Problem 12
Question
For Problems \(1-18\), find the multiplicative inverse (if one exists) of each matrix. $$ \left[\begin{array}{ll} -2 & 0 \\ -3 & 5 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The multiplicative inverse is \( \begin{bmatrix} -\frac{1}{2} & 0 \\ -\frac{3}{10} & \frac{1}{5} \end{bmatrix} \).
1Step 1: Identify the matrix elements
The given matrix is \( \begin{bmatrix} -2 & 0 \ -3 & 5 \end{bmatrix} \). Let's denote the elements as \( a = -2 \), \( b = 0 \), \( c = -3 \), and \( d = 5 \). The matrix is a 2x2 matrix.
2Step 2: Calculate the determinant
The formula for the determinant of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is \( ad - bc \). Substituting the values, we get the determinant: \(-2 \cdot 5 - 0 \cdot -3 = -10 - 0 = -10\).
3Step 3: Check if the determinant is zero
The determinant is \(-10\). Since this is not zero, the matrix does have an inverse.
4Step 4: Apply the formula for the inverse of a 2x2 matrix
The formula for the inverse of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is \( \frac{1}{ad - bc} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \). Substitute in the values: \( \frac{1}{-10} \begin{bmatrix} 5 & 0 \ 3 & -2 \end{bmatrix} \).
5Step 5: Simplify the result
Multiply each element in the matrix by \( \frac{1}{-10} \): \( \begin{bmatrix} -\frac{1}{2} & 0 \ -\frac{3}{10} & \frac{1}{5} \end{bmatrix} \).
6Step 6: Verify the inverse (Optional)
To confirm, multiply the original matrix by the calculated inverse and check if it equals the identity matrix. \( \begin{bmatrix} -2 & 0 \ -3 & 5 \end{bmatrix} \times \begin{bmatrix} -\frac{1}{2} & 0 \ -\frac{3}{10} & \frac{1}{5} \end{bmatrix} = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \), which confirms our inverse is correct.
Key Concepts
Determinant2x2 MatrixIdentity MatrixMatrices Multiplication
Determinant
The determinant is a key concept in linear algebra that helps us understand many properties of matrices. For a 2x2 matrix, the determinant can determine if a matrix has an inverse. If the determinant is zero, the matrix does not have an inverse. This is because the inverse relies on dividing by the determinant, and division by zero is undefined.
For a 2x2 matrix represented as \[ \begin{bmatrix} a & b \ c & d \end{bmatrix} \]the determinant is calculated using the formula \( ad - bc \).
For a 2x2 matrix represented as \[ \begin{bmatrix} a & b \ c & d \end{bmatrix} \]the determinant is calculated using the formula \( ad - bc \).
- In our exercise, with matrix \[ \begin{bmatrix} -2 & 0 \ -3 & 5 \end{bmatrix} \],the determinant is \( -2 \times 5 - 0 \times (-3) = -10 \).
- This non-zero result confirms an inverse does exist.
2x2 Matrix
The 2x2 matrix is one of the simplest forms of matrices and is frequently used in linear algebra due to its simplicity and relevance. It consists of two rows and two columns, making it compact yet powerful enough for various calculations and transformations.
A typical 2x2 matrix is written as:\[ \begin{bmatrix} a & b \ c & d \end{bmatrix} \]where:
A typical 2x2 matrix is written as:\[ \begin{bmatrix} a & b \ c & d \end{bmatrix} \]where:
- \(a\), \(b\), \(c\), and \(d\) are elements of the matrix.
- These elements can be any real numbers or even complex numbers, depending on the context.
Identity Matrix
In matrix algebra, the identity matrix plays a critical role similar to the number 1 in arithmetic. When a matrix is multiplied by the identity matrix, it remains unchanged. This feature is essential when verifying whether a matrix has been correctly inverted.
For a 2x2 identity matrix:\[ \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \]
For a 2x2 identity matrix:\[ \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \]
- If \(A\) is any 2x2 matrix, then \(A \times I = I \times A = A\).
- Using the identity matrix, the correctness of an inverse is confirmed. If multiplying the original matrix and its inverse yields the identity matrix, the inversion is correct.
Matrices Multiplication
Matrix multiplication is a fundamental operation in linear algebra and is crucial when dealing with matrices and their transformations. Multiplying matrices involves combining rows from the first matrix with columns of the second matrix. The process is not commutative, meaning the order of multiplication matters.
For any two 2x2 matrices \(A\) and \(B\):
For any two 2x2 matrices \(A\) and \(B\):
- The element in the first row first column of the result comes from multiplying elements of the first row of \(A\) by those in the first column of \(B\) and summing the results.
- Similarly, the rest of the resulting matrix can be filled by following this pattern for the respective rows and columns.
Other exercises in this chapter
Problem 11
For Problems \(1-12\), compute the indicated matrix by using the following matrices: \(\begin{array}{ll} A=\left[\begin{array}{rr} 1 & -2 \\ 3 & 4 \end{array}\r
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For Problems \(9-20\), find \(A B\) and \(B A\), whenever they exist. $$ A=\left[\begin{array}{rrr} 3 & -1 & -4 \\ -5 & 2 & 2 \end{array}\right], \quad B=\left[
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For Problems \(1-12\), compute the indicated matrix by using the following matrices: \(\begin{array}{ll} A=\left[\begin{array}{rr} 1 & -2 \\ 3 & 4 \end{array}\r
View solution Problem 12
For Problems \(1-24\), indicate the solution set for each system of inequalities by graphing the system and shading the appropriate region. $$ \left(\begin{arra
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