Problem 12
Question
Find the center-radius form for each circle satisfying the given conditions. Center \((0,0) ;\) radius 5
Step-by-Step Solution
Verified Answer
The equation of the circle is \(x^2 + y^2 = 25\).
1Step 1: Recall the Center-Radius Form of a Circle
The center-radius form of a circle is given by the equation \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) represents the center of the circle and \(r\) is the radius.
2Step 2: Identify the Values for Center and Radius
From the problem, the center of the circle is given as \((0, 0)\), and the radius is given as \(5\).
3Step 3: Substitute the Center and Radius into the Equation
Substitute \(h = 0\), \(k = 0\), and \(r = 5\) into the center-radius form equation. This gives \((x-0)^2 + (y-0)^2 = 5^2\).
4Step 4: Simplify the Equation
Simplify the equation by eliminating zeroes and calculating the square of the radius: \(x^2 + y^2 = 25\).
Key Concepts
Center-Radius FormCircle GeometryAlgebraic Equations
Center-Radius Form
Understanding the center-radius form of a circle is essential when working with circle equations. This form is a special equation that provides the relationship between the coordinates of any point on the circle and the fixed center point. It is expressed as:\[(x-h)^2 + (y-k)^2 = r^2\]In this equation:
- \((h, k)\) represents the circle’s center coordinates.
- \(r\) is the circle's radius.
- The variables \(x\) and \(y\) are the coordinates of a point located on the circle itself.
Circle Geometry
Circle geometry is a captivating topic in mathematics, focusing on the properties and measurements of circles. At the heart of circle geometry is understanding how all the points are equidistant from a central point.Key aspects of circle geometry include:
- **Radius:** This is the distance from the center of the circle to any point on its boundary. All radii in a circle are equal.
- **Diameter:** Equal to twice the radius, the diameter is the longest distance across the circle.
- **Circumference:** This is the total distance around the circle, calculated using the formula \(C=2\pi r\), where \(r\) is the radius.
- **Area:** Representing the space contained within a circle, this is calculated as \(A=\pi r^2\).
Algebraic Equations
Algebraic equations form the backbone of expressing mathematical relationships, including those in circle geometry. In the case of the center-radius form of a circle, the equation is algebraic because it consists of variables that capture the relationship between the circle's center, its radius, and any point on the circle.This form is algebraic because:
- It involves two variables, \(x\) and \(y\), representing coordinates in a plane.
- By squaring the differences \((x-h)\) and \((y-k)\), it ensures all points equidistant from the center \((h, k)\) fall on the circle perimeter.
- The equation is quadratic, a type of polynomial equation, which frequently appears in algebra.
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