Problem 12
Question
Find the limit of the following vector-valued functions at the indicated value of \(t\). $$ \lim _{t \rightarrow \pi / 6}\left\langle\cos ^{2} t, \sin ^{2} t, 1\right\rangle $$
Step-by-Step Solution
Verified Answer
The limit of the vector-valued function is \( \langle \frac{3}{4}, \frac{1}{4}, 1 \rangle \).
1Step 1: Identify the Limit Components
The problem requires us to take the limit of the vector-valued function as the variable \( t \) approaches \( \frac{\pi}{6} \). The components of the vector are \( \cos^2 t \), \( \sin^2 t \), and \( 1 \). We will evaluate each component separately.
2Step 2: Calculate Limit of First Component
The first component of the vector is \( \cos^2 t \). Substitute \( t = \frac{\pi}{6} \) into \( \cos^2 t \):\[ \cos \left(\frac{\pi}{6}\right) = \frac{\sqrt{3}}{2} \rightarrow \cos^2 \left(\frac{\pi}{6}\right) = \left( \frac{\sqrt{3}}{2} \right)^2 = \frac{3}{4} \].
3Step 3: Calculate Limit of Second Component
The second component is \( \sin^2 t \). Substitute \( t = \frac{\pi}{6} \) into \( \sin^2 t \):\[ \sin \left(\frac{\pi}{6}\right) = \frac{1}{2} \rightarrow \sin^2 \left(\frac{\pi}{6}\right) = \left( \frac{1}{2} \right)^2 = \frac{1}{4} \].
4Step 4: Evaluate the Constant Component
The third component is the constant \( 1 \). The limit of a constant is the constant itself, so this remains \( 1 \).
5Step 5: Combine Limits into a Vector
Now, we combine the limits of each component vector to form the final limit vector:\[ \langle \frac{3}{4}, \frac{1}{4}, 1 \rangle \].
Key Concepts
LimitsTrigonometric functionsVector components
Limits
In calculus, the concept of limits is fundamental for understanding how functions behave as they close in on a particular point. When dealing with vector-valued functions,these limits involve breaking down the vector into its individual components and finding the limit for each piece separately.
This procedure becomes especially important when vectors include trigonometric functions, constants, and more complicated expressions.
In our exercise, we have a vector \[ \langle \cos^2 t, \sin^2 t, 1 \rangle \] and are asked to find its limit as \[ t \to \frac{\pi}{6} \] To do this, let's:
Understanding limits is not just about numbers or points. It’s also about comprehending the nature and direction of vectors and functions.
This procedure becomes especially important when vectors include trigonometric functions, constants, and more complicated expressions.
In our exercise, we have a vector \[ \langle \cos^2 t, \sin^2 t, 1 \rangle \] and are asked to find its limit as \[ t \to \frac{\pi}{6} \] To do this, let's:
- Substitute the target value into each component one at a time.
- Calculate the result for each component limit independently.
- Reassemble these results into a new vector to find the overall limit value.
Understanding limits is not just about numbers or points. It’s also about comprehending the nature and direction of vectors and functions.
Trigonometric functions
Trigonometric functions like sine and cosine are crucial when working with vector-valued functions.They describe angular relationships and periodic phenomena in mathematics. In problems involving limits, inserting a value of the variable often transforms them into specific numerical results.
Consider the components in our exercise:
Consider the components in our exercise:
- \( \cos^2 t \) involves taking the cosine of an angle squared.
- \( \sin^2 t \) is the sine of an angle squared.
Vector components
Vector components are individual segments that make up a vector in mathematics. Each component represents a different aspect of the vector, behaving independently but contributing to the overall vector's outcome.
In vector-valued functions, evaluating limits or any operation means treating each part as a separate entity before putting them back together.
Take our problem, where:
In vector-valued functions, evaluating limits or any operation means treating each part as a separate entity before putting them back together.
Take our problem, where:
- The vector \( \langle \cos^2 t, \sin^2 t, 1 \rangle \) is split into its three components.
- Both trigonometric calculations for cosine and sine are performed individually.
- The constant \(1\) stays unchanged since its limit is itself.
Other exercises in this chapter
Problem 12
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