Problem 12
Question
Find the derivative of each function. $$ h(x)=\frac{4}{x^{3}} $$
Step-by-Step Solution
Verified Answer
The derivative of \( h(x) = \frac{4}{x^3} \) is \(-\frac{12}{x^4}\).
1Step 1: Transform Function
To find the derivative of the function \( h(x) = \frac{4}{x^3} \), we first rewrite it in a more differentiable form. We can express \( \frac{4}{x^3} \) as \( 4x^{-3} \). This step uses the property that \( \frac{1}{x^n} = x^{-n} \).
2Step 2: Differentiate Using Power Rule
Now that we have rewritten the function, \( h(x) = 4x^{-3} \), we can differentiate it using the power rule. The power rule states that \( \frac{d}{dx} x^n = nx^{n-1} \). Applying the power rule, we differentiate: \( \frac{d}{dx} [4x^{-3}] = 4 \cdot (-3) x^{-3-1} = -12x^{-4} \).
3Step 3: Simplify Expression
The expression \(-12x^{-4}\) can be rewritten in a more standard form as \(-\frac{12}{x^4}\). The negative exponent indicates the reciprocal of the power of \(x\). This gives us the derivative in a more conventional form.
Key Concepts
Power RuleNegative ExponentsDifferentiation Steps
Power Rule
The power rule is a fundamental concept in calculus that simplifies the process of finding derivatives for expressions involving powers of a variable. It is particularly useful because it provides a quick method for differentiating polynomial terms. The rule states that if you have a function of the form \( f(x) = x^n \), the derivative is given by \( f'(x) = nx^{n-1} \).
For example, when differentiating \( 4x^{-3} \), we use the power rule by multiplying the exponent, \(-3\), by the coefficient, \(4\), resulting in \(-12\). We then decrease the power of \(x\) by one, which changes it from \(-3\) to \(-4\).
Using the power rule effectively allows us to transform complex algebraic expressions into simpler derivatives, making calculus more approachable. It's a vital technique when dealing with polynomial expressions in calculus exercises.
For example, when differentiating \( 4x^{-3} \), we use the power rule by multiplying the exponent, \(-3\), by the coefficient, \(4\), resulting in \(-12\). We then decrease the power of \(x\) by one, which changes it from \(-3\) to \(-4\).
Using the power rule effectively allows us to transform complex algebraic expressions into simpler derivatives, making calculus more approachable. It's a vital technique when dealing with polynomial expressions in calculus exercises.
Negative Exponents
Negative exponents are a mathematical notation that shows a reciprocal relationship. When an expression involves a negative exponent, it implies the reciprocal of that power.
It is expressed as \( x^{-n} = \frac{1}{x^n} \). This transformation is critical for simplifying expressions and performing derivative operations. It converts division into multiplication by a power of the base number \(x\).
In our function \( h(x) = \frac{4}{x^3} \), by rewriting it as \( 4x^{-3} \), we convert the divisor into a multiplication form, simplifying the differentiation process. This transformation harnesses negative exponents for easier manipulation and can be very useful in calculus and algebra.
It is expressed as \( x^{-n} = \frac{1}{x^n} \). This transformation is critical for simplifying expressions and performing derivative operations. It converts division into multiplication by a power of the base number \(x\).
In our function \( h(x) = \frac{4}{x^3} \), by rewriting it as \( 4x^{-3} \), we convert the divisor into a multiplication form, simplifying the differentiation process. This transformation harnesses negative exponents for easier manipulation and can be very useful in calculus and algebra.
Differentiation Steps
Differentiation involves a systematic process to find the derivative of a function.
- First, reformulate the function to a differentiable form, if necessary. For instance, rewrite any fractions with negative exponents.
- Next, apply the appropriate differentiation rule, such as the power rule, to find the derivative of each term in the expression.
- Finally, simplify the derivative expression. For example, rewrite terms with negative exponents into their fractional form if needed.
Other exercises in this chapter
Problem 12
For each function, find: a. \(f^{\prime \prime}(x)\) and b. \(f^{\prime \prime}(3)\). $$ f(x)=\frac{1}{12 x^{3}} $$
View solution Problem 12
a. Show that the definition of the derivative applied to the function \(f(x)=\sqrt[3]{x}\) at \(x=0\) gives \(f^{\prime}(0)=\lim _{h \rightarrow 0} \frac{\sqrt[
View solution Problem 12
Find the derivative of each function by using the Product Rule. Simplify your answers. $$ f(x)=\left(x^{3}-1\right)\left(x^{3}+1\right) $$
View solution Problem 13
Use the Generalized Power Rule to find the derivative of each function. $$ g(x)=\left(2 x^{2}-7 x+3\right)^{4} $$
View solution