Problem 12
Question
For the following exercises, simplify each expression. $$ \sqrt{\frac{27}{64}} $$
Step-by-Step Solution
Verified Answer
\( \frac{3\sqrt{3}}{8} \)
1Step 1: Simplify the square root
Start by simplifying the expression under the square root. Notice that the expression is a fraction, and the square root can be taken for both the numerator and the denominator individually: \[ \sqrt{\frac{27}{64}} = \frac{\sqrt{27}}{\sqrt{64}}. \]
2Step 2: Simplify the denominator
Calculate the square root of the denominator, 64. Since 64 is a perfect square, we find \[ \sqrt{64} = 8. \]
3Step 3: Simplify the numerator
Now simplify the square root of the numerator, 27, by factoring it into a perfect square: \[ 27 = 9 \times 3 = 3^2 \times 3. \] Thus, \[ \sqrt{27} = \sqrt{3^2 \times 3} = 3\sqrt{3}. \]
4Step 4: Combine simplified results
Combine the simplified results from steps 2 and 3 to get the simplified expression: \[ \frac{\sqrt{27}}{\sqrt{64}} = \frac{3\sqrt{3}}{8}. \]
Key Concepts
Square RootsFactoring ExpressionsRational Expressions
Square Roots
Square roots are a fundamental concept in mathematics. They allow us to find a number which, when multiplied by itself, gives the original number. When dealing with square roots of fractions, as in the expression \( \sqrt{\frac{27}{64}} \), we can simplify by considering the square root of the numerator and the denominator separately. Here are a few key points to remember:
- For any positive number \( x \), the square root is denoted as \( \sqrt{x} \).
- The process involves looking for perfect squares (numbers like 1, 4, 9, 16, etc.) within the number in the square root.
- If dealing with fractions, simplify using \( \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} \).
Factoring Expressions
Factoring expressions can make simplifying radicals much more straightforward. In the case of the expression \( \sqrt{27} \), we need to break it down into factors to identify if any part is a perfect square. Here's how you can do it:
- Identify components of the number that can be rewritten as squares. For instance, \( 27 = 9 \times 3 \). Here, 9 is a perfect square, \( 9 = 3^2 \).
- Expressing it in terms of powers, \( 27 = 3^2 \times 3 \), clarifies which part can exit the square root.
- Remember that \( \sqrt{3^2 \times 3} = 3\sqrt{3} \), because the square root of \( 3^2 \) is 3.
Rational Expressions
Rational expressions simplify the process of working with fractions, especially when they involve radicals. To manage expressions like \( \frac{\sqrt{27}}{\sqrt{64}} \), consider these steps:
- First, ensure the fraction is in its simplest form by simplifying the square roots involved separately.
- Identify the perfect square in the denominator; since \( 64 \) is \( 8^2 \), \( \sqrt{64} = 8 \).
- With the numerator simplified to \( 3\sqrt{3} \), the expression is \( \frac{3\sqrt{3}}{8} \).
- This clean simplification means your radical is now wrapped up in a neat rational expression for clarity.
Other exercises in this chapter
Problem 12
For the following exercises, simplify the rational expressions. $$ \frac{3 c^{2}+25 c-18}{3 c^{2}-23 c+14} $$
View solution Problem 12
Simplify the rational expressions. $$ \frac{3 c^{2}+25 c-18}{3 c^{2}-23 c+14} $$
View solution Problem 12
For the following exercises, find the sum or difference. $$ \left(4 z^{3}+8 z^{2}-z\right)+\left(-2 z^{2}+z+6\right) $$
View solution Problem 12
Simplify each expression. $$\sqrt{\frac{27}{64}}$$
View solution