4 \times 3 \times 2 \times 1\).
2Step 2: Express Given Expression
We need to consider two expressions: \((n-1)! \cdot n\) and \(n!\). Write the first expression: \((n-1)!\) denotes the factorial of \(n-1\). So, \((n-1)! = (n-1) \times (n-2) \times \cdots \times 1\). Multiply this by \(n\) to get \((n-1)! \cdot n\).
3Step 3: Compare with Factorial Definition
According to the definition of factorial, \(n! = n \times (n-1) \times (n-2) \times \cdots \times 1\). This is exactly the same as \((n-1)! \cdot n\).
4Step 4: Conclude Equality
Since \((n-1)! \cdot n\) expands to the same multiplication as \(n!\), we conclude that \((n-1)! \cdot n = n!\) for any positive integer \(n > 1\).
Key Concepts
Understanding IntegerExploring the ProductFactorial Notation DemystifiedPositive Integer Insights
Understanding Integer
An integer is a whole number that can be positive, negative, or zero. In mathematics, when we talk about integers, we refer to numbers like \(-3, 0, 4\). These are numbers without fractions or decimals.
However, when solving factorial problems, we mainly focus on positive integers.
Here's why integers are essential in factorials:
However, when solving factorial problems, we mainly focus on positive integers.
Here's why integers are essential in factorials:
- They help us understand the count of terms in a multiplication.
- Integers can be seen on the number line.
Exploring the Product
A product in mathematics is the result of multiplying numbers together.
For example, the product of \(3\) and \(4\) is \(12\) because \(3 \times 4 = 12\).
Products are crucial in understanding factorials:
This operation shows how products form the core of factorial calculations.
For example, the product of \(3\) and \(4\) is \(12\) because \(3 \times 4 = 12\).
Products are crucial in understanding factorials:
- Factorials involve a series of products of consecutive integers.
- The operation builds from one integer to the next.
This operation shows how products form the core of factorial calculations.
Factorial Notation Demystified
Factorial notation, represented by an exclamation mark (!), is a way to convey a sequence of multiplied integers.
For example, \(n!\) means we multiply all positive integers from \(n\) down to \(1\).
Here's what makes factorial notation special:
In the equation we solved, \((n-1)! \cdot n = n!\), the notation helps clearly show the relationship between values.
For example, \(n!\) means we multiply all positive integers from \(n\) down to \(1\).
Here's what makes factorial notation special:
- It simplifies expressing multiple multiplications.
- Commonly used in permutations and combinations.
In the equation we solved, \((n-1)! \cdot n = n!\), the notation helps clearly show the relationship between values.
Positive Integer Insights
Positive integers are the numbers we count with, starting at \(1\).
They are essential in defining factorials, as factorials only apply to non-negative numbers.
Here's why positive integers matter in our context:
This ensures that the factorial operation is valid and meaningful.
They are essential in defining factorials, as factorials only apply to non-negative numbers.
Here's why positive integers matter in our context:
- They ensure the operations in factorials make sense.
- The factorial of a positive integer \(n\) includes all numbers up to \(n\).
This ensures that the factorial operation is valid and meaningful.
Other exercises in this chapter
Problem 12
If the probability of an event is 0.857 what is the probability that the event will not occur?
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Use mathematical induction to prove each statement. Assume that \(n\) is a positive integer. $$5 \cdot 6+5 \cdot 6^{2}+5 \cdot 6^{3}+\cdots+5 \cdot 6^{n}=6\left
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Evaluate the following. In Exercises 17 and \(18,\) express the answer in terms of \(n .\) Do not use a calculator. $$\left(\begin{array}{l}9 \\\7\end{array}\ri
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Find \(a_{8}\) and \(a_{n}\) for each arithmetic sequence. $$a_{1}=5, d=2$$
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