Problem 12
Question
If \(D \subset \mathbb{C}\) is a bounded domain, and \(f: \bar{D} \rightarrow \mathbb{C}\) is a continuous function on the closure of \(D\) which is analytic on \(D\), then \(|f|\) takes its maximum on the boundary of \(D\) Using the example of the strip $$ S=\left\\{z \in \mathbb{C} ; \quad|\operatorname{Im} z|<\frac{\pi}{2}\right\\} $$ and the function \(f(z)=\exp (\exp (z))\) show the necessity of the boundedness of \(D\)
Step-by-Step Solution
Verified Answer
The example shows that boundedness is necessary for the Maximum Modulus Principle as \(|f(z)|\) can become unbounded in unbounded domains like \(S\).
1Step 1: Understand the Maximum Modulus Principle
The Maximum Modulus Principle states that if a function is analytic and non-constant on a bounded domain, the maximum modulus of the function occurs on the boundary of that domain. This exercise aims to show that if the domain is unbounded, like the strip \( S \), then the function \( |f| \) can achieve its maximum inside the domain.
2Step 2: Analyze the Given Strip and Function
The strip \( S = \left\{ z \in \mathbb{C} ; \quad |\operatorname{Im} z| < \frac{\pi}{2} \right\} \) is unbounded in the real direction. The function \( f(z) = \exp (\exp (z)) \) is analytic across the complex plane including \( \bar{S} \). The goal is to show that there could be scenarios where \( |f| \) doesn't achieve its maximum on the boundary of \( D \) due to unboundedness.
3Step 3: Evaluate the Behavior of \( f \) on \( S \)
For \( f(z) = \exp(\exp(z)) \), consider the property of the exponential function that it maps large real parts of \( z \) to very large values. Since \( S \) is unbounded in the real part as \( \text{Re}(z) \rightarrow \infty \), \( \exp(z) \rightarrow \infty \) and hence \( f(z) \rightarrow \infty \). Therefore, \(|f(z)|\) can increase indefinitely within \( S \).
4Step 4: Show the Necessity of Boundedness
Since \( \text{Re}(z) \) is unbounded in \( S \), \( |f(z)| \) can become arbitrarily large as discussed in Step 3. This violates the condition that the maximum modulus should occur on the boundary of a bounded domain. Hence, this example shows that boundedness of \( D \) is necessary for the Maximum Modulus Principle to hold.
Key Concepts
Bounded DomainAnalytic FunctionsUnbounded Domain
Bounded Domain
In complex analysis, a bounded domain is an important concept when discussing the behavior of analytic functions. A domain, in this context, refers to an open and connected subset of the complex plane, denoted as \( D \). It is "bounded" if there exists a real number \( M \) such that the distance from the origin to any point in \( D \) is less than \( M \).
- A typical way to visualize this is thinking of a domain that can fit within a large circle in the complex plane.
- The boundaries of such a domain play a key role when applying the Maximum Modulus Principle.
Analytic Functions
Analytic functions are central to complex analysis. These are functions that are differentiable at every point in a domain in the complex plane. Even more interestingly, they are infinitely differentiable and can be represented as power series.
- Analytic functions have powerful properties, like the Maximum Modulus Principle.
- For a function to be analytic everywhere in a domain, it must satisfy Cauchy-Riemann equations and must be continuous.
Unbounded Domain
An unbounded domain, unlike a bounded one, extends infinitely in at least one direction. This means there is no real number \( M \) limiting the distance of points in the domain from the origin.
- An example of an unbounded domain is the strip \( S = \{ z \in \mathbb{C} \, | \, |\operatorname{Im} z| < \frac{\pi}{2} \} \), which extends infinitely in the real direction.
- Such domains do not have a fixed "boundary" where the function achieves its maximum, as the limit at infinity might surpass any boundary.
Other exercises in this chapter
Problem 11
Show: (a) \(\quad \int_{-\infty}^{\infty} \frac{1}{x^{4}+1} d x=\frac{\pi}{\sqrt{2}}\), (b) \(\int_{0}^{\infty} \frac{x}{x^{4}+1} d x=\frac{\pi}{4}\), (c) \(\in
View solution Problem 12
Assume that the power series \(P(z)=\sum_{n=0}^{\infty} c_{n} z^{n}\) has convergence radius \(r\) \(0
View solution Problem 12
Show: (a) $$ \int_{-\infty}^{\infty} \frac{x^{2}}{\left(x^{2}+a^{2}\right)^{2}} d x=\frac{\pi}{2 a}, \quad(a>0) $$ (b) $$ \int_{-\infty}^{\infty} \frac{d x}{\le
View solution Problem 13
Determine an entire function \(f: \mathbb{C} \rightarrow \mathbb{C}\) with $$ z^{2} f^{\prime \prime}(z)+z f^{\prime}(z)+z^{2} f(z)=0 \quad \text { for all } z
View solution